Decimal to roman python Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Roman Numeral to Decimal ConversionConverting Roman numerals to decimalRoman numeral converter in RubyRoman numerals to decimalRoman numeral to decimal converterCurrency converter in Python 2.7“Merchants Guide to Galaxy” challengeGreed Dice Scoring Game expanded - Python KoansArea and volume calculatorNumber of possible numbers in roman number string

Why not use the yoke to control yaw, as well as pitch and roll?

Marquee sign letters

Can a Wizard take the Magic Initiate feat and select spells from the Wizard list?

Why do C and C++ allow the expression (int) + 4*5?

Protagonist's race is hidden - should I reveal it?

Compiling and throwing simple dynamic exceptions at runtime for JVM

Is it OK if I do not take the receipt in Germany?

Why does my GNOME settings mention "Moto C Plus"?

Why did Bronn offer to be Tyrion Lannister's champion in trial by combat?

Raising a bilingual kid. When should we introduce the majority language?

How can I introduce the names of fantasy creatures to the reader?

What is the difference between 准时 and 按时?

Why these surprising proportionalities of integrals involving odd zeta values?

Is "ein Herz wie das meine" an antiquated or colloquial use of the possesive pronoun?

Why aren't road bike wheels tiny?

Recursive calls to a function - why is the address of the parameter passed to it lowering with each call?

How to leave only the following strings?

Help Recreating a Table

Is my guitar’s action too high?

What's the difference between using dependency injection with a container and using a service locator?

Putting Ant-Man on house arrest

Can this water damage be explained by lack of gutters and grading issues?

Unix AIX passing variable and arguments to expect and spawn

What could prevent concentrated local exploration?



Decimal to roman python



Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Roman Numeral to Decimal ConversionConverting Roman numerals to decimalRoman numeral converter in RubyRoman numerals to decimalRoman numeral to decimal converterCurrency converter in Python 2.7“Merchants Guide to Galaxy” challengeGreed Dice Scoring Game expanded - Python KoansArea and volume calculatorNumber of possible numbers in roman number string



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








6












$begingroup$


I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.



roman_dict = 1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
500: 'D', 900: 'CM', 1000: 'M'

divide_list = [1000, 100, 10, 1]

def not_in_dict(fixed_decimal, divide_num):
sub_count = 0
sub_roman_multi = roman_dict[divide_num]
temp_decimal = fixed_decimal
while temp_decimal not in roman_dict:
temp_decimal -= divide_num
sub_count += 1
return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)

def decimal_to_roman(decimal):
original_decimal = decimal
roman = ""
for divide_num in divide_list:
if decimal >= divide_num:
reminder = decimal//divide_num
if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
roman += roman_dict[(reminder*divide_num)]
decimal -= reminder*divide_num
else:
roman += not_in_dict(reminder*divide_num, divide_num)
decimal -= (reminder*divide_num)
return str(original_decimal)+' = '+roman









share|improve this question











$endgroup$


















    6












    $begingroup$


    I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.



    roman_dict = 1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
    500: 'D', 900: 'CM', 1000: 'M'

    divide_list = [1000, 100, 10, 1]

    def not_in_dict(fixed_decimal, divide_num):
    sub_count = 0
    sub_roman_multi = roman_dict[divide_num]
    temp_decimal = fixed_decimal
    while temp_decimal not in roman_dict:
    temp_decimal -= divide_num
    sub_count += 1
    return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)

    def decimal_to_roman(decimal):
    original_decimal = decimal
    roman = ""
    for divide_num in divide_list:
    if decimal >= divide_num:
    reminder = decimal//divide_num
    if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
    roman += roman_dict[(reminder*divide_num)]
    decimal -= reminder*divide_num
    else:
    roman += not_in_dict(reminder*divide_num, divide_num)
    decimal -= (reminder*divide_num)
    return str(original_decimal)+' = '+roman









    share|improve this question











    $endgroup$














      6












      6








      6





      $begingroup$


      I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.



      roman_dict = 1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
      500: 'D', 900: 'CM', 1000: 'M'

      divide_list = [1000, 100, 10, 1]

      def not_in_dict(fixed_decimal, divide_num):
      sub_count = 0
      sub_roman_multi = roman_dict[divide_num]
      temp_decimal = fixed_decimal
      while temp_decimal not in roman_dict:
      temp_decimal -= divide_num
      sub_count += 1
      return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)

      def decimal_to_roman(decimal):
      original_decimal = decimal
      roman = ""
      for divide_num in divide_list:
      if decimal >= divide_num:
      reminder = decimal//divide_num
      if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
      roman += roman_dict[(reminder*divide_num)]
      decimal -= reminder*divide_num
      else:
      roman += not_in_dict(reminder*divide_num, divide_num)
      decimal -= (reminder*divide_num)
      return str(original_decimal)+' = '+roman









      share|improve this question











      $endgroup$




      I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.



      roman_dict = 1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
      500: 'D', 900: 'CM', 1000: 'M'

      divide_list = [1000, 100, 10, 1]

      def not_in_dict(fixed_decimal, divide_num):
      sub_count = 0
      sub_roman_multi = roman_dict[divide_num]
      temp_decimal = fixed_decimal
      while temp_decimal not in roman_dict:
      temp_decimal -= divide_num
      sub_count += 1
      return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)

      def decimal_to_roman(decimal):
      original_decimal = decimal
      roman = ""
      for divide_num in divide_list:
      if decimal >= divide_num:
      reminder = decimal//divide_num
      if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
      roman += roman_dict[(reminder*divide_num)]
      decimal -= reminder*divide_num
      else:
      roman += not_in_dict(reminder*divide_num, divide_num)
      decimal -= (reminder*divide_num)
      return str(original_decimal)+' = '+roman






      python roman-numerals






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Apr 4 at 11:53









      Graipher

      27.7k54499




      27.7k54499










      asked Apr 4 at 10:23









      OfeksOfeks

      333




      333




















          1 Answer
          1






          active

          oldest

          votes


















          10












          $begingroup$

          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)





          share|improve this answer











          $endgroup$












          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            Apr 4 at 13:36







          • 1




            $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            Apr 4 at 14:01











          Your Answer






          StackExchange.ifUsing("editor", function ()
          StackExchange.using("externalEditor", function ()
          StackExchange.using("snippets", function ()
          StackExchange.snippets.init();
          );
          );
          , "code-snippets");

          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "196"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: false,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: null,
          bindNavPrevention: true,
          postfix: "",
          imageUploader:
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          ,
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );













          draft saved

          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f216852%2fdecimal-to-roman-python%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          10












          $begingroup$

          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)





          share|improve this answer











          $endgroup$












          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            Apr 4 at 13:36







          • 1




            $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            Apr 4 at 14:01















          10












          $begingroup$

          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)





          share|improve this answer











          $endgroup$












          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            Apr 4 at 13:36







          • 1




            $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            Apr 4 at 14:01













          10












          10








          10





          $begingroup$

          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)





          share|improve this answer











          $endgroup$



          If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.



          Instead of manually adding strings (something you should basically never do in in Python), use str.join.



          ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
          (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
          (5, 'V'), (4, 'IV'), (1, 'I')]

          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          while x >= value:
          x -= value
          out.append(literal)
          return "".join(out)


          Instead of the while loop you can also use integer division like you did:



          def decimal_to_roman(x):
          out = []
          for value, literal in ROMAN_LITERALS:
          n = x // value # will be 0 if value is too large
          out.extend([literal] * n) # will not do anything if n == 0
          x -= n * value # will also not do anything if n == 0
          return "".join(out)






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Apr 4 at 14:44

























          answered Apr 4 at 12:01









          GraipherGraipher

          27.7k54499




          27.7k54499











          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            Apr 4 at 13:36







          • 1




            $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            Apr 4 at 14:01
















          • $begingroup$
            wow. looks so easy now, thank you. that's great.
            $endgroup$
            – Ofeks
            Apr 4 at 13:36







          • 1




            $begingroup$
            @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
            $endgroup$
            – Graipher
            Apr 4 at 14:01















          $begingroup$
          wow. looks so easy now, thank you. that's great.
          $endgroup$
          – Ofeks
          Apr 4 at 13:36





          $begingroup$
          wow. looks so easy now, thank you. that's great.
          $endgroup$
          – Ofeks
          Apr 4 at 13:36





          1




          1




          $begingroup$
          @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
          $endgroup$
          – Graipher
          Apr 4 at 14:01




          $begingroup$
          @Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
          $endgroup$
          – Graipher
          Apr 4 at 14:01

















          draft saved

          draft discarded
















































          Thanks for contributing an answer to Code Review Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid


          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.

          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f216852%2fdecimal-to-roman-python%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Adding axes to figuresAdding axes labels to LaTeX figuresLaTeX equivalent of ConTeXt buffersRotate a node but not its content: the case of the ellipse decorationHow to define the default vertical distance between nodes?TikZ scaling graphic and adjust node position and keep font sizeNumerical conditional within tikz keys?adding axes to shapesAlign axes across subfiguresAdding figures with a certain orderLine up nested tikz enviroments or how to get rid of themAdding axes labels to LaTeX figures

          Tähtien Talli Jäsenet | Lähteet | NavigointivalikkoSuomen Hippos – Tähtien Talli

          Do these cracks on my tires look bad? The Next CEO of Stack OverflowDry rot tire should I replace?Having to replace tiresFishtailed so easily? Bad tires? ABS?Filling the tires with something other than air, to avoid puncture hassles?Used Michelin tires safe to install?Do these tyre cracks necessitate replacement?Rumbling noise: tires or mechanicalIs it possible to fix noisy feathered tires?Are bad winter tires still better than summer tires in winter?Torque converter failure - Related to replacing only 2 tires?Why use snow tires on all 4 wheels on 2-wheel-drive cars?