Isometries between spherical space formsFree actions of finite groups on products of even-dimensional spheresIsometry classification of spherical space formsRealizing a homology by a smooth immersionCombination theorems for discrete subgroups of isometry groupsGeodesic cuffs of pairs of pants in a hyperbolic manifold- why are they disjoint?Groups of equi-quasi-isometric diffeomorphisms of a Riemannian surface of bounded geometryWhich spherical space forms embed in $S^4$?Relation between conjugacy class, quotient isomorphism class, and signature of Fuchsian groups4-manifolds with finite fundamental group and spherical boundaryCan a hyperbolic manifold be a product?

Isometries between spherical space forms


Free actions of finite groups on products of even-dimensional spheresIsometry classification of spherical space formsRealizing a homology by a smooth immersionCombination theorems for discrete subgroups of isometry groupsGeodesic cuffs of pairs of pants in a hyperbolic manifold- why are they disjoint?Groups of equi-quasi-isometric diffeomorphisms of a Riemannian surface of bounded geometryWhich spherical space forms embed in $S^4$?Relation between conjugacy class, quotient isomorphism class, and signature of Fuchsian groups4-manifolds with finite fundamental group and spherical boundaryCan a hyperbolic manifold be a product?













3












$begingroup$


Let $S^n/Gamma_i,(i=1,2)$ be a $n$-dimensional spherical space form, where $Gamma_i subset SO(n+1)$ is a finite subgroup acting freely on $S^n$.



Suppose $S^n/Gamma_1$ is diffeomorphic to $S^n/Gamma_2$, can we show they are isometric?










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    A big chunk of the details are in Thurston's "Three-Dimensional Geometry and Topology". As Igor mentioned, the primary technicality issue is Lens spaces, and that part isn't as developed in Thurston's book. Bonahon has a lovely proof in that context, and you can also find Bonahon's proof in Hatcher's 3-manifolds notes (on his web page).
    $endgroup$
    – Ryan Budney
    Mar 21 at 16:50










  • $begingroup$
    @RyanBudney Thursron's book and Hatcher's notes are about the three dimensional manifolds while the question is for any $n$. I see something missing here.
    $endgroup$
    – Piotr Hajlasz
    Mar 21 at 16:54










  • $begingroup$
    De Rham's theorem is for every dimension. For 3d lens spaces there are other proofs, I think.
    $endgroup$
    – Igor Belegradek
    Mar 21 at 16:59










  • $begingroup$
    Whoops, I just imagined this was the $n=3$ case. The general case is similar, although the Bonahon proof is particular to $n=3$.
    $endgroup$
    – Ryan Budney
    Mar 21 at 20:24















3












$begingroup$


Let $S^n/Gamma_i,(i=1,2)$ be a $n$-dimensional spherical space form, where $Gamma_i subset SO(n+1)$ is a finite subgroup acting freely on $S^n$.



Suppose $S^n/Gamma_1$ is diffeomorphic to $S^n/Gamma_2$, can we show they are isometric?










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    A big chunk of the details are in Thurston's "Three-Dimensional Geometry and Topology". As Igor mentioned, the primary technicality issue is Lens spaces, and that part isn't as developed in Thurston's book. Bonahon has a lovely proof in that context, and you can also find Bonahon's proof in Hatcher's 3-manifolds notes (on his web page).
    $endgroup$
    – Ryan Budney
    Mar 21 at 16:50










  • $begingroup$
    @RyanBudney Thursron's book and Hatcher's notes are about the three dimensional manifolds while the question is for any $n$. I see something missing here.
    $endgroup$
    – Piotr Hajlasz
    Mar 21 at 16:54










  • $begingroup$
    De Rham's theorem is for every dimension. For 3d lens spaces there are other proofs, I think.
    $endgroup$
    – Igor Belegradek
    Mar 21 at 16:59










  • $begingroup$
    Whoops, I just imagined this was the $n=3$ case. The general case is similar, although the Bonahon proof is particular to $n=3$.
    $endgroup$
    – Ryan Budney
    Mar 21 at 20:24













3












3








3


2



$begingroup$


Let $S^n/Gamma_i,(i=1,2)$ be a $n$-dimensional spherical space form, where $Gamma_i subset SO(n+1)$ is a finite subgroup acting freely on $S^n$.



Suppose $S^n/Gamma_1$ is diffeomorphic to $S^n/Gamma_2$, can we show they are isometric?










share|cite|improve this question









$endgroup$




Let $S^n/Gamma_i,(i=1,2)$ be a $n$-dimensional spherical space form, where $Gamma_i subset SO(n+1)$ is a finite subgroup acting freely on $S^n$.



Suppose $S^n/Gamma_1$ is diffeomorphic to $S^n/Gamma_2$, can we show they are isometric?







gt.geometric-topology






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 21 at 15:00









TotoroTotoro

46327




46327







  • 1




    $begingroup$
    A big chunk of the details are in Thurston's "Three-Dimensional Geometry and Topology". As Igor mentioned, the primary technicality issue is Lens spaces, and that part isn't as developed in Thurston's book. Bonahon has a lovely proof in that context, and you can also find Bonahon's proof in Hatcher's 3-manifolds notes (on his web page).
    $endgroup$
    – Ryan Budney
    Mar 21 at 16:50










  • $begingroup$
    @RyanBudney Thursron's book and Hatcher's notes are about the three dimensional manifolds while the question is for any $n$. I see something missing here.
    $endgroup$
    – Piotr Hajlasz
    Mar 21 at 16:54










  • $begingroup$
    De Rham's theorem is for every dimension. For 3d lens spaces there are other proofs, I think.
    $endgroup$
    – Igor Belegradek
    Mar 21 at 16:59










  • $begingroup$
    Whoops, I just imagined this was the $n=3$ case. The general case is similar, although the Bonahon proof is particular to $n=3$.
    $endgroup$
    – Ryan Budney
    Mar 21 at 20:24












  • 1




    $begingroup$
    A big chunk of the details are in Thurston's "Three-Dimensional Geometry and Topology". As Igor mentioned, the primary technicality issue is Lens spaces, and that part isn't as developed in Thurston's book. Bonahon has a lovely proof in that context, and you can also find Bonahon's proof in Hatcher's 3-manifolds notes (on his web page).
    $endgroup$
    – Ryan Budney
    Mar 21 at 16:50










  • $begingroup$
    @RyanBudney Thursron's book and Hatcher's notes are about the three dimensional manifolds while the question is for any $n$. I see something missing here.
    $endgroup$
    – Piotr Hajlasz
    Mar 21 at 16:54










  • $begingroup$
    De Rham's theorem is for every dimension. For 3d lens spaces there are other proofs, I think.
    $endgroup$
    – Igor Belegradek
    Mar 21 at 16:59










  • $begingroup$
    Whoops, I just imagined this was the $n=3$ case. The general case is similar, although the Bonahon proof is particular to $n=3$.
    $endgroup$
    – Ryan Budney
    Mar 21 at 20:24







1




1




$begingroup$
A big chunk of the details are in Thurston's "Three-Dimensional Geometry and Topology". As Igor mentioned, the primary technicality issue is Lens spaces, and that part isn't as developed in Thurston's book. Bonahon has a lovely proof in that context, and you can also find Bonahon's proof in Hatcher's 3-manifolds notes (on his web page).
$endgroup$
– Ryan Budney
Mar 21 at 16:50




$begingroup$
A big chunk of the details are in Thurston's "Three-Dimensional Geometry and Topology". As Igor mentioned, the primary technicality issue is Lens spaces, and that part isn't as developed in Thurston's book. Bonahon has a lovely proof in that context, and you can also find Bonahon's proof in Hatcher's 3-manifolds notes (on his web page).
$endgroup$
– Ryan Budney
Mar 21 at 16:50












$begingroup$
@RyanBudney Thursron's book and Hatcher's notes are about the three dimensional manifolds while the question is for any $n$. I see something missing here.
$endgroup$
– Piotr Hajlasz
Mar 21 at 16:54




$begingroup$
@RyanBudney Thursron's book and Hatcher's notes are about the three dimensional manifolds while the question is for any $n$. I see something missing here.
$endgroup$
– Piotr Hajlasz
Mar 21 at 16:54












$begingroup$
De Rham's theorem is for every dimension. For 3d lens spaces there are other proofs, I think.
$endgroup$
– Igor Belegradek
Mar 21 at 16:59




$begingroup$
De Rham's theorem is for every dimension. For 3d lens spaces there are other proofs, I think.
$endgroup$
– Igor Belegradek
Mar 21 at 16:59












$begingroup$
Whoops, I just imagined this was the $n=3$ case. The general case is similar, although the Bonahon proof is particular to $n=3$.
$endgroup$
– Ryan Budney
Mar 21 at 20:24




$begingroup$
Whoops, I just imagined this was the $n=3$ case. The general case is similar, although the Bonahon proof is particular to $n=3$.
$endgroup$
– Ryan Budney
Mar 21 at 20:24










1 Answer
1






active

oldest

votes


















8












$begingroup$

Yes, diffeomorphic spherical space forms are isometric. This famous result of Georges de Rham can be found in [de Rham, G.
Complexes à automorphismes et homéomorphie différentiable.
Ann. Inst. Fourier Grenoble 2 (1950), 51–67 (1951)]. The main tool is Reidemeister's torsion. For lens spaces the result was proved by W. Franz in 1935.






share|cite|improve this answer











$endgroup$












    Your Answer





    StackExchange.ifUsing("editor", function ()
    return StackExchange.using("mathjaxEditing", function ()
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    );
    );
    , "mathjax-editing");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "504"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathoverflow.net%2fquestions%2f325973%2fisometries-between-spherical-space-forms%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    8












    $begingroup$

    Yes, diffeomorphic spherical space forms are isometric. This famous result of Georges de Rham can be found in [de Rham, G.
    Complexes à automorphismes et homéomorphie différentiable.
    Ann. Inst. Fourier Grenoble 2 (1950), 51–67 (1951)]. The main tool is Reidemeister's torsion. For lens spaces the result was proved by W. Franz in 1935.






    share|cite|improve this answer











    $endgroup$

















      8












      $begingroup$

      Yes, diffeomorphic spherical space forms are isometric. This famous result of Georges de Rham can be found in [de Rham, G.
      Complexes à automorphismes et homéomorphie différentiable.
      Ann. Inst. Fourier Grenoble 2 (1950), 51–67 (1951)]. The main tool is Reidemeister's torsion. For lens spaces the result was proved by W. Franz in 1935.






      share|cite|improve this answer











      $endgroup$















        8












        8








        8





        $begingroup$

        Yes, diffeomorphic spherical space forms are isometric. This famous result of Georges de Rham can be found in [de Rham, G.
        Complexes à automorphismes et homéomorphie différentiable.
        Ann. Inst. Fourier Grenoble 2 (1950), 51–67 (1951)]. The main tool is Reidemeister's torsion. For lens spaces the result was proved by W. Franz in 1935.






        share|cite|improve this answer











        $endgroup$



        Yes, diffeomorphic spherical space forms are isometric. This famous result of Georges de Rham can be found in [de Rham, G.
        Complexes à automorphismes et homéomorphie différentiable.
        Ann. Inst. Fourier Grenoble 2 (1950), 51–67 (1951)]. The main tool is Reidemeister's torsion. For lens spaces the result was proved by W. Franz in 1935.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Mar 21 at 15:52

























        answered Mar 21 at 15:44









        Igor BelegradekIgor Belegradek

        19.2k143125




        19.2k143125



























            draft saved

            draft discarded
















































            Thanks for contributing an answer to MathOverflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathoverflow.net%2fquestions%2f325973%2fisometries-between-spherical-space-forms%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Adding axes to figuresAdding axes labels to LaTeX figuresLaTeX equivalent of ConTeXt buffersRotate a node but not its content: the case of the ellipse decorationHow to define the default vertical distance between nodes?TikZ scaling graphic and adjust node position and keep font sizeNumerical conditional within tikz keys?adding axes to shapesAlign axes across subfiguresAdding figures with a certain orderLine up nested tikz enviroments or how to get rid of themAdding axes labels to LaTeX figures

            Luettelo Yhdysvaltain laivaston lentotukialuksista Lähteet | Navigointivalikko

            Gary (muusikko) Sisällysluettelo Historia | Rockin' High | Lähteet | Aiheesta muualla | NavigointivalikkoInfobox OKTuomas "Gary" Keskinen Ancaran kitaristiksiProjekti Rockin' High