Remove part of the string in R - dropping some words from it2019 Community Moderator ElectionRemove specific words containing dots from a string
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Remove part of the string in R - dropping some words from it
2019 Community Moderator ElectionRemove specific words containing dots from a string
$begingroup$
I have a column in dataframe which should represent the date, named "taken", and looks like this:
taken
Sat Jan 01 15:30:27 CET 2011
Thu Jan 06 00:54:26 CET 2011
Sat Jan 08 19:49:02 CET 2011
Sun Jan 16 09:57:16 CET 2011
etc (more than 30000 rows)
Now, I need to change class from factor to date, but I haven't found solution for this kind of format. Since it would be easier with date looking like this:
taken
Jan 01 2011
Jan 06 2011
Jan 08 2011
Jan 16 2011
...How could I drop some words from a string (obviously, Mon/Tue... time and CET in this case) to change it into date?
rstudio
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$begingroup$
I have a column in dataframe which should represent the date, named "taken", and looks like this:
taken
Sat Jan 01 15:30:27 CET 2011
Thu Jan 06 00:54:26 CET 2011
Sat Jan 08 19:49:02 CET 2011
Sun Jan 16 09:57:16 CET 2011
etc (more than 30000 rows)
Now, I need to change class from factor to date, but I haven't found solution for this kind of format. Since it would be easier with date looking like this:
taken
Jan 01 2011
Jan 06 2011
Jan 08 2011
Jan 16 2011
...How could I drop some words from a string (obviously, Mon/Tue... time and CET in this case) to change it into date?
rstudio
New contributor
Timorche is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I have a column in dataframe which should represent the date, named "taken", and looks like this:
taken
Sat Jan 01 15:30:27 CET 2011
Thu Jan 06 00:54:26 CET 2011
Sat Jan 08 19:49:02 CET 2011
Sun Jan 16 09:57:16 CET 2011
etc (more than 30000 rows)
Now, I need to change class from factor to date, but I haven't found solution for this kind of format. Since it would be easier with date looking like this:
taken
Jan 01 2011
Jan 06 2011
Jan 08 2011
Jan 16 2011
...How could I drop some words from a string (obviously, Mon/Tue... time and CET in this case) to change it into date?
rstudio
New contributor
Timorche is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I have a column in dataframe which should represent the date, named "taken", and looks like this:
taken
Sat Jan 01 15:30:27 CET 2011
Thu Jan 06 00:54:26 CET 2011
Sat Jan 08 19:49:02 CET 2011
Sun Jan 16 09:57:16 CET 2011
etc (more than 30000 rows)
Now, I need to change class from factor to date, but I haven't found solution for this kind of format. Since it would be easier with date looking like this:
taken
Jan 01 2011
Jan 06 2011
Jan 08 2011
Jan 16 2011
...How could I drop some words from a string (obviously, Mon/Tue... time and CET in this case) to change it into date?
rstudio
rstudio
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Timorche is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
Timorche is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked Mar 20 at 16:17
TimorcheTimorche
1
1
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$begingroup$
I wouldn't use them as time at first place. What would I do:
String <- "Sat Jan 01 15:30:27 CET 2011"
As your dates have same number of elements in them we could just count what part of the String we would like to get.
date <- substr(String, start = 5, stop = 10)
year <- substr(String, start =25 , stop = 28)
Attach them togheter
final <- paste(date,year, sep = " ")
as.Date(final, format = "%b %d %Y")
Little bit more information about as.Date
https://www.statmethods.net/input/dates.html
I hope it helps you :)
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1 Answer
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1 Answer
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active
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$begingroup$
I wouldn't use them as time at first place. What would I do:
String <- "Sat Jan 01 15:30:27 CET 2011"
As your dates have same number of elements in them we could just count what part of the String we would like to get.
date <- substr(String, start = 5, stop = 10)
year <- substr(String, start =25 , stop = 28)
Attach them togheter
final <- paste(date,year, sep = " ")
as.Date(final, format = "%b %d %Y")
Little bit more information about as.Date
https://www.statmethods.net/input/dates.html
I hope it helps you :)
New contributor
Bhji is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I wouldn't use them as time at first place. What would I do:
String <- "Sat Jan 01 15:30:27 CET 2011"
As your dates have same number of elements in them we could just count what part of the String we would like to get.
date <- substr(String, start = 5, stop = 10)
year <- substr(String, start =25 , stop = 28)
Attach them togheter
final <- paste(date,year, sep = " ")
as.Date(final, format = "%b %d %Y")
Little bit more information about as.Date
https://www.statmethods.net/input/dates.html
I hope it helps you :)
New contributor
Bhji is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I wouldn't use them as time at first place. What would I do:
String <- "Sat Jan 01 15:30:27 CET 2011"
As your dates have same number of elements in them we could just count what part of the String we would like to get.
date <- substr(String, start = 5, stop = 10)
year <- substr(String, start =25 , stop = 28)
Attach them togheter
final <- paste(date,year, sep = " ")
as.Date(final, format = "%b %d %Y")
Little bit more information about as.Date
https://www.statmethods.net/input/dates.html
I hope it helps you :)
New contributor
Bhji is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I wouldn't use them as time at first place. What would I do:
String <- "Sat Jan 01 15:30:27 CET 2011"
As your dates have same number of elements in them we could just count what part of the String we would like to get.
date <- substr(String, start = 5, stop = 10)
year <- substr(String, start =25 , stop = 28)
Attach them togheter
final <- paste(date,year, sep = " ")
as.Date(final, format = "%b %d %Y")
Little bit more information about as.Date
https://www.statmethods.net/input/dates.html
I hope it helps you :)
New contributor
Bhji is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Bhji is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
BhjiBhji
111
111
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add a comment |
Timorche is a new contributor. Be nice, and check out our Code of Conduct.
Timorche is a new contributor. Be nice, and check out our Code of Conduct.
Timorche is a new contributor. Be nice, and check out our Code of Conduct.
Timorche is a new contributor. Be nice, and check out our Code of Conduct.
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