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Isometries between spherical space forms


Free actions of finite groups on products of even-dimensional spheresIsometry classification of spherical space formsRealizing a homology by a smooth immersionCombination theorems for discrete subgroups of isometry groupsGeodesic cuffs of pairs of pants in a hyperbolic manifold- why are they disjoint?Groups of equi-quasi-isometric diffeomorphisms of a Riemannian surface of bounded geometryWhich spherical space forms embed in $S^4$?Relation between conjugacy class, quotient isomorphism class, and signature of Fuchsian groups4-manifolds with finite fundamental group and spherical boundaryCan a hyperbolic manifold be a product?













3












$begingroup$


Let $S^n/Gamma_i,(i=1,2)$ be a $n$-dimensional spherical space form, where $Gamma_i subset SO(n+1)$ is a finite subgroup acting freely on $S^n$.



Suppose $S^n/Gamma_1$ is diffeomorphic to $S^n/Gamma_2$, can we show they are isometric?










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    A big chunk of the details are in Thurston's "Three-Dimensional Geometry and Topology". As Igor mentioned, the primary technicality issue is Lens spaces, and that part isn't as developed in Thurston's book. Bonahon has a lovely proof in that context, and you can also find Bonahon's proof in Hatcher's 3-manifolds notes (on his web page).
    $endgroup$
    – Ryan Budney
    Mar 21 at 16:50










  • $begingroup$
    @RyanBudney Thursron's book and Hatcher's notes are about the three dimensional manifolds while the question is for any $n$. I see something missing here.
    $endgroup$
    – Piotr Hajlasz
    Mar 21 at 16:54










  • $begingroup$
    De Rham's theorem is for every dimension. For 3d lens spaces there are other proofs, I think.
    $endgroup$
    – Igor Belegradek
    Mar 21 at 16:59










  • $begingroup$
    Whoops, I just imagined this was the $n=3$ case. The general case is similar, although the Bonahon proof is particular to $n=3$.
    $endgroup$
    – Ryan Budney
    Mar 21 at 20:24















3












$begingroup$


Let $S^n/Gamma_i,(i=1,2)$ be a $n$-dimensional spherical space form, where $Gamma_i subset SO(n+1)$ is a finite subgroup acting freely on $S^n$.



Suppose $S^n/Gamma_1$ is diffeomorphic to $S^n/Gamma_2$, can we show they are isometric?










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    A big chunk of the details are in Thurston's "Three-Dimensional Geometry and Topology". As Igor mentioned, the primary technicality issue is Lens spaces, and that part isn't as developed in Thurston's book. Bonahon has a lovely proof in that context, and you can also find Bonahon's proof in Hatcher's 3-manifolds notes (on his web page).
    $endgroup$
    – Ryan Budney
    Mar 21 at 16:50










  • $begingroup$
    @RyanBudney Thursron's book and Hatcher's notes are about the three dimensional manifolds while the question is for any $n$. I see something missing here.
    $endgroup$
    – Piotr Hajlasz
    Mar 21 at 16:54










  • $begingroup$
    De Rham's theorem is for every dimension. For 3d lens spaces there are other proofs, I think.
    $endgroup$
    – Igor Belegradek
    Mar 21 at 16:59










  • $begingroup$
    Whoops, I just imagined this was the $n=3$ case. The general case is similar, although the Bonahon proof is particular to $n=3$.
    $endgroup$
    – Ryan Budney
    Mar 21 at 20:24













3












3








3


2



$begingroup$


Let $S^n/Gamma_i,(i=1,2)$ be a $n$-dimensional spherical space form, where $Gamma_i subset SO(n+1)$ is a finite subgroup acting freely on $S^n$.



Suppose $S^n/Gamma_1$ is diffeomorphic to $S^n/Gamma_2$, can we show they are isometric?










share|cite|improve this question









$endgroup$




Let $S^n/Gamma_i,(i=1,2)$ be a $n$-dimensional spherical space form, where $Gamma_i subset SO(n+1)$ is a finite subgroup acting freely on $S^n$.



Suppose $S^n/Gamma_1$ is diffeomorphic to $S^n/Gamma_2$, can we show they are isometric?







gt.geometric-topology






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 21 at 15:00









TotoroTotoro

46327




46327







  • 1




    $begingroup$
    A big chunk of the details are in Thurston's "Three-Dimensional Geometry and Topology". As Igor mentioned, the primary technicality issue is Lens spaces, and that part isn't as developed in Thurston's book. Bonahon has a lovely proof in that context, and you can also find Bonahon's proof in Hatcher's 3-manifolds notes (on his web page).
    $endgroup$
    – Ryan Budney
    Mar 21 at 16:50










  • $begingroup$
    @RyanBudney Thursron's book and Hatcher's notes are about the three dimensional manifolds while the question is for any $n$. I see something missing here.
    $endgroup$
    – Piotr Hajlasz
    Mar 21 at 16:54










  • $begingroup$
    De Rham's theorem is for every dimension. For 3d lens spaces there are other proofs, I think.
    $endgroup$
    – Igor Belegradek
    Mar 21 at 16:59










  • $begingroup$
    Whoops, I just imagined this was the $n=3$ case. The general case is similar, although the Bonahon proof is particular to $n=3$.
    $endgroup$
    – Ryan Budney
    Mar 21 at 20:24












  • 1




    $begingroup$
    A big chunk of the details are in Thurston's "Three-Dimensional Geometry and Topology". As Igor mentioned, the primary technicality issue is Lens spaces, and that part isn't as developed in Thurston's book. Bonahon has a lovely proof in that context, and you can also find Bonahon's proof in Hatcher's 3-manifolds notes (on his web page).
    $endgroup$
    – Ryan Budney
    Mar 21 at 16:50










  • $begingroup$
    @RyanBudney Thursron's book and Hatcher's notes are about the three dimensional manifolds while the question is for any $n$. I see something missing here.
    $endgroup$
    – Piotr Hajlasz
    Mar 21 at 16:54










  • $begingroup$
    De Rham's theorem is for every dimension. For 3d lens spaces there are other proofs, I think.
    $endgroup$
    – Igor Belegradek
    Mar 21 at 16:59










  • $begingroup$
    Whoops, I just imagined this was the $n=3$ case. The general case is similar, although the Bonahon proof is particular to $n=3$.
    $endgroup$
    – Ryan Budney
    Mar 21 at 20:24







1




1




$begingroup$
A big chunk of the details are in Thurston's "Three-Dimensional Geometry and Topology". As Igor mentioned, the primary technicality issue is Lens spaces, and that part isn't as developed in Thurston's book. Bonahon has a lovely proof in that context, and you can also find Bonahon's proof in Hatcher's 3-manifolds notes (on his web page).
$endgroup$
– Ryan Budney
Mar 21 at 16:50




$begingroup$
A big chunk of the details are in Thurston's "Three-Dimensional Geometry and Topology". As Igor mentioned, the primary technicality issue is Lens spaces, and that part isn't as developed in Thurston's book. Bonahon has a lovely proof in that context, and you can also find Bonahon's proof in Hatcher's 3-manifolds notes (on his web page).
$endgroup$
– Ryan Budney
Mar 21 at 16:50












$begingroup$
@RyanBudney Thursron's book and Hatcher's notes are about the three dimensional manifolds while the question is for any $n$. I see something missing here.
$endgroup$
– Piotr Hajlasz
Mar 21 at 16:54




$begingroup$
@RyanBudney Thursron's book and Hatcher's notes are about the three dimensional manifolds while the question is for any $n$. I see something missing here.
$endgroup$
– Piotr Hajlasz
Mar 21 at 16:54












$begingroup$
De Rham's theorem is for every dimension. For 3d lens spaces there are other proofs, I think.
$endgroup$
– Igor Belegradek
Mar 21 at 16:59




$begingroup$
De Rham's theorem is for every dimension. For 3d lens spaces there are other proofs, I think.
$endgroup$
– Igor Belegradek
Mar 21 at 16:59












$begingroup$
Whoops, I just imagined this was the $n=3$ case. The general case is similar, although the Bonahon proof is particular to $n=3$.
$endgroup$
– Ryan Budney
Mar 21 at 20:24




$begingroup$
Whoops, I just imagined this was the $n=3$ case. The general case is similar, although the Bonahon proof is particular to $n=3$.
$endgroup$
– Ryan Budney
Mar 21 at 20:24










1 Answer
1






active

oldest

votes


















8












$begingroup$

Yes, diffeomorphic spherical space forms are isometric. This famous result of Georges de Rham can be found in [de Rham, G.
Complexes à automorphismes et homéomorphie différentiable.
Ann. Inst. Fourier Grenoble 2 (1950), 51–67 (1951)]. The main tool is Reidemeister's torsion. For lens spaces the result was proved by W. Franz in 1935.






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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

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    active

    oldest

    votes









    8












    $begingroup$

    Yes, diffeomorphic spherical space forms are isometric. This famous result of Georges de Rham can be found in [de Rham, G.
    Complexes à automorphismes et homéomorphie différentiable.
    Ann. Inst. Fourier Grenoble 2 (1950), 51–67 (1951)]. The main tool is Reidemeister's torsion. For lens spaces the result was proved by W. Franz in 1935.






    share|cite|improve this answer











    $endgroup$

















      8












      $begingroup$

      Yes, diffeomorphic spherical space forms are isometric. This famous result of Georges de Rham can be found in [de Rham, G.
      Complexes à automorphismes et homéomorphie différentiable.
      Ann. Inst. Fourier Grenoble 2 (1950), 51–67 (1951)]. The main tool is Reidemeister's torsion. For lens spaces the result was proved by W. Franz in 1935.






      share|cite|improve this answer











      $endgroup$















        8












        8








        8





        $begingroup$

        Yes, diffeomorphic spherical space forms are isometric. This famous result of Georges de Rham can be found in [de Rham, G.
        Complexes à automorphismes et homéomorphie différentiable.
        Ann. Inst. Fourier Grenoble 2 (1950), 51–67 (1951)]. The main tool is Reidemeister's torsion. For lens spaces the result was proved by W. Franz in 1935.






        share|cite|improve this answer











        $endgroup$



        Yes, diffeomorphic spherical space forms are isometric. This famous result of Georges de Rham can be found in [de Rham, G.
        Complexes à automorphismes et homéomorphie différentiable.
        Ann. Inst. Fourier Grenoble 2 (1950), 51–67 (1951)]. The main tool is Reidemeister's torsion. For lens spaces the result was proved by W. Franz in 1935.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Mar 21 at 15:52

























        answered Mar 21 at 15:44









        Igor BelegradekIgor Belegradek

        19.2k143125




        19.2k143125



























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