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How to format a long polynomial



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)Why are default LaTeX margins so big?Polynomial Long Division over GF(p)Why does widehat behave differently if I insert hspace0pt?Converting all numbers in document to set number of decimal placesHow to construct a long equation that is split in LHS and RHS to occupy a narrow column?Using mathspec to change digits font in math mode isn't workingStrange alignment issue in subequationsCorrect typesetting of a formula with a long fractionWriting Lines and Lines of Math Without Continuation CharactersHow continue a equation next lineIn the figure form, adjust the whole size of “text” and “math” format at once (II): from twocolumngrid to onecolumngrid










10















I have a long polynomial:



documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
$ f(z)=frac1382112640(-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028\
079eta^3+347370177721463765064153eta)/((417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001))$
enddocument


How do I format such a long polynomial correctly?










share|improve this question



















  • 5





    For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_i,j$ and then adding a table to show the values.

    – Mefitico
    Apr 5 at 11:59






  • 1





    @Mefitico It is a nice option! Why don't you post an answer?

    – JouleV
    Apr 5 at 12:12






  • 1





    @JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"

    – Mefitico
    Apr 5 at 12:19











  • @Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.

    – JouleV
    Apr 5 at 12:23















10















I have a long polynomial:



documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
$ f(z)=frac1382112640(-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028\
079eta^3+347370177721463765064153eta)/((417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001))$
enddocument


How do I format such a long polynomial correctly?










share|improve this question



















  • 5





    For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_i,j$ and then adding a table to show the values.

    – Mefitico
    Apr 5 at 11:59






  • 1





    @Mefitico It is a nice option! Why don't you post an answer?

    – JouleV
    Apr 5 at 12:12






  • 1





    @JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"

    – Mefitico
    Apr 5 at 12:19











  • @Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.

    – JouleV
    Apr 5 at 12:23













10












10








10








I have a long polynomial:



documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
$ f(z)=frac1382112640(-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028\
079eta^3+347370177721463765064153eta)/((417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001))$
enddocument


How do I format such a long polynomial correctly?










share|improve this question
















I have a long polynomial:



documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
$ f(z)=frac1382112640(-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028\
079eta^3+347370177721463765064153eta)/((417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001))$
enddocument


How do I format such a long polynomial correctly?







math-mode






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Apr 7 at 10:20









Peter Mortensen

55437




55437










asked Apr 5 at 7:16









NickNick

1988




1988







  • 5





    For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_i,j$ and then adding a table to show the values.

    – Mefitico
    Apr 5 at 11:59






  • 1





    @Mefitico It is a nice option! Why don't you post an answer?

    – JouleV
    Apr 5 at 12:12






  • 1





    @JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"

    – Mefitico
    Apr 5 at 12:19











  • @Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.

    – JouleV
    Apr 5 at 12:23












  • 5





    For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_i,j$ and then adding a table to show the values.

    – Mefitico
    Apr 5 at 11:59






  • 1





    @Mefitico It is a nice option! Why don't you post an answer?

    – JouleV
    Apr 5 at 12:12






  • 1





    @JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"

    – Mefitico
    Apr 5 at 12:19











  • @Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.

    – JouleV
    Apr 5 at 12:23







5




5





For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_i,j$ and then adding a table to show the values.

– Mefitico
Apr 5 at 11:59





For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_i,j$ and then adding a table to show the values.

– Mefitico
Apr 5 at 11:59




1




1





@Mefitico It is a nice option! Why don't you post an answer?

– JouleV
Apr 5 at 12:12





@Mefitico It is a nice option! Why don't you post an answer?

– JouleV
Apr 5 at 12:12




1




1





@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"

– Mefitico
Apr 5 at 12:19





@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"

– Mefitico
Apr 5 at 12:19













@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.

– JouleV
Apr 5 at 12:23





@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.

– JouleV
Apr 5 at 12:23










7 Answers
7






active

oldest

votes


















15














I would use something like this



documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools
begindocument
Blah blah
[f(z)=frac1382112640cdotfracAB]
where
beginalign*
A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
&,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
&,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
&,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
&,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
&,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
&,+82327155732241730770824eta z-514623285385260545505123eta^2z\
&,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
&,-43808044579418934376632-214023244873618345872240eta^4\
&,+11818373349781028079eta^3+347370177721463765064153eta
endalign*
and
[B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
enddocument


enter image description here






share|improve this answer


















  • 1





    you could format this even more compactly by using matrix multiplication to express A

    – Tasos Papastylianou
    Apr 5 at 15:44


















13














I suggest something line the following, so the wide terms are reduced.



documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools

begindocument

begingather*
beginalign*
g(eta,z)&=
parbox[t]0.85displaywidthraggedright
$-306772802511648469920eta^4z^4+
762453974480763801600eta^5z^4-
1678626210368271790080eta^5z^3-
28510918043555533736160eta^4z^3+
11443138641451067779872eta^3z^3-
52164076923190540413504eta^2z^2-
78145258181161076156160eta^5z^2-
211306163712129371808450eta^4z^2+
228927087397104405937944eta^3z^2+
999881065017543109136462eta^3z-
317254092617698017425280eta^5z-
443761561344388063474665eta^4z+
82327155732241730770824eta z-
514623285385260545505123eta^2z-
1010535343560043404912120eta^2-
357788302700438191196160eta^5-
43808044579418934376632-
214023244873618345872240eta^4+
11818373349781028079eta^3+
347370177721463765064153eta$

\[2ex]
h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
endalign*
\[2ex]
f(z)=frac1382112640fracg(eta,z)h(z)
endgather*

enddocument


enter image description here






share|improve this answer























  • your answer is OK, but some terms are out of pages margins.

    – Nick
    Apr 5 at 8:01






  • 8





    @Nick Without knowing the line width you're using it's difficult to say more.

    – egreg
    Apr 5 at 8:19











  • @Nick egreg's answer uses default margin of article, which is already really big. But it doesn't fit your margin?

    – JouleV
    Apr 5 at 8:29











  • I have moved the signs "-, +" from lines end and put them under sign "=".

    – Nick
    Apr 5 at 8:36


















8














Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:





where:





Code:



$$ f(z)=frac1382,112,640 ; fracg(eta, z)u(z) , v(z) , w(z) $$

where

$$
beginarrayll
g(eta, z) =
beginbmatrix
beginarrayr @hspace0em r
- & 306,772,802,511,648,469,920 \
& 762,453,974,480,763,801,600 \
- & 1,678,626,210,368,271,790,080 \
- & 28,510,918,043,555,533,736,160 \
& 11,443,138,641,451,067,779,872 \
- & 52,164,076,923,190,540,413,504 \
- & 78,145,258,181,161,076,156,160 \
- & 211,306,163,712,129,371,808,450 \
& 228,927,087,397,104,405,937,944 \
& 999,881,065,017,543,109,136,462 \
- & 317,254,092,617,698,017,425,280 \
- & 443,761,561,344,388,063,474,665 \
& 82,327,155,732,241,730,770,824 \
- & 514,623,285,385,260,545,505,123 \
- & 1,010,535,343,560,043,404,912,120 \
- & 357,788,302,700,438,191,196,160 \
- & 43,808,044,579,418,934,376,632 \
- & 214,023,244,873,618,345,872,240 \
& 11,818,373,349,781,028,079 \
& 347,370,177,721,463,765,064,153
endarray
endbmatrix^T
beginbmatrix
beginarrayl
eta^4z^4 \
eta^5z^4 \
eta^5z^3 \
eta^4z^3 \
eta^3z^3 \
eta^2z^2 \
eta^5z^2 \
eta^4z^2 \
eta^3z^2 \
eta^3z \
eta^5z \
eta^4z \
eta z \
eta^2z \
eta^2 \
eta^5 \
1 \
eta^4 \
eta^3 \
eta
endarray
endbmatrix
&
beginarrayl
u(z) = beginbmatrix beginarrayr @hspace0em r & 417,420 \ - & 4,169,121 \ - & 15,571,312 endarrayendbmatrix^T beginbmatrix beginarrayl z^2 \ z \ 1 endarrayendbmatrix\[3em]
v(z) = beginbmatrix beginarrayr @hspace0em r & 1,546 \ & 3,537 endarrayendbmatrix^T beginbmatrixbeginarrayl z \ 1 endarrayendbmatrix\[3em]
w(z) = beginbmatrixbeginarrayr @hspace0em r & 3,092 \ & 17,001 endarrayendbmatrix^T beginbmatrixbeginarrayl z \ 1 endarrayendbmatrix \[3em]
endarray
endarray
$$



PS. Having said that, given the nature of the numbers involved, I would also agree with Mefitico's point of view in the comments, i.e. it's best to create a variable with indices and express via a cleaner expression, and then refer to a table mapping those indices to the actual numbers involved.






share|improve this answer




















  • 1





    The round brackets in the definitions of $u$, $v$ and $w$ seem superfluous.

    – jochen
    Apr 6 at 11:00






  • 1





    From the point of view of someone wishing or needing to use such a polynomial, it would be helpful to insert breaks in all the long numbers to ease readability.

    – JeremyC
    Apr 7 at 3:49











  • @jochen thanks, updated

    – Tasos Papastylianou
    Apr 7 at 15:51











  • @JeremyC thanks, updated. I went for comma delimiters rather than breaks, as that might have been misleading in the context of matrix notation.

    – Tasos Papastylianou
    Apr 7 at 15:51


















6














or



enter image description here



documentclassarticle
%usepackageamsmath% Loaded by mathtools
usepackagemathtools, nccmath
begindocument
beginmultline*medmath
f(z)=frac1382112640
fracleft[
beginmultlined
-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
82327155732241730770824eta z - 514623285385260545505123eta^2z-\
1010535343560043404912120eta^2-357788302700438191196160eta^5-\
43808044579418934376632-214023244873618345872240eta^4+\
11818373349781028079eta^3+347370177721463765064153eta
endmultlinedright]
(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
endmultline*





share|improve this answer






























    2














    I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.



    documentclassarticle
    %usepackageamsmath% Loaded by mathtools
    usepackagemathtools
    begindocument
    Blah blah
    [f(z)=frac1382112640cdotfracAB]
    where
    [
    arraycolsep=0.5pt
    beginarrayrrllrll
    A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
    &, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
    &, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
    &, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
    &, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
    &, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
    &, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
    &,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
    &, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
    &, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
    endarray
    ]
    and
    [B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
    enddocument


    I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:



    enter image description here






    share|improve this answer






























      0














      I would usually use the package breqn. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn and sansmath in the same document)



      begindmath*
      f(z)=frac1382112640times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^-1
      enddmath*


      which produces this huge equation



      IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat version.






      share|improve this answer






























        0














        Following the original disposition of the function, but using alignat, parenthesis, and fractions to emphasize its different terms.



        documentclassarticle

        usepackagemathtools

        begindocument

        beginalignat*2
        & f(z) && = frac1382112640 times left( vphantomfrac1382112640 -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
        & && -1678626210368271790080 eta^5 z^3 -28510918043555533736160 eta^4 z^3 \[1.5ex]
        & && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
        & && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
        & && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
        & && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
        & && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
        & && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
        & && -43808044579418934376632 -214023244873618345872240 eta^4 \[1.5ex]
        & && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantomfrac1382112640 right) \[1.5ex]
        & && times frac1(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
        endalignat*

        enddocument


        fig






        share|improve this answer

























        • Do you think this fits the page margin?

          – JouleV
          Apr 5 at 9:14











        • It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.

          – Andre
          Apr 5 at 9:22












        • In the original question, the term 417420z^2-4169121z-15571312 is in denominator, not in the numerator as you place it.

          – quark67
          Apr 7 at 0:32











        • OK. I will revise this.

          – Andre
          Apr 7 at 8:37











        • Revised the members of the last fraction. Also added a line for the last term (which also ensures that the display will fit the margins).

          – Andre
          Apr 7 at 10:12












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        7 Answers
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        15














        I would use something like this



        documentclassarticle
        %usepackageamsmath% Loaded by mathtools
        usepackagemathtools
        begindocument
        Blah blah
        [f(z)=frac1382112640cdotfracAB]
        where
        beginalign*
        A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
        &,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
        &,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
        &,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
        &,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
        &,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
        &,+82327155732241730770824eta z-514623285385260545505123eta^2z\
        &,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
        &,-43808044579418934376632-214023244873618345872240eta^4\
        &,+11818373349781028079eta^3+347370177721463765064153eta
        endalign*
        and
        [B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
        enddocument


        enter image description here






        share|improve this answer


















        • 1





          you could format this even more compactly by using matrix multiplication to express A

          – Tasos Papastylianou
          Apr 5 at 15:44















        15














        I would use something like this



        documentclassarticle
        %usepackageamsmath% Loaded by mathtools
        usepackagemathtools
        begindocument
        Blah blah
        [f(z)=frac1382112640cdotfracAB]
        where
        beginalign*
        A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
        &,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
        &,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
        &,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
        &,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
        &,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
        &,+82327155732241730770824eta z-514623285385260545505123eta^2z\
        &,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
        &,-43808044579418934376632-214023244873618345872240eta^4\
        &,+11818373349781028079eta^3+347370177721463765064153eta
        endalign*
        and
        [B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
        enddocument


        enter image description here






        share|improve this answer


















        • 1





          you could format this even more compactly by using matrix multiplication to express A

          – Tasos Papastylianou
          Apr 5 at 15:44













        15












        15








        15







        I would use something like this



        documentclassarticle
        %usepackageamsmath% Loaded by mathtools
        usepackagemathtools
        begindocument
        Blah blah
        [f(z)=frac1382112640cdotfracAB]
        where
        beginalign*
        A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
        &,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
        &,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
        &,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
        &,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
        &,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
        &,+82327155732241730770824eta z-514623285385260545505123eta^2z\
        &,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
        &,-43808044579418934376632-214023244873618345872240eta^4\
        &,+11818373349781028079eta^3+347370177721463765064153eta
        endalign*
        and
        [B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
        enddocument


        enter image description here






        share|improve this answer













        I would use something like this



        documentclassarticle
        %usepackageamsmath% Loaded by mathtools
        usepackagemathtools
        begindocument
        Blah blah
        [f(z)=frac1382112640cdotfracAB]
        where
        beginalign*
        A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
        &,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
        &,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
        &,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
        &,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
        &,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
        &,+82327155732241730770824eta z-514623285385260545505123eta^2z\
        &,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
        &,-43808044579418934376632-214023244873618345872240eta^4\
        &,+11818373349781028079eta^3+347370177721463765064153eta
        endalign*
        and
        [B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
        enddocument


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Apr 5 at 7:24









        JouleVJouleV

        15.1k22666




        15.1k22666







        • 1





          you could format this even more compactly by using matrix multiplication to express A

          – Tasos Papastylianou
          Apr 5 at 15:44












        • 1





          you could format this even more compactly by using matrix multiplication to express A

          – Tasos Papastylianou
          Apr 5 at 15:44







        1




        1





        you could format this even more compactly by using matrix multiplication to express A

        – Tasos Papastylianou
        Apr 5 at 15:44





        you could format this even more compactly by using matrix multiplication to express A

        – Tasos Papastylianou
        Apr 5 at 15:44











        13














        I suggest something line the following, so the wide terms are reduced.



        documentclassarticle
        %usepackageamsmath% Loaded by mathtools
        usepackagemathtools

        begindocument

        begingather*
        beginalign*
        g(eta,z)&=
        parbox[t]0.85displaywidthraggedright
        $-306772802511648469920eta^4z^4+
        762453974480763801600eta^5z^4-
        1678626210368271790080eta^5z^3-
        28510918043555533736160eta^4z^3+
        11443138641451067779872eta^3z^3-
        52164076923190540413504eta^2z^2-
        78145258181161076156160eta^5z^2-
        211306163712129371808450eta^4z^2+
        228927087397104405937944eta^3z^2+
        999881065017543109136462eta^3z-
        317254092617698017425280eta^5z-
        443761561344388063474665eta^4z+
        82327155732241730770824eta z-
        514623285385260545505123eta^2z-
        1010535343560043404912120eta^2-
        357788302700438191196160eta^5-
        43808044579418934376632-
        214023244873618345872240eta^4+
        11818373349781028079eta^3+
        347370177721463765064153eta$

        \[2ex]
        h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
        endalign*
        \[2ex]
        f(z)=frac1382112640fracg(eta,z)h(z)
        endgather*

        enddocument


        enter image description here






        share|improve this answer























        • your answer is OK, but some terms are out of pages margins.

          – Nick
          Apr 5 at 8:01






        • 8





          @Nick Without knowing the line width you're using it's difficult to say more.

          – egreg
          Apr 5 at 8:19











        • @Nick egreg's answer uses default margin of article, which is already really big. But it doesn't fit your margin?

          – JouleV
          Apr 5 at 8:29











        • I have moved the signs "-, +" from lines end and put them under sign "=".

          – Nick
          Apr 5 at 8:36















        13














        I suggest something line the following, so the wide terms are reduced.



        documentclassarticle
        %usepackageamsmath% Loaded by mathtools
        usepackagemathtools

        begindocument

        begingather*
        beginalign*
        g(eta,z)&=
        parbox[t]0.85displaywidthraggedright
        $-306772802511648469920eta^4z^4+
        762453974480763801600eta^5z^4-
        1678626210368271790080eta^5z^3-
        28510918043555533736160eta^4z^3+
        11443138641451067779872eta^3z^3-
        52164076923190540413504eta^2z^2-
        78145258181161076156160eta^5z^2-
        211306163712129371808450eta^4z^2+
        228927087397104405937944eta^3z^2+
        999881065017543109136462eta^3z-
        317254092617698017425280eta^5z-
        443761561344388063474665eta^4z+
        82327155732241730770824eta z-
        514623285385260545505123eta^2z-
        1010535343560043404912120eta^2-
        357788302700438191196160eta^5-
        43808044579418934376632-
        214023244873618345872240eta^4+
        11818373349781028079eta^3+
        347370177721463765064153eta$

        \[2ex]
        h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
        endalign*
        \[2ex]
        f(z)=frac1382112640fracg(eta,z)h(z)
        endgather*

        enddocument


        enter image description here






        share|improve this answer























        • your answer is OK, but some terms are out of pages margins.

          – Nick
          Apr 5 at 8:01






        • 8





          @Nick Without knowing the line width you're using it's difficult to say more.

          – egreg
          Apr 5 at 8:19











        • @Nick egreg's answer uses default margin of article, which is already really big. But it doesn't fit your margin?

          – JouleV
          Apr 5 at 8:29











        • I have moved the signs "-, +" from lines end and put them under sign "=".

          – Nick
          Apr 5 at 8:36













        13












        13








        13







        I suggest something line the following, so the wide terms are reduced.



        documentclassarticle
        %usepackageamsmath% Loaded by mathtools
        usepackagemathtools

        begindocument

        begingather*
        beginalign*
        g(eta,z)&=
        parbox[t]0.85displaywidthraggedright
        $-306772802511648469920eta^4z^4+
        762453974480763801600eta^5z^4-
        1678626210368271790080eta^5z^3-
        28510918043555533736160eta^4z^3+
        11443138641451067779872eta^3z^3-
        52164076923190540413504eta^2z^2-
        78145258181161076156160eta^5z^2-
        211306163712129371808450eta^4z^2+
        228927087397104405937944eta^3z^2+
        999881065017543109136462eta^3z-
        317254092617698017425280eta^5z-
        443761561344388063474665eta^4z+
        82327155732241730770824eta z-
        514623285385260545505123eta^2z-
        1010535343560043404912120eta^2-
        357788302700438191196160eta^5-
        43808044579418934376632-
        214023244873618345872240eta^4+
        11818373349781028079eta^3+
        347370177721463765064153eta$

        \[2ex]
        h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
        endalign*
        \[2ex]
        f(z)=frac1382112640fracg(eta,z)h(z)
        endgather*

        enddocument


        enter image description here






        share|improve this answer













        I suggest something line the following, so the wide terms are reduced.



        documentclassarticle
        %usepackageamsmath% Loaded by mathtools
        usepackagemathtools

        begindocument

        begingather*
        beginalign*
        g(eta,z)&=
        parbox[t]0.85displaywidthraggedright
        $-306772802511648469920eta^4z^4+
        762453974480763801600eta^5z^4-
        1678626210368271790080eta^5z^3-
        28510918043555533736160eta^4z^3+
        11443138641451067779872eta^3z^3-
        52164076923190540413504eta^2z^2-
        78145258181161076156160eta^5z^2-
        211306163712129371808450eta^4z^2+
        228927087397104405937944eta^3z^2+
        999881065017543109136462eta^3z-
        317254092617698017425280eta^5z-
        443761561344388063474665eta^4z+
        82327155732241730770824eta z-
        514623285385260545505123eta^2z-
        1010535343560043404912120eta^2-
        357788302700438191196160eta^5-
        43808044579418934376632-
        214023244873618345872240eta^4+
        11818373349781028079eta^3+
        347370177721463765064153eta$

        \[2ex]
        h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
        endalign*
        \[2ex]
        f(z)=frac1382112640fracg(eta,z)h(z)
        endgather*

        enddocument


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Apr 5 at 7:32









        egregegreg

        736k8919353261




        736k8919353261












        • your answer is OK, but some terms are out of pages margins.

          – Nick
          Apr 5 at 8:01






        • 8





          @Nick Without knowing the line width you're using it's difficult to say more.

          – egreg
          Apr 5 at 8:19











        • @Nick egreg's answer uses default margin of article, which is already really big. But it doesn't fit your margin?

          – JouleV
          Apr 5 at 8:29











        • I have moved the signs "-, +" from lines end and put them under sign "=".

          – Nick
          Apr 5 at 8:36

















        • your answer is OK, but some terms are out of pages margins.

          – Nick
          Apr 5 at 8:01






        • 8





          @Nick Without knowing the line width you're using it's difficult to say more.

          – egreg
          Apr 5 at 8:19











        • @Nick egreg's answer uses default margin of article, which is already really big. But it doesn't fit your margin?

          – JouleV
          Apr 5 at 8:29











        • I have moved the signs "-, +" from lines end and put them under sign "=".

          – Nick
          Apr 5 at 8:36
















        your answer is OK, but some terms are out of pages margins.

        – Nick
        Apr 5 at 8:01





        your answer is OK, but some terms are out of pages margins.

        – Nick
        Apr 5 at 8:01




        8




        8





        @Nick Without knowing the line width you're using it's difficult to say more.

        – egreg
        Apr 5 at 8:19





        @Nick Without knowing the line width you're using it's difficult to say more.

        – egreg
        Apr 5 at 8:19













        @Nick egreg's answer uses default margin of article, which is already really big. But it doesn't fit your margin?

        – JouleV
        Apr 5 at 8:29





        @Nick egreg's answer uses default margin of article, which is already really big. But it doesn't fit your margin?

        – JouleV
        Apr 5 at 8:29













        I have moved the signs "-, +" from lines end and put them under sign "=".

        – Nick
        Apr 5 at 8:36





        I have moved the signs "-, +" from lines end and put them under sign "=".

        – Nick
        Apr 5 at 8:36











        8














        Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:





        where:





        Code:



        $$ f(z)=frac1382,112,640 ; fracg(eta, z)u(z) , v(z) , w(z) $$

        where

        $$
        beginarrayll
        g(eta, z) =
        beginbmatrix
        beginarrayr @hspace0em r
        - & 306,772,802,511,648,469,920 \
        & 762,453,974,480,763,801,600 \
        - & 1,678,626,210,368,271,790,080 \
        - & 28,510,918,043,555,533,736,160 \
        & 11,443,138,641,451,067,779,872 \
        - & 52,164,076,923,190,540,413,504 \
        - & 78,145,258,181,161,076,156,160 \
        - & 211,306,163,712,129,371,808,450 \
        & 228,927,087,397,104,405,937,944 \
        & 999,881,065,017,543,109,136,462 \
        - & 317,254,092,617,698,017,425,280 \
        - & 443,761,561,344,388,063,474,665 \
        & 82,327,155,732,241,730,770,824 \
        - & 514,623,285,385,260,545,505,123 \
        - & 1,010,535,343,560,043,404,912,120 \
        - & 357,788,302,700,438,191,196,160 \
        - & 43,808,044,579,418,934,376,632 \
        - & 214,023,244,873,618,345,872,240 \
        & 11,818,373,349,781,028,079 \
        & 347,370,177,721,463,765,064,153
        endarray
        endbmatrix^T
        beginbmatrix
        beginarrayl
        eta^4z^4 \
        eta^5z^4 \
        eta^5z^3 \
        eta^4z^3 \
        eta^3z^3 \
        eta^2z^2 \
        eta^5z^2 \
        eta^4z^2 \
        eta^3z^2 \
        eta^3z \
        eta^5z \
        eta^4z \
        eta z \
        eta^2z \
        eta^2 \
        eta^5 \
        1 \
        eta^4 \
        eta^3 \
        eta
        endarray
        endbmatrix
        &
        beginarrayl
        u(z) = beginbmatrix beginarrayr @hspace0em r & 417,420 \ - & 4,169,121 \ - & 15,571,312 endarrayendbmatrix^T beginbmatrix beginarrayl z^2 \ z \ 1 endarrayendbmatrix\[3em]
        v(z) = beginbmatrix beginarrayr @hspace0em r & 1,546 \ & 3,537 endarrayendbmatrix^T beginbmatrixbeginarrayl z \ 1 endarrayendbmatrix\[3em]
        w(z) = beginbmatrixbeginarrayr @hspace0em r & 3,092 \ & 17,001 endarrayendbmatrix^T beginbmatrixbeginarrayl z \ 1 endarrayendbmatrix \[3em]
        endarray
        endarray
        $$



        PS. Having said that, given the nature of the numbers involved, I would also agree with Mefitico's point of view in the comments, i.e. it's best to create a variable with indices and express via a cleaner expression, and then refer to a table mapping those indices to the actual numbers involved.






        share|improve this answer




















        • 1





          The round brackets in the definitions of $u$, $v$ and $w$ seem superfluous.

          – jochen
          Apr 6 at 11:00






        • 1





          From the point of view of someone wishing or needing to use such a polynomial, it would be helpful to insert breaks in all the long numbers to ease readability.

          – JeremyC
          Apr 7 at 3:49











        • @jochen thanks, updated

          – Tasos Papastylianou
          Apr 7 at 15:51











        • @JeremyC thanks, updated. I went for comma delimiters rather than breaks, as that might have been misleading in the context of matrix notation.

          – Tasos Papastylianou
          Apr 7 at 15:51















        8














        Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:





        where:





        Code:



        $$ f(z)=frac1382,112,640 ; fracg(eta, z)u(z) , v(z) , w(z) $$

        where

        $$
        beginarrayll
        g(eta, z) =
        beginbmatrix
        beginarrayr @hspace0em r
        - & 306,772,802,511,648,469,920 \
        & 762,453,974,480,763,801,600 \
        - & 1,678,626,210,368,271,790,080 \
        - & 28,510,918,043,555,533,736,160 \
        & 11,443,138,641,451,067,779,872 \
        - & 52,164,076,923,190,540,413,504 \
        - & 78,145,258,181,161,076,156,160 \
        - & 211,306,163,712,129,371,808,450 \
        & 228,927,087,397,104,405,937,944 \
        & 999,881,065,017,543,109,136,462 \
        - & 317,254,092,617,698,017,425,280 \
        - & 443,761,561,344,388,063,474,665 \
        & 82,327,155,732,241,730,770,824 \
        - & 514,623,285,385,260,545,505,123 \
        - & 1,010,535,343,560,043,404,912,120 \
        - & 357,788,302,700,438,191,196,160 \
        - & 43,808,044,579,418,934,376,632 \
        - & 214,023,244,873,618,345,872,240 \
        & 11,818,373,349,781,028,079 \
        & 347,370,177,721,463,765,064,153
        endarray
        endbmatrix^T
        beginbmatrix
        beginarrayl
        eta^4z^4 \
        eta^5z^4 \
        eta^5z^3 \
        eta^4z^3 \
        eta^3z^3 \
        eta^2z^2 \
        eta^5z^2 \
        eta^4z^2 \
        eta^3z^2 \
        eta^3z \
        eta^5z \
        eta^4z \
        eta z \
        eta^2z \
        eta^2 \
        eta^5 \
        1 \
        eta^4 \
        eta^3 \
        eta
        endarray
        endbmatrix
        &
        beginarrayl
        u(z) = beginbmatrix beginarrayr @hspace0em r & 417,420 \ - & 4,169,121 \ - & 15,571,312 endarrayendbmatrix^T beginbmatrix beginarrayl z^2 \ z \ 1 endarrayendbmatrix\[3em]
        v(z) = beginbmatrix beginarrayr @hspace0em r & 1,546 \ & 3,537 endarrayendbmatrix^T beginbmatrixbeginarrayl z \ 1 endarrayendbmatrix\[3em]
        w(z) = beginbmatrixbeginarrayr @hspace0em r & 3,092 \ & 17,001 endarrayendbmatrix^T beginbmatrixbeginarrayl z \ 1 endarrayendbmatrix \[3em]
        endarray
        endarray
        $$



        PS. Having said that, given the nature of the numbers involved, I would also agree with Mefitico's point of view in the comments, i.e. it's best to create a variable with indices and express via a cleaner expression, and then refer to a table mapping those indices to the actual numbers involved.






        share|improve this answer




















        • 1





          The round brackets in the definitions of $u$, $v$ and $w$ seem superfluous.

          – jochen
          Apr 6 at 11:00






        • 1





          From the point of view of someone wishing or needing to use such a polynomial, it would be helpful to insert breaks in all the long numbers to ease readability.

          – JeremyC
          Apr 7 at 3:49











        • @jochen thanks, updated

          – Tasos Papastylianou
          Apr 7 at 15:51











        • @JeremyC thanks, updated. I went for comma delimiters rather than breaks, as that might have been misleading in the context of matrix notation.

          – Tasos Papastylianou
          Apr 7 at 15:51













        8












        8








        8







        Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:





        where:





        Code:



        $$ f(z)=frac1382,112,640 ; fracg(eta, z)u(z) , v(z) , w(z) $$

        where

        $$
        beginarrayll
        g(eta, z) =
        beginbmatrix
        beginarrayr @hspace0em r
        - & 306,772,802,511,648,469,920 \
        & 762,453,974,480,763,801,600 \
        - & 1,678,626,210,368,271,790,080 \
        - & 28,510,918,043,555,533,736,160 \
        & 11,443,138,641,451,067,779,872 \
        - & 52,164,076,923,190,540,413,504 \
        - & 78,145,258,181,161,076,156,160 \
        - & 211,306,163,712,129,371,808,450 \
        & 228,927,087,397,104,405,937,944 \
        & 999,881,065,017,543,109,136,462 \
        - & 317,254,092,617,698,017,425,280 \
        - & 443,761,561,344,388,063,474,665 \
        & 82,327,155,732,241,730,770,824 \
        - & 514,623,285,385,260,545,505,123 \
        - & 1,010,535,343,560,043,404,912,120 \
        - & 357,788,302,700,438,191,196,160 \
        - & 43,808,044,579,418,934,376,632 \
        - & 214,023,244,873,618,345,872,240 \
        & 11,818,373,349,781,028,079 \
        & 347,370,177,721,463,765,064,153
        endarray
        endbmatrix^T
        beginbmatrix
        beginarrayl
        eta^4z^4 \
        eta^5z^4 \
        eta^5z^3 \
        eta^4z^3 \
        eta^3z^3 \
        eta^2z^2 \
        eta^5z^2 \
        eta^4z^2 \
        eta^3z^2 \
        eta^3z \
        eta^5z \
        eta^4z \
        eta z \
        eta^2z \
        eta^2 \
        eta^5 \
        1 \
        eta^4 \
        eta^3 \
        eta
        endarray
        endbmatrix
        &
        beginarrayl
        u(z) = beginbmatrix beginarrayr @hspace0em r & 417,420 \ - & 4,169,121 \ - & 15,571,312 endarrayendbmatrix^T beginbmatrix beginarrayl z^2 \ z \ 1 endarrayendbmatrix\[3em]
        v(z) = beginbmatrix beginarrayr @hspace0em r & 1,546 \ & 3,537 endarrayendbmatrix^T beginbmatrixbeginarrayl z \ 1 endarrayendbmatrix\[3em]
        w(z) = beginbmatrixbeginarrayr @hspace0em r & 3,092 \ & 17,001 endarrayendbmatrix^T beginbmatrixbeginarrayl z \ 1 endarrayendbmatrix \[3em]
        endarray
        endarray
        $$



        PS. Having said that, given the nature of the numbers involved, I would also agree with Mefitico's point of view in the comments, i.e. it's best to create a variable with indices and express via a cleaner expression, and then refer to a table mapping those indices to the actual numbers involved.






        share|improve this answer















        Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:





        where:





        Code:



        $$ f(z)=frac1382,112,640 ; fracg(eta, z)u(z) , v(z) , w(z) $$

        where

        $$
        beginarrayll
        g(eta, z) =
        beginbmatrix
        beginarrayr @hspace0em r
        - & 306,772,802,511,648,469,920 \
        & 762,453,974,480,763,801,600 \
        - & 1,678,626,210,368,271,790,080 \
        - & 28,510,918,043,555,533,736,160 \
        & 11,443,138,641,451,067,779,872 \
        - & 52,164,076,923,190,540,413,504 \
        - & 78,145,258,181,161,076,156,160 \
        - & 211,306,163,712,129,371,808,450 \
        & 228,927,087,397,104,405,937,944 \
        & 999,881,065,017,543,109,136,462 \
        - & 317,254,092,617,698,017,425,280 \
        - & 443,761,561,344,388,063,474,665 \
        & 82,327,155,732,241,730,770,824 \
        - & 514,623,285,385,260,545,505,123 \
        - & 1,010,535,343,560,043,404,912,120 \
        - & 357,788,302,700,438,191,196,160 \
        - & 43,808,044,579,418,934,376,632 \
        - & 214,023,244,873,618,345,872,240 \
        & 11,818,373,349,781,028,079 \
        & 347,370,177,721,463,765,064,153
        endarray
        endbmatrix^T
        beginbmatrix
        beginarrayl
        eta^4z^4 \
        eta^5z^4 \
        eta^5z^3 \
        eta^4z^3 \
        eta^3z^3 \
        eta^2z^2 \
        eta^5z^2 \
        eta^4z^2 \
        eta^3z^2 \
        eta^3z \
        eta^5z \
        eta^4z \
        eta z \
        eta^2z \
        eta^2 \
        eta^5 \
        1 \
        eta^4 \
        eta^3 \
        eta
        endarray
        endbmatrix
        &
        beginarrayl
        u(z) = beginbmatrix beginarrayr @hspace0em r & 417,420 \ - & 4,169,121 \ - & 15,571,312 endarrayendbmatrix^T beginbmatrix beginarrayl z^2 \ z \ 1 endarrayendbmatrix\[3em]
        v(z) = beginbmatrix beginarrayr @hspace0em r & 1,546 \ & 3,537 endarrayendbmatrix^T beginbmatrixbeginarrayl z \ 1 endarrayendbmatrix\[3em]
        w(z) = beginbmatrixbeginarrayr @hspace0em r & 3,092 \ & 17,001 endarrayendbmatrix^T beginbmatrixbeginarrayl z \ 1 endarrayendbmatrix \[3em]
        endarray
        endarray
        $$



        PS. Having said that, given the nature of the numbers involved, I would also agree with Mefitico's point of view in the comments, i.e. it's best to create a variable with indices and express via a cleaner expression, and then refer to a table mapping those indices to the actual numbers involved.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Apr 7 at 15:56

























        answered Apr 5 at 16:10









        Tasos PapastylianouTasos Papastylianou

        362211




        362211







        • 1





          The round brackets in the definitions of $u$, $v$ and $w$ seem superfluous.

          – jochen
          Apr 6 at 11:00






        • 1





          From the point of view of someone wishing or needing to use such a polynomial, it would be helpful to insert breaks in all the long numbers to ease readability.

          – JeremyC
          Apr 7 at 3:49











        • @jochen thanks, updated

          – Tasos Papastylianou
          Apr 7 at 15:51











        • @JeremyC thanks, updated. I went for comma delimiters rather than breaks, as that might have been misleading in the context of matrix notation.

          – Tasos Papastylianou
          Apr 7 at 15:51












        • 1





          The round brackets in the definitions of $u$, $v$ and $w$ seem superfluous.

          – jochen
          Apr 6 at 11:00






        • 1





          From the point of view of someone wishing or needing to use such a polynomial, it would be helpful to insert breaks in all the long numbers to ease readability.

          – JeremyC
          Apr 7 at 3:49











        • @jochen thanks, updated

          – Tasos Papastylianou
          Apr 7 at 15:51











        • @JeremyC thanks, updated. I went for comma delimiters rather than breaks, as that might have been misleading in the context of matrix notation.

          – Tasos Papastylianou
          Apr 7 at 15:51







        1




        1





        The round brackets in the definitions of $u$, $v$ and $w$ seem superfluous.

        – jochen
        Apr 6 at 11:00





        The round brackets in the definitions of $u$, $v$ and $w$ seem superfluous.

        – jochen
        Apr 6 at 11:00




        1




        1





        From the point of view of someone wishing or needing to use such a polynomial, it would be helpful to insert breaks in all the long numbers to ease readability.

        – JeremyC
        Apr 7 at 3:49





        From the point of view of someone wishing or needing to use such a polynomial, it would be helpful to insert breaks in all the long numbers to ease readability.

        – JeremyC
        Apr 7 at 3:49













        @jochen thanks, updated

        – Tasos Papastylianou
        Apr 7 at 15:51





        @jochen thanks, updated

        – Tasos Papastylianou
        Apr 7 at 15:51













        @JeremyC thanks, updated. I went for comma delimiters rather than breaks, as that might have been misleading in the context of matrix notation.

        – Tasos Papastylianou
        Apr 7 at 15:51





        @JeremyC thanks, updated. I went for comma delimiters rather than breaks, as that might have been misleading in the context of matrix notation.

        – Tasos Papastylianou
        Apr 7 at 15:51











        6














        or



        enter image description here



        documentclassarticle
        %usepackageamsmath% Loaded by mathtools
        usepackagemathtools, nccmath
        begindocument
        beginmultline*medmath
        f(z)=frac1382112640
        fracleft[
        beginmultlined
        -306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
        1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
        11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
        78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
        228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
        317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
        82327155732241730770824eta z - 514623285385260545505123eta^2z-\
        1010535343560043404912120eta^2-357788302700438191196160eta^5-\
        43808044579418934376632-214023244873618345872240eta^4+\
        11818373349781028079eta^3+347370177721463765064153eta
        endmultlinedright]
        (417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
        endmultline*





        share|improve this answer



























          6














          or



          enter image description here



          documentclassarticle
          %usepackageamsmath% Loaded by mathtools
          usepackagemathtools, nccmath
          begindocument
          beginmultline*medmath
          f(z)=frac1382112640
          fracleft[
          beginmultlined
          -306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
          1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
          11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
          78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
          228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
          317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
          82327155732241730770824eta z - 514623285385260545505123eta^2z-\
          1010535343560043404912120eta^2-357788302700438191196160eta^5-\
          43808044579418934376632-214023244873618345872240eta^4+\
          11818373349781028079eta^3+347370177721463765064153eta
          endmultlinedright]
          (417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
          endmultline*





          share|improve this answer

























            6












            6








            6







            or



            enter image description here



            documentclassarticle
            %usepackageamsmath% Loaded by mathtools
            usepackagemathtools, nccmath
            begindocument
            beginmultline*medmath
            f(z)=frac1382112640
            fracleft[
            beginmultlined
            -306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
            1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
            11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
            78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
            228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
            317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
            82327155732241730770824eta z - 514623285385260545505123eta^2z-\
            1010535343560043404912120eta^2-357788302700438191196160eta^5-\
            43808044579418934376632-214023244873618345872240eta^4+\
            11818373349781028079eta^3+347370177721463765064153eta
            endmultlinedright]
            (417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
            endmultline*





            share|improve this answer













            or



            enter image description here



            documentclassarticle
            %usepackageamsmath% Loaded by mathtools
            usepackagemathtools, nccmath
            begindocument
            beginmultline*medmath
            f(z)=frac1382112640
            fracleft[
            beginmultlined
            -306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
            1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
            11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
            78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
            228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
            317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
            82327155732241730770824eta z - 514623285385260545505123eta^2z-\
            1010535343560043404912120eta^2-357788302700438191196160eta^5-\
            43808044579418934376632-214023244873618345872240eta^4+\
            11818373349781028079eta^3+347370177721463765064153eta
            endmultlinedright]
            (417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
            endmultline*






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Apr 5 at 7:36









            ZarkoZarko

            130k869170




            130k869170





















                2














                I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.



                documentclassarticle
                %usepackageamsmath% Loaded by mathtools
                usepackagemathtools
                begindocument
                Blah blah
                [f(z)=frac1382112640cdotfracAB]
                where
                [
                arraycolsep=0.5pt
                beginarrayrrllrll
                A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
                &, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
                &, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
                &, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
                &, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
                &, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
                &, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
                &,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
                &, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
                &, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
                endarray
                ]
                and
                [B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
                enddocument


                I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:



                enter image description here






                share|improve this answer



























                  2














                  I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.



                  documentclassarticle
                  %usepackageamsmath% Loaded by mathtools
                  usepackagemathtools
                  begindocument
                  Blah blah
                  [f(z)=frac1382112640cdotfracAB]
                  where
                  [
                  arraycolsep=0.5pt
                  beginarrayrrllrll
                  A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
                  &, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
                  &, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
                  &, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
                  &, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
                  &, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
                  &, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
                  &,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
                  &, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
                  &, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
                  endarray
                  ]
                  and
                  [B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
                  enddocument


                  I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:



                  enter image description here






                  share|improve this answer

























                    2












                    2








                    2







                    I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.



                    documentclassarticle
                    %usepackageamsmath% Loaded by mathtools
                    usepackagemathtools
                    begindocument
                    Blah blah
                    [f(z)=frac1382112640cdotfracAB]
                    where
                    [
                    arraycolsep=0.5pt
                    beginarrayrrllrll
                    A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
                    &, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
                    &, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
                    &, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
                    &, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
                    &, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
                    &, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
                    &,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
                    &, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
                    &, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
                    endarray
                    ]
                    and
                    [B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
                    enddocument


                    I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:



                    enter image description here






                    share|improve this answer













                    I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.



                    documentclassarticle
                    %usepackageamsmath% Loaded by mathtools
                    usepackagemathtools
                    begindocument
                    Blah blah
                    [f(z)=frac1382112640cdotfracAB]
                    where
                    [
                    arraycolsep=0.5pt
                    beginarrayrrllrll
                    A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
                    &, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
                    &, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
                    &, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
                    &, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
                    &, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
                    &, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
                    &,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
                    &, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
                    &, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
                    endarray
                    ]
                    and
                    [B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
                    enddocument


                    I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:



                    enter image description here







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Apr 5 at 10:33









                    flawrflawr

                    527413




                    527413





















                        0














                        I would usually use the package breqn. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn and sansmath in the same document)



                        begindmath*
                        f(z)=frac1382112640times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^-1
                        enddmath*


                        which produces this huge equation



                        IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat version.






                        share|improve this answer



























                          0














                          I would usually use the package breqn. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn and sansmath in the same document)



                          begindmath*
                          f(z)=frac1382112640times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^-1
                          enddmath*


                          which produces this huge equation



                          IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat version.






                          share|improve this answer

























                            0












                            0








                            0







                            I would usually use the package breqn. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn and sansmath in the same document)



                            begindmath*
                            f(z)=frac1382112640times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^-1
                            enddmath*


                            which produces this huge equation



                            IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat version.






                            share|improve this answer













                            I would usually use the package breqn. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn and sansmath in the same document)



                            begindmath*
                            f(z)=frac1382112640times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^-1
                            enddmath*


                            which produces this huge equation



                            IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat version.







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Apr 5 at 13:48









                            PhilipPhilip

                            235




                            235





















                                0














                                Following the original disposition of the function, but using alignat, parenthesis, and fractions to emphasize its different terms.



                                documentclassarticle

                                usepackagemathtools

                                begindocument

                                beginalignat*2
                                & f(z) && = frac1382112640 times left( vphantomfrac1382112640 -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
                                & && -1678626210368271790080 eta^5 z^3 -28510918043555533736160 eta^4 z^3 \[1.5ex]
                                & && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
                                & && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
                                & && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
                                & && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
                                & && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
                                & && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
                                & && -43808044579418934376632 -214023244873618345872240 eta^4 \[1.5ex]
                                & && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantomfrac1382112640 right) \[1.5ex]
                                & && times frac1(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
                                endalignat*

                                enddocument


                                fig






                                share|improve this answer

























                                • Do you think this fits the page margin?

                                  – JouleV
                                  Apr 5 at 9:14











                                • It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.

                                  – Andre
                                  Apr 5 at 9:22












                                • In the original question, the term 417420z^2-4169121z-15571312 is in denominator, not in the numerator as you place it.

                                  – quark67
                                  Apr 7 at 0:32











                                • OK. I will revise this.

                                  – Andre
                                  Apr 7 at 8:37











                                • Revised the members of the last fraction. Also added a line for the last term (which also ensures that the display will fit the margins).

                                  – Andre
                                  Apr 7 at 10:12
















                                0














                                Following the original disposition of the function, but using alignat, parenthesis, and fractions to emphasize its different terms.



                                documentclassarticle

                                usepackagemathtools

                                begindocument

                                beginalignat*2
                                & f(z) && = frac1382112640 times left( vphantomfrac1382112640 -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
                                & && -1678626210368271790080 eta^5 z^3 -28510918043555533736160 eta^4 z^3 \[1.5ex]
                                & && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
                                & && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
                                & && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
                                & && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
                                & && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
                                & && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
                                & && -43808044579418934376632 -214023244873618345872240 eta^4 \[1.5ex]
                                & && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantomfrac1382112640 right) \[1.5ex]
                                & && times frac1(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
                                endalignat*

                                enddocument


                                fig






                                share|improve this answer

























                                • Do you think this fits the page margin?

                                  – JouleV
                                  Apr 5 at 9:14











                                • It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.

                                  – Andre
                                  Apr 5 at 9:22












                                • In the original question, the term 417420z^2-4169121z-15571312 is in denominator, not in the numerator as you place it.

                                  – quark67
                                  Apr 7 at 0:32











                                • OK. I will revise this.

                                  – Andre
                                  Apr 7 at 8:37











                                • Revised the members of the last fraction. Also added a line for the last term (which also ensures that the display will fit the margins).

                                  – Andre
                                  Apr 7 at 10:12














                                0












                                0








                                0







                                Following the original disposition of the function, but using alignat, parenthesis, and fractions to emphasize its different terms.



                                documentclassarticle

                                usepackagemathtools

                                begindocument

                                beginalignat*2
                                & f(z) && = frac1382112640 times left( vphantomfrac1382112640 -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
                                & && -1678626210368271790080 eta^5 z^3 -28510918043555533736160 eta^4 z^3 \[1.5ex]
                                & && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
                                & && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
                                & && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
                                & && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
                                & && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
                                & && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
                                & && -43808044579418934376632 -214023244873618345872240 eta^4 \[1.5ex]
                                & && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantomfrac1382112640 right) \[1.5ex]
                                & && times frac1(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
                                endalignat*

                                enddocument


                                fig






                                share|improve this answer















                                Following the original disposition of the function, but using alignat, parenthesis, and fractions to emphasize its different terms.



                                documentclassarticle

                                usepackagemathtools

                                begindocument

                                beginalignat*2
                                & f(z) && = frac1382112640 times left( vphantomfrac1382112640 -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
                                & && -1678626210368271790080 eta^5 z^3 -28510918043555533736160 eta^4 z^3 \[1.5ex]
                                & && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
                                & && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
                                & && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
                                & && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
                                & && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
                                & && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
                                & && -43808044579418934376632 -214023244873618345872240 eta^4 \[1.5ex]
                                & && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantomfrac1382112640 right) \[1.5ex]
                                & && times frac1(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
                                endalignat*

                                enddocument


                                fig







                                share|improve this answer














                                share|improve this answer



                                share|improve this answer








                                edited Apr 7 at 10:10

























                                answered Apr 5 at 9:11









                                AndreAndre

                                17618




                                17618












                                • Do you think this fits the page margin?

                                  – JouleV
                                  Apr 5 at 9:14











                                • It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.

                                  – Andre
                                  Apr 5 at 9:22












                                • In the original question, the term 417420z^2-4169121z-15571312 is in denominator, not in the numerator as you place it.

                                  – quark67
                                  Apr 7 at 0:32











                                • OK. I will revise this.

                                  – Andre
                                  Apr 7 at 8:37











                                • Revised the members of the last fraction. Also added a line for the last term (which also ensures that the display will fit the margins).

                                  – Andre
                                  Apr 7 at 10:12


















                                • Do you think this fits the page margin?

                                  – JouleV
                                  Apr 5 at 9:14











                                • It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.

                                  – Andre
                                  Apr 5 at 9:22












                                • In the original question, the term 417420z^2-4169121z-15571312 is in denominator, not in the numerator as you place it.

                                  – quark67
                                  Apr 7 at 0:32











                                • OK. I will revise this.

                                  – Andre
                                  Apr 7 at 8:37











                                • Revised the members of the last fraction. Also added a line for the last term (which also ensures that the display will fit the margins).

                                  – Andre
                                  Apr 7 at 10:12

















                                Do you think this fits the page margin?

                                – JouleV
                                Apr 5 at 9:14





                                Do you think this fits the page margin?

                                – JouleV
                                Apr 5 at 9:14













                                It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.

                                – Andre
                                Apr 5 at 9:22






                                It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.

                                – Andre
                                Apr 5 at 9:22














                                In the original question, the term 417420z^2-4169121z-15571312 is in denominator, not in the numerator as you place it.

                                – quark67
                                Apr 7 at 0:32





                                In the original question, the term 417420z^2-4169121z-15571312 is in denominator, not in the numerator as you place it.

                                – quark67
                                Apr 7 at 0:32













                                OK. I will revise this.

                                – Andre
                                Apr 7 at 8:37





                                OK. I will revise this.

                                – Andre
                                Apr 7 at 8:37













                                Revised the members of the last fraction. Also added a line for the last term (which also ensures that the display will fit the margins).

                                – Andre
                                Apr 7 at 10:12






                                Revised the members of the last fraction. Also added a line for the last term (which also ensures that the display will fit the margins).

                                – Andre
                                Apr 7 at 10:12


















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