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Array of objects return object when condition matched

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7

1

I have an array which have value of id, email and password.

let array = [
 id: hyu, email: a@a.com, password: 123,
 id: rft, email: b@b.com, password: 456,
 id: ght, email: c@c.com, password: 789,
 id: kui, email: d@d.com, password: 679
]

Now I would like to return that object when my condition is matched. For that I created a function using javascript some function but I want to return the object and we know that some function return boolean.

I don't have any idea how to do this.

My code is:

const isEmailExists = (email, array) => 
 return array.some(function(el) 
 return el.email === email;
 );
;

if (isEmailExists("c@c.com", array) == true) 
 // I want to work here with returned objects i.e on success case
 else 
 // error case

Any help is really appreciated

javascript ecmascript-6

share|improve this question

asked Apr 3 at 9:05

AksAks

415

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You're looking for .filter().
  
  – Madara Uchiha♦
  Apr 3 at 9:09
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  Possible duplicate of Javascript: How to filter object array based on attributes?
  
  – Shibon
  Apr 3 at 9:12
  

  
  
  
  

add a comment | 

7

1

I have an array which have value of id, email and password.

let array = [
 id: hyu, email: a@a.com, password: 123,
 id: rft, email: b@b.com, password: 456,
 id: ght, email: c@c.com, password: 789,
 id: kui, email: d@d.com, password: 679
]

Now I would like to return that object when my condition is matched. For that I created a function using javascript some function but I want to return the object and we know that some function return boolean.

I don't have any idea how to do this.

My code is:

const isEmailExists = (email, array) => 
 return array.some(function(el) 
 return el.email === email;
 );
;

if (isEmailExists("c@c.com", array) == true) 
 // I want to work here with returned objects i.e on success case
 else 
 // error case

Any help is really appreciated

javascript ecmascript-6

share|improve this question

asked Apr 3 at 9:05

AksAks

415

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You're looking for .filter().
  
  – Madara Uchiha♦
  Apr 3 at 9:09
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  Possible duplicate of Javascript: How to filter object array based on attributes?
  
  – Shibon
  Apr 3 at 9:12
  

  
  
  
  

add a comment | 

I have an array which have value of id, email and password.

let array = [
 id: hyu, email: a@a.com, password: 123,
 id: rft, email: b@b.com, password: 456,
 id: ght, email: c@c.com, password: 789,
 id: kui, email: d@d.com, password: 679
]

Now I would like to return that object when my condition is matched. For that I created a function using javascript some function but I want to return the object and we know that some function return boolean.

I don't have any idea how to do this.

My code is:

const isEmailExists = (email, array) => 
 return array.some(function(el) 
 return el.email === email;
 );
;

if (isEmailExists("c@c.com", array) == true) 
 // I want to work here with returned objects i.e on success case
 else 
 // error case

Any help is really appreciated

javascript ecmascript-6

share|improve this question

asked Apr 3 at 9:05

AksAks

415

let array = [
 id: hyu, email: a@a.com, password: 123,
 id: rft, email: b@b.com, password: 456,
 id: ght, email: c@c.com, password: 789,
 id: kui, email: d@d.com, password: 679
]

const isEmailExists = (email, array) => 
 return array.some(function(el) 
 return el.email === email;
 );
;

if (isEmailExists("c@c.com", array) == true) 
 // I want to work here with returned objects i.e on success case
 else 
 // error case

share|improve this question

asked Apr 3 at 9:05

AksAks

415

share|improve this question

asked Apr 3 at 9:05

AksAks

415

asked Apr 3 at 9:05

AksAks

415

asked Apr 3 at 9:05

AksAks

415

5 Answers
5

active

oldest

votes

9

You can make use of .filter() and check if the filtered array has a length of more than 0:

let array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

let filtered = array.filter(row => row.email === 'a@a.com');

console.log(filtered);

if (filtered.length > 0) /* mail exists */ 
else /* mail does not exist */ 

share|improve this answer

edited Apr 3 at 10:26

answered Apr 3 at 9:08

Sebastian KaczmarekSebastian Kaczmarek

1,8071025

add a comment | 

9

Assuming the email is unique, you can use find(). This will return null if not email does not exist.

let array = ["id":"hyu","email":"a@a.com","password":123,"id":"rft","email":"b@b.com","password":456,"id":"ght","email":"c@c.com","password":789,"id":"kui","email":"d@d.com","password":679];

const getObject = (email, array) => ;

console.log(getObject("c@c.com", array));

Shorter Version:

const getObject = (email, array) => array.find(el => el.email === email ) || null;

share|improve this answer

answered Apr 3 at 9:10

EddieEddie

20.4k51642

add a comment | 

1

You could take a function and hand over the key and the value and filter the array.

function getObjects(array, key, value) 
 return array.filter(object => object[key] === value);


let array = [ id: 'hyu', email: 'a@a.com', password: 123 , id: 'rft', email: 'b@b.com', password: 456 , id: 'ght', email: 'c@c.com', password: 789 , id: 'kui', email: 'd@d.com', password: 679 ];

console.log(getObjects(array, 'email', 'c@c.com'));

share|improve this answer

answered Apr 3 at 9:09

Nina ScholzNina Scholz

199k15112182

add a comment | 

1

Use find(), not filter(), when you expect zero or one match. find() will return undefined if no match is found and since undefined is falsy and any object is truthy, you can use the return value as a condition for an if clause directly.

const array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

const mail = array.find(row => row.email === 'a@a.com');

if (mail) 
 // Do stuff with mail
 console.log(mail);
 else 
 // Handle error

share|improve this answer

answered Apr 3 at 12:32

JollyJokerJollyJoker

22115

add a comment | 

0

const found = array.find(item => (item.email === 'a@a.com')) || null;
console.log(found);

share|improve this answer

answered Apr 3 at 11:02

0xsr3k4nth0xsr3k4nth

778

add a comment | 

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9

You can make use of .filter() and check if the filtered array has a length of more than 0:

let array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

let filtered = array.filter(row => row.email === 'a@a.com');

console.log(filtered);

if (filtered.length > 0) /* mail exists */ 
else /* mail does not exist */ 

share|improve this answer

edited Apr 3 at 10:26

answered Apr 3 at 9:08

Sebastian KaczmarekSebastian Kaczmarek

1,8071025

add a comment | 

9

You can make use of .filter() and check if the filtered array has a length of more than 0:

let array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

let filtered = array.filter(row => row.email === 'a@a.com');

console.log(filtered);

if (filtered.length > 0) /* mail exists */ 
else /* mail does not exist */ 

share|improve this answer

edited Apr 3 at 10:26

answered Apr 3 at 9:08

Sebastian KaczmarekSebastian Kaczmarek

1,8071025

add a comment | 

You can make use of .filter() and check if the filtered array has a length of more than 0:

let array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

let filtered = array.filter(row => row.email === 'a@a.com');

console.log(filtered);

if (filtered.length > 0) /* mail exists */ 
else /* mail does not exist */ 

share|improve this answer

edited Apr 3 at 10:26

answered Apr 3 at 9:08

Sebastian KaczmarekSebastian Kaczmarek

1,8071025

let array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

let filtered = array.filter(row => row.email === 'a@a.com');

console.log(filtered);

if (filtered.length > 0) /* mail exists */ 
else /* mail does not exist */ 

let array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

let filtered = array.filter(row => row.email === 'a@a.com');

console.log(filtered);

if (filtered.length > 0) /* mail exists */ 
else /* mail does not exist */ 

let array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

let filtered = array.filter(row => row.email === 'a@a.com');

console.log(filtered);

if (filtered.length > 0) /* mail exists */ 
else /* mail does not exist */ 

share|improve this answer

edited Apr 3 at 10:26

answered Apr 3 at 9:08

Sebastian KaczmarekSebastian Kaczmarek

1,8071025

answered Apr 3 at 9:08

Sebastian KaczmarekSebastian Kaczmarek

1,8071025

answered Apr 3 at 9:08

Sebastian KaczmarekSebastian Kaczmarek

1,8071025

9

Assuming the email is unique, you can use find(). This will return null if not email does not exist.

let array = ["id":"hyu","email":"a@a.com","password":123,"id":"rft","email":"b@b.com","password":456,"id":"ght","email":"c@c.com","password":789,"id":"kui","email":"d@d.com","password":679];

const getObject = (email, array) => ;

console.log(getObject("c@c.com", array));

Shorter Version:

const getObject = (email, array) => array.find(el => el.email === email ) || null;

share|improve this answer

answered Apr 3 at 9:10

EddieEddie

20.4k51642

add a comment | 

9

Assuming the email is unique, you can use find(). This will return null if not email does not exist.

let array = ["id":"hyu","email":"a@a.com","password":123,"id":"rft","email":"b@b.com","password":456,"id":"ght","email":"c@c.com","password":789,"id":"kui","email":"d@d.com","password":679];

const getObject = (email, array) => ;

console.log(getObject("c@c.com", array));

Shorter Version:

const getObject = (email, array) => array.find(el => el.email === email ) || null;

share|improve this answer

answered Apr 3 at 9:10

EddieEddie

20.4k51642

add a comment | 

Assuming the email is unique, you can use find(). This will return null if not email does not exist.

let array = ["id":"hyu","email":"a@a.com","password":123,"id":"rft","email":"b@b.com","password":456,"id":"ght","email":"c@c.com","password":789,"id":"kui","email":"d@d.com","password":679];

const getObject = (email, array) => ;

console.log(getObject("c@c.com", array));

Shorter Version:

const getObject = (email, array) => array.find(el => el.email === email ) || null;

share|improve this answer

answered Apr 3 at 9:10

EddieEddie

20.4k51642

let array = ["id":"hyu","email":"a@a.com","password":123,"id":"rft","email":"b@b.com","password":456,"id":"ght","email":"c@c.com","password":789,"id":"kui","email":"d@d.com","password":679];

const getObject = (email, array) => ;

console.log(getObject("c@c.com", array));

const getObject = (email, array) => array.find(el => el.email === email ) || null;

let array = ["id":"hyu","email":"a@a.com","password":123,"id":"rft","email":"b@b.com","password":456,"id":"ght","email":"c@c.com","password":789,"id":"kui","email":"d@d.com","password":679];

const getObject = (email, array) => ;

console.log(getObject("c@c.com", array));

let array = ["id":"hyu","email":"a@a.com","password":123,"id":"rft","email":"b@b.com","password":456,"id":"ght","email":"c@c.com","password":789,"id":"kui","email":"d@d.com","password":679];

const getObject = (email, array) => ;

console.log(getObject("c@c.com", array));

share|improve this answer

answered Apr 3 at 9:10

EddieEddie

20.4k51642

answered Apr 3 at 9:10

EddieEddie

20.4k51642

answered Apr 3 at 9:10

EddieEddie

20.4k51642

1

You could take a function and hand over the key and the value and filter the array.

function getObjects(array, key, value) 
 return array.filter(object => object[key] === value);


let array = [ id: 'hyu', email: 'a@a.com', password: 123 , id: 'rft', email: 'b@b.com', password: 456 , id: 'ght', email: 'c@c.com', password: 789 , id: 'kui', email: 'd@d.com', password: 679 ];

console.log(getObjects(array, 'email', 'c@c.com'));

share|improve this answer

answered Apr 3 at 9:09

Nina ScholzNina Scholz

199k15112182

add a comment | 

1

You could take a function and hand over the key and the value and filter the array.

function getObjects(array, key, value) 
 return array.filter(object => object[key] === value);


let array = [ id: 'hyu', email: 'a@a.com', password: 123 , id: 'rft', email: 'b@b.com', password: 456 , id: 'ght', email: 'c@c.com', password: 789 , id: 'kui', email: 'd@d.com', password: 679 ];

console.log(getObjects(array, 'email', 'c@c.com'));

share|improve this answer

answered Apr 3 at 9:09

Nina ScholzNina Scholz

199k15112182

add a comment | 

You could take a function and hand over the key and the value and filter the array.

function getObjects(array, key, value) 
 return array.filter(object => object[key] === value);


let array = [ id: 'hyu', email: 'a@a.com', password: 123 , id: 'rft', email: 'b@b.com', password: 456 , id: 'ght', email: 'c@c.com', password: 789 , id: 'kui', email: 'd@d.com', password: 679 ];

console.log(getObjects(array, 'email', 'c@c.com'));

share|improve this answer

answered Apr 3 at 9:09

Nina ScholzNina Scholz

199k15112182

function getObjects(array, key, value) 
 return array.filter(object => object[key] === value);


let array = [ id: 'hyu', email: 'a@a.com', password: 123 , id: 'rft', email: 'b@b.com', password: 456 , id: 'ght', email: 'c@c.com', password: 789 , id: 'kui', email: 'd@d.com', password: 679 ];

console.log(getObjects(array, 'email', 'c@c.com'));

function getObjects(array, key, value) 
 return array.filter(object => object[key] === value);


let array = [ id: 'hyu', email: 'a@a.com', password: 123 , id: 'rft', email: 'b@b.com', password: 456 , id: 'ght', email: 'c@c.com', password: 789 , id: 'kui', email: 'd@d.com', password: 679 ];

console.log(getObjects(array, 'email', 'c@c.com'));

function getObjects(array, key, value) 
 return array.filter(object => object[key] === value);


let array = [ id: 'hyu', email: 'a@a.com', password: 123 , id: 'rft', email: 'b@b.com', password: 456 , id: 'ght', email: 'c@c.com', password: 789 , id: 'kui', email: 'd@d.com', password: 679 ];

console.log(getObjects(array, 'email', 'c@c.com'));

share|improve this answer

answered Apr 3 at 9:09

Nina ScholzNina Scholz

199k15112182

answered Apr 3 at 9:09

Nina ScholzNina Scholz

199k15112182

answered Apr 3 at 9:09

Nina ScholzNina Scholz

199k15112182

1

Use find(), not filter(), when you expect zero or one match. find() will return undefined if no match is found and since undefined is falsy and any object is truthy, you can use the return value as a condition for an if clause directly.

const array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

const mail = array.find(row => row.email === 'a@a.com');

if (mail) 
 // Do stuff with mail
 console.log(mail);
 else 
 // Handle error

share|improve this answer

answered Apr 3 at 12:32

JollyJokerJollyJoker

22115

add a comment | 

1

Use find(), not filter(), when you expect zero or one match. find() will return undefined if no match is found and since undefined is falsy and any object is truthy, you can use the return value as a condition for an if clause directly.

const array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

const mail = array.find(row => row.email === 'a@a.com');

if (mail) 
 // Do stuff with mail
 console.log(mail);
 else 
 // Handle error

share|improve this answer

answered Apr 3 at 12:32

JollyJokerJollyJoker

22115

add a comment | 

Use find(), not filter(), when you expect zero or one match. find() will return undefined if no match is found and since undefined is falsy and any object is truthy, you can use the return value as a condition for an if clause directly.

const array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

const mail = array.find(row => row.email === 'a@a.com');

if (mail) 
 // Do stuff with mail
 console.log(mail);
 else 
 // Handle error

share|improve this answer

answered Apr 3 at 12:32

JollyJokerJollyJoker

22115

const array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

const mail = array.find(row => row.email === 'a@a.com');

if (mail) 
 // Do stuff with mail
 console.log(mail);
 else 
 // Handle error

const array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

const mail = array.find(row => row.email === 'a@a.com');

if (mail) 
 // Do stuff with mail
 console.log(mail);
 else 
 // Handle error

const array = [
 id: 'hyu', email: 'a@a.com', password: 123,
 id: 'rft', email: 'b@b.com', password: 456,
 id: 'ght', email: 'c@c.com', password: 789,
 id: 'kui', email: 'd@d.com', password: 679
]

const mail = array.find(row => row.email === 'a@a.com');

if (mail) 
 // Do stuff with mail
 console.log(mail);
 else 
 // Handle error

share|improve this answer

answered Apr 3 at 12:32

JollyJokerJollyJoker

22115

answered Apr 3 at 12:32

JollyJokerJollyJoker

22115

answered Apr 3 at 12:32

JollyJokerJollyJoker

22115

0

const found = array.find(item => (item.email === 'a@a.com')) || null;
console.log(found);

share|improve this answer

answered Apr 3 at 11:02

0xsr3k4nth0xsr3k4nth

778

add a comment | 

0

const found = array.find(item => (item.email === 'a@a.com')) || null;
console.log(found);

share|improve this answer

answered Apr 3 at 11:02

0xsr3k4nth0xsr3k4nth

778

add a comment | 

const found = array.find(item => (item.email === 'a@a.com')) || null;
console.log(found);

share|improve this answer

answered Apr 3 at 11:02

0xsr3k4nth0xsr3k4nth

778

const found = array.find(item => (item.email === 'a@a.com')) || null;
console.log(found);

share|improve this answer

answered Apr 3 at 11:02

0xsr3k4nth0xsr3k4nth

778

answered Apr 3 at 11:02

0xsr3k4nth0xsr3k4nth

778

answered Apr 3 at 11:02

0xsr3k4nth0xsr3k4nth

778