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Matrix using tikz package
aligning a multiline formula with the bullet of itemizeRotate a node but not its content: the case of the ellipse decorationvertical lines in matrix using tikz packageSubequation aligning using matrixNumerical conditional within tikz keys?Missing } inserted when using beginmatrixDrawing this matrix using TikzAlignment for equationsLatex matrix tikzCreating 6x6 matrix using bmatrix
I am working on my dissertation and I have no idea how I should do this in LaTeX.
And the shading definitely is challenging.
I have only been able to do this so far, I am still an amateur at it.
usepackagecolor
newcommandxtimes
newcommandycellcolorgreen
begindocument
beginequation*
left[
beginarrayccc
y & y & y \
& y & y R \
& & y \
endarray
right]left[
beginarrayc
\
a_j \
\
endarray
right]=
endequation*
enddocument
tikz-pgf math-mode equations matrices
New contributor
add a comment |
I am working on my dissertation and I have no idea how I should do this in LaTeX.
And the shading definitely is challenging.
I have only been able to do this so far, I am still an amateur at it.
usepackagecolor
newcommandxtimes
newcommandycellcolorgreen
begindocument
beginequation*
left[
beginarrayccc
y & y & y \
& y & y R \
& & y \
endarray
right]left[
beginarrayc
\
a_j \
\
endarray
right]=
endequation*
enddocument
tikz-pgf math-mode equations matrices
New contributor
add a comment |
I am working on my dissertation and I have no idea how I should do this in LaTeX.
And the shading definitely is challenging.
I have only been able to do this so far, I am still an amateur at it.
usepackagecolor
newcommandxtimes
newcommandycellcolorgreen
begindocument
beginequation*
left[
beginarrayccc
y & y & y \
& y & y R \
& & y \
endarray
right]left[
beginarrayc
\
a_j \
\
endarray
right]=
endequation*
enddocument
tikz-pgf math-mode equations matrices
New contributor
I am working on my dissertation and I have no idea how I should do this in LaTeX.
And the shading definitely is challenging.
I have only been able to do this so far, I am still an amateur at it.
usepackagecolor
newcommandxtimes
newcommandycellcolorgreen
begindocument
beginequation*
left[
beginarrayccc
y & y & y \
& y & y R \
& & y \
endarray
right]left[
beginarrayc
\
a_j \
\
endarray
right]=
endequation*
enddocument
tikz-pgf math-mode equations matrices
tikz-pgf math-mode equations matrices
New contributor
New contributor
edited Mar 17 at 9:34
Tarini Ramsewak
New contributor
asked Mar 17 at 8:25
Tarini RamsewakTarini Ramsewak
384
384
New contributor
New contributor
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
With TikZ matrix
:
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarymatrix, positioning, patterns, backgrounds
tikzset
every matrix/.append style=
matrix of math nodes,
nodes in empty cells,
inner sep=0pt,
outer sep=0pt,
column sep=-pgflinewidth,
row sep=-pgflinewidth,
,
mylargenode/.style=
text centered,
text width=30pt,
text height=20pt,
text depth=10pt,
,
mylongnode/.style=
text centered,
text width=20pt,
text height=40pt,
text depth=30pt,
,
mysmallnode/.style=
text centered,
text width=20pt,
text height=20pt,
text depth=10pt,
,
mylonglargenode/.style=
text centered,
text width=30pt,
text height=40pt,
text depth=30pt,
,
begindocument
With delimiters like in your image:
[
begintikzpicture
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) %
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) \
;
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
% delimiters:
foreach mymatr in A,B,C
draw[very thick] ([xshift=4pt]mymatr.north west) -- (mymatr.north west) -- (mymatr.south west) -- ([xshift=4pt]mymatr.south west);
draw[very thick] ([xshift=-4pt]mymatr.north east) -- (mymatr.north east) -- (mymatr.south east) -- ([xshift=-4pt]mymatr.south east);
endtikzpicture
]
Or with ordinary delimiter:
[
begintikzpicture[
every matrix/.append style=
left delimiter=[,
right delimiter=],
]
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) %
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) \
;
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
endtikzpicture
]
enddocument
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
1
@Sebastiano Thank you!
– CarLaTeX
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
2 days ago
Thank you so much!
– Tarini Ramsewak
2 days ago
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
2 days ago
add a comment |
It is indeed a bit tedious. (EDIT: Fixed the first R
to become math mode, mille grazie to @Sebastiano!)
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypositioning,backgrounds,patterns
begindocument
begintikzpicture
beginscope[local bounding box=mat1]
path node (R0) $R$ foreach X [remember=X as lastX (initially 0)] in
1,...,4
ifnumX=3
node[below right=1.5em of RlastX] (RX) $phantomR$
else
node[below right=1.5em of RlastX] (RX) $R$
fi
;
beginscope[on background layer]
draw[fill=green!70!black]
foreach X in 0,1,2,4
([xshift=-1em]RX.north west) -- ([yshift=-1em]RX.south east)
coordinate(bX)
;
draw[densely dotted] ([xshift=-1em]R3.north west) -- ([yshift=-1em]R3.south east)
coordinate(b3) |- cycle;
endscope
node[pattern=crosshatch,pattern color=purple,anchor=north west,
minimum height=6em] (F) at ([yshift=-1em]R4.south east) $F$;
draw[densely dotted] ([yshift=-1em]R3.south east-|R4.south east)
rectangle (F.east|-R3.north);
foreach X [evaluate=X as Y using int(40+10*X)] in 0,1,2,4
-RX.north);
endscope
path (mat1.south west) -- (mat1.north east)
node[pos=0.3,font=Large] $0$ node[pos=0.7,font=Large] $0$;
draw[thick] ([xshift=0.7em]mat1.north west) -| (mat1.south west) -- ++ (0.7em,0)
([xshift=-0.7em]mat1.north east) -| (mat1.south east) -- ++ (-0.7em,0);
%
beginscope[local bounding box=mat2]
foreach X [remember=X as lastX (initially 0)] in 1,2,3
-RlastX.north) --
([xshift=2.5em]mat1.east
path ([xshift=1em]mat1.east|-R4.north) --
([xshift=2.5em]mat1.east|-b4) node[midway] (aM) $a_M$;
node[below=0.5em of aM] (b) $b$;
endscope
draw[thick] ([xshift=0.5em]mat2.north west) -| (mat2.south west) -- ++
(0.5em,0)
([xshift=-0.5em]mat2.north east) -| (mat2.south east) -- ++ (-0.5em,0);
foreach X in 0,...,4
-bX) -- (mat2.east
%
node[anchor=west] (eq) at (mat2.east|-mat1.center) $=$;
%
beginscope[local bounding box=mat3]
node[pattern=dots,anchor=north west,pattern color=yellow!60!orange,
minimum height=6em] (f) at ([xshift=0.1em]eq.east|-F.north) $f$;
foreach X [remember=X as lastX (initially 0),
evaluate=X as Y using int(30*X+10)] in 1,2,3
fill[yellow!Y] ([xshift=0.1em]eq.east
fill[yellow] ([xshift=0.1em]eq.east|-R4.north) rectangle
(f.east|-b4);
draw[densely dotted] (f.center|-b2) -- (f.center|-b3);
endscope
foreach X in 0,...,4
draw (mat3.west
draw[thick] ([xshift=0.3em]mat3.north west) -| (mat3.south west) -- ++
(0.3em,0)
([xshift=-0.3em]mat3.north east) -| (mat3.south east) -- ++ (-0.3em,0);
endtikzpicture
enddocument
1
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
Mar 17 at 12:50
@Sebastiano Mille grazie!
– marmot
Mar 17 at 14:42
1
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
Mar 17 at 15:06
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
2 days ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
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votes
active
oldest
votes
With TikZ matrix
:
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarymatrix, positioning, patterns, backgrounds
tikzset
every matrix/.append style=
matrix of math nodes,
nodes in empty cells,
inner sep=0pt,
outer sep=0pt,
column sep=-pgflinewidth,
row sep=-pgflinewidth,
,
mylargenode/.style=
text centered,
text width=30pt,
text height=20pt,
text depth=10pt,
,
mylongnode/.style=
text centered,
text width=20pt,
text height=40pt,
text depth=30pt,
,
mysmallnode/.style=
text centered,
text width=20pt,
text height=20pt,
text depth=10pt,
,
mylonglargenode/.style=
text centered,
text width=30pt,
text height=40pt,
text depth=30pt,
,
begindocument
With delimiters like in your image:
[
begintikzpicture
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) %
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) \
;
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
% delimiters:
foreach mymatr in A,B,C
draw[very thick] ([xshift=4pt]mymatr.north west) -- (mymatr.north west) -- (mymatr.south west) -- ([xshift=4pt]mymatr.south west);
draw[very thick] ([xshift=-4pt]mymatr.north east) -- (mymatr.north east) -- (mymatr.south east) -- ([xshift=-4pt]mymatr.south east);
endtikzpicture
]
Or with ordinary delimiter:
[
begintikzpicture[
every matrix/.append style=
left delimiter=[,
right delimiter=],
]
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) %
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) \
;
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
endtikzpicture
]
enddocument
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
1
@Sebastiano Thank you!
– CarLaTeX
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
2 days ago
Thank you so much!
– Tarini Ramsewak
2 days ago
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
2 days ago
add a comment |
With TikZ matrix
:
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarymatrix, positioning, patterns, backgrounds
tikzset
every matrix/.append style=
matrix of math nodes,
nodes in empty cells,
inner sep=0pt,
outer sep=0pt,
column sep=-pgflinewidth,
row sep=-pgflinewidth,
,
mylargenode/.style=
text centered,
text width=30pt,
text height=20pt,
text depth=10pt,
,
mylongnode/.style=
text centered,
text width=20pt,
text height=40pt,
text depth=30pt,
,
mysmallnode/.style=
text centered,
text width=20pt,
text height=20pt,
text depth=10pt,
,
mylonglargenode/.style=
text centered,
text width=30pt,
text height=40pt,
text depth=30pt,
,
begindocument
With delimiters like in your image:
[
begintikzpicture
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) %
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) \
;
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
% delimiters:
foreach mymatr in A,B,C
draw[very thick] ([xshift=4pt]mymatr.north west) -- (mymatr.north west) -- (mymatr.south west) -- ([xshift=4pt]mymatr.south west);
draw[very thick] ([xshift=-4pt]mymatr.north east) -- (mymatr.north east) -- (mymatr.south east) -- ([xshift=-4pt]mymatr.south east);
endtikzpicture
]
Or with ordinary delimiter:
[
begintikzpicture[
every matrix/.append style=
left delimiter=[,
right delimiter=],
]
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) %
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) \
;
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
endtikzpicture
]
enddocument
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
1
@Sebastiano Thank you!
– CarLaTeX
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
2 days ago
Thank you so much!
– Tarini Ramsewak
2 days ago
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
2 days ago
add a comment |
With TikZ matrix
:
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarymatrix, positioning, patterns, backgrounds
tikzset
every matrix/.append style=
matrix of math nodes,
nodes in empty cells,
inner sep=0pt,
outer sep=0pt,
column sep=-pgflinewidth,
row sep=-pgflinewidth,
,
mylargenode/.style=
text centered,
text width=30pt,
text height=20pt,
text depth=10pt,
,
mylongnode/.style=
text centered,
text width=20pt,
text height=40pt,
text depth=30pt,
,
mysmallnode/.style=
text centered,
text width=20pt,
text height=20pt,
text depth=10pt,
,
mylonglargenode/.style=
text centered,
text width=30pt,
text height=40pt,
text depth=30pt,
,
begindocument
With delimiters like in your image:
[
begintikzpicture
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) %
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) \
;
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
% delimiters:
foreach mymatr in A,B,C
draw[very thick] ([xshift=4pt]mymatr.north west) -- (mymatr.north west) -- (mymatr.south west) -- ([xshift=4pt]mymatr.south west);
draw[very thick] ([xshift=-4pt]mymatr.north east) -- (mymatr.north east) -- (mymatr.south east) -- ([xshift=-4pt]mymatr.south east);
endtikzpicture
]
Or with ordinary delimiter:
[
begintikzpicture[
every matrix/.append style=
left delimiter=[,
right delimiter=],
]
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) %
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) \
;
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
endtikzpicture
]
enddocument
With TikZ matrix
:
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarymatrix, positioning, patterns, backgrounds
tikzset
every matrix/.append style=
matrix of math nodes,
nodes in empty cells,
inner sep=0pt,
outer sep=0pt,
column sep=-pgflinewidth,
row sep=-pgflinewidth,
,
mylargenode/.style=
text centered,
text width=30pt,
text height=20pt,
text depth=10pt,
,
mylongnode/.style=
text centered,
text width=20pt,
text height=40pt,
text depth=30pt,
,
mysmallnode/.style=
text centered,
text width=20pt,
text height=20pt,
text depth=10pt,
,
mylonglargenode/.style=
text centered,
text width=30pt,
text height=40pt,
text depth=30pt,
,
begindocument
With delimiters like in your image:
[
begintikzpicture
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) %
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) \
;
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
% delimiters:
foreach mymatr in A,B,C
draw[very thick] ([xshift=4pt]mymatr.north west) -- (mymatr.north west) -- (mymatr.south west) -- ([xshift=4pt]mymatr.south west);
draw[very thick] ([xshift=-4pt]mymatr.north east) -- (mymatr.north east) -- (mymatr.south east) -- ([xshift=-4pt]mymatr.south east);
endtikzpicture
]
Or with ordinary delimiter:
[
begintikzpicture[
every matrix/.append style=
left delimiter=[,
right delimiter=],
]
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) %
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) \
;
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
endtikzpicture
]
enddocument
answered 2 days ago
CarLaTeXCarLaTeX
33.7k551138
33.7k551138
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
1
@Sebastiano Thank you!
– CarLaTeX
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
2 days ago
Thank you so much!
– Tarini Ramsewak
2 days ago
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
2 days ago
add a comment |
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
1
@Sebastiano Thank you!
– CarLaTeX
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
2 days ago
Thank you so much!
– Tarini Ramsewak
2 days ago
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
2 days ago
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
1
1
@Sebastiano Thank you!
– CarLaTeX
2 days ago
@Sebastiano Thank you!
– CarLaTeX
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
2 days ago
Thank you so much!
– Tarini Ramsewak
2 days ago
Thank you so much!
– Tarini Ramsewak
2 days ago
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
2 days ago
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
2 days ago
add a comment |
It is indeed a bit tedious. (EDIT: Fixed the first R
to become math mode, mille grazie to @Sebastiano!)
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypositioning,backgrounds,patterns
begindocument
begintikzpicture
beginscope[local bounding box=mat1]
path node (R0) $R$ foreach X [remember=X as lastX (initially 0)] in
1,...,4
ifnumX=3
node[below right=1.5em of RlastX] (RX) $phantomR$
else
node[below right=1.5em of RlastX] (RX) $R$
fi
;
beginscope[on background layer]
draw[fill=green!70!black]
foreach X in 0,1,2,4
([xshift=-1em]RX.north west) -- ([yshift=-1em]RX.south east)
coordinate(bX)
;
draw[densely dotted] ([xshift=-1em]R3.north west) -- ([yshift=-1em]R3.south east)
coordinate(b3) |- cycle;
endscope
node[pattern=crosshatch,pattern color=purple,anchor=north west,
minimum height=6em] (F) at ([yshift=-1em]R4.south east) $F$;
draw[densely dotted] ([yshift=-1em]R3.south east-|R4.south east)
rectangle (F.east|-R3.north);
foreach X [evaluate=X as Y using int(40+10*X)] in 0,1,2,4
-RX.north);
endscope
path (mat1.south west) -- (mat1.north east)
node[pos=0.3,font=Large] $0$ node[pos=0.7,font=Large] $0$;
draw[thick] ([xshift=0.7em]mat1.north west) -| (mat1.south west) -- ++ (0.7em,0)
([xshift=-0.7em]mat1.north east) -| (mat1.south east) -- ++ (-0.7em,0);
%
beginscope[local bounding box=mat2]
foreach X [remember=X as lastX (initially 0)] in 1,2,3
-RlastX.north) --
([xshift=2.5em]mat1.east
path ([xshift=1em]mat1.east|-R4.north) --
([xshift=2.5em]mat1.east|-b4) node[midway] (aM) $a_M$;
node[below=0.5em of aM] (b) $b$;
endscope
draw[thick] ([xshift=0.5em]mat2.north west) -| (mat2.south west) -- ++
(0.5em,0)
([xshift=-0.5em]mat2.north east) -| (mat2.south east) -- ++ (-0.5em,0);
foreach X in 0,...,4
-bX) -- (mat2.east
%
node[anchor=west] (eq) at (mat2.east|-mat1.center) $=$;
%
beginscope[local bounding box=mat3]
node[pattern=dots,anchor=north west,pattern color=yellow!60!orange,
minimum height=6em] (f) at ([xshift=0.1em]eq.east|-F.north) $f$;
foreach X [remember=X as lastX (initially 0),
evaluate=X as Y using int(30*X+10)] in 1,2,3
fill[yellow!Y] ([xshift=0.1em]eq.east
fill[yellow] ([xshift=0.1em]eq.east|-R4.north) rectangle
(f.east|-b4);
draw[densely dotted] (f.center|-b2) -- (f.center|-b3);
endscope
foreach X in 0,...,4
draw (mat3.west
draw[thick] ([xshift=0.3em]mat3.north west) -| (mat3.south west) -- ++
(0.3em,0)
([xshift=-0.3em]mat3.north east) -| (mat3.south east) -- ++ (-0.3em,0);
endtikzpicture
enddocument
1
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
Mar 17 at 12:50
@Sebastiano Mille grazie!
– marmot
Mar 17 at 14:42
1
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
Mar 17 at 15:06
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
2 days ago
add a comment |
It is indeed a bit tedious. (EDIT: Fixed the first R
to become math mode, mille grazie to @Sebastiano!)
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypositioning,backgrounds,patterns
begindocument
begintikzpicture
beginscope[local bounding box=mat1]
path node (R0) $R$ foreach X [remember=X as lastX (initially 0)] in
1,...,4
ifnumX=3
node[below right=1.5em of RlastX] (RX) $phantomR$
else
node[below right=1.5em of RlastX] (RX) $R$
fi
;
beginscope[on background layer]
draw[fill=green!70!black]
foreach X in 0,1,2,4
([xshift=-1em]RX.north west) -- ([yshift=-1em]RX.south east)
coordinate(bX)
;
draw[densely dotted] ([xshift=-1em]R3.north west) -- ([yshift=-1em]R3.south east)
coordinate(b3) |- cycle;
endscope
node[pattern=crosshatch,pattern color=purple,anchor=north west,
minimum height=6em] (F) at ([yshift=-1em]R4.south east) $F$;
draw[densely dotted] ([yshift=-1em]R3.south east-|R4.south east)
rectangle (F.east|-R3.north);
foreach X [evaluate=X as Y using int(40+10*X)] in 0,1,2,4
-RX.north);
endscope
path (mat1.south west) -- (mat1.north east)
node[pos=0.3,font=Large] $0$ node[pos=0.7,font=Large] $0$;
draw[thick] ([xshift=0.7em]mat1.north west) -| (mat1.south west) -- ++ (0.7em,0)
([xshift=-0.7em]mat1.north east) -| (mat1.south east) -- ++ (-0.7em,0);
%
beginscope[local bounding box=mat2]
foreach X [remember=X as lastX (initially 0)] in 1,2,3
-RlastX.north) --
([xshift=2.5em]mat1.east
path ([xshift=1em]mat1.east|-R4.north) --
([xshift=2.5em]mat1.east|-b4) node[midway] (aM) $a_M$;
node[below=0.5em of aM] (b) $b$;
endscope
draw[thick] ([xshift=0.5em]mat2.north west) -| (mat2.south west) -- ++
(0.5em,0)
([xshift=-0.5em]mat2.north east) -| (mat2.south east) -- ++ (-0.5em,0);
foreach X in 0,...,4
-bX) -- (mat2.east
%
node[anchor=west] (eq) at (mat2.east|-mat1.center) $=$;
%
beginscope[local bounding box=mat3]
node[pattern=dots,anchor=north west,pattern color=yellow!60!orange,
minimum height=6em] (f) at ([xshift=0.1em]eq.east|-F.north) $f$;
foreach X [remember=X as lastX (initially 0),
evaluate=X as Y using int(30*X+10)] in 1,2,3
fill[yellow!Y] ([xshift=0.1em]eq.east
fill[yellow] ([xshift=0.1em]eq.east|-R4.north) rectangle
(f.east|-b4);
draw[densely dotted] (f.center|-b2) -- (f.center|-b3);
endscope
foreach X in 0,...,4
draw (mat3.west
draw[thick] ([xshift=0.3em]mat3.north west) -| (mat3.south west) -- ++
(0.3em,0)
([xshift=-0.3em]mat3.north east) -| (mat3.south east) -- ++ (-0.3em,0);
endtikzpicture
enddocument
1
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
Mar 17 at 12:50
@Sebastiano Mille grazie!
– marmot
Mar 17 at 14:42
1
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
Mar 17 at 15:06
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
2 days ago
add a comment |
It is indeed a bit tedious. (EDIT: Fixed the first R
to become math mode, mille grazie to @Sebastiano!)
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypositioning,backgrounds,patterns
begindocument
begintikzpicture
beginscope[local bounding box=mat1]
path node (R0) $R$ foreach X [remember=X as lastX (initially 0)] in
1,...,4
ifnumX=3
node[below right=1.5em of RlastX] (RX) $phantomR$
else
node[below right=1.5em of RlastX] (RX) $R$
fi
;
beginscope[on background layer]
draw[fill=green!70!black]
foreach X in 0,1,2,4
([xshift=-1em]RX.north west) -- ([yshift=-1em]RX.south east)
coordinate(bX)
;
draw[densely dotted] ([xshift=-1em]R3.north west) -- ([yshift=-1em]R3.south east)
coordinate(b3) |- cycle;
endscope
node[pattern=crosshatch,pattern color=purple,anchor=north west,
minimum height=6em] (F) at ([yshift=-1em]R4.south east) $F$;
draw[densely dotted] ([yshift=-1em]R3.south east-|R4.south east)
rectangle (F.east|-R3.north);
foreach X [evaluate=X as Y using int(40+10*X)] in 0,1,2,4
-RX.north);
endscope
path (mat1.south west) -- (mat1.north east)
node[pos=0.3,font=Large] $0$ node[pos=0.7,font=Large] $0$;
draw[thick] ([xshift=0.7em]mat1.north west) -| (mat1.south west) -- ++ (0.7em,0)
([xshift=-0.7em]mat1.north east) -| (mat1.south east) -- ++ (-0.7em,0);
%
beginscope[local bounding box=mat2]
foreach X [remember=X as lastX (initially 0)] in 1,2,3
-RlastX.north) --
([xshift=2.5em]mat1.east
path ([xshift=1em]mat1.east|-R4.north) --
([xshift=2.5em]mat1.east|-b4) node[midway] (aM) $a_M$;
node[below=0.5em of aM] (b) $b$;
endscope
draw[thick] ([xshift=0.5em]mat2.north west) -| (mat2.south west) -- ++
(0.5em,0)
([xshift=-0.5em]mat2.north east) -| (mat2.south east) -- ++ (-0.5em,0);
foreach X in 0,...,4
-bX) -- (mat2.east
%
node[anchor=west] (eq) at (mat2.east|-mat1.center) $=$;
%
beginscope[local bounding box=mat3]
node[pattern=dots,anchor=north west,pattern color=yellow!60!orange,
minimum height=6em] (f) at ([xshift=0.1em]eq.east|-F.north) $f$;
foreach X [remember=X as lastX (initially 0),
evaluate=X as Y using int(30*X+10)] in 1,2,3
fill[yellow!Y] ([xshift=0.1em]eq.east
fill[yellow] ([xshift=0.1em]eq.east|-R4.north) rectangle
(f.east|-b4);
draw[densely dotted] (f.center|-b2) -- (f.center|-b3);
endscope
foreach X in 0,...,4
draw (mat3.west
draw[thick] ([xshift=0.3em]mat3.north west) -| (mat3.south west) -- ++
(0.3em,0)
([xshift=-0.3em]mat3.north east) -| (mat3.south east) -- ++ (-0.3em,0);
endtikzpicture
enddocument
It is indeed a bit tedious. (EDIT: Fixed the first R
to become math mode, mille grazie to @Sebastiano!)
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypositioning,backgrounds,patterns
begindocument
begintikzpicture
beginscope[local bounding box=mat1]
path node (R0) $R$ foreach X [remember=X as lastX (initially 0)] in
1,...,4
ifnumX=3
node[below right=1.5em of RlastX] (RX) $phantomR$
else
node[below right=1.5em of RlastX] (RX) $R$
fi
;
beginscope[on background layer]
draw[fill=green!70!black]
foreach X in 0,1,2,4
([xshift=-1em]RX.north west) -- ([yshift=-1em]RX.south east)
coordinate(bX)
;
draw[densely dotted] ([xshift=-1em]R3.north west) -- ([yshift=-1em]R3.south east)
coordinate(b3) |- cycle;
endscope
node[pattern=crosshatch,pattern color=purple,anchor=north west,
minimum height=6em] (F) at ([yshift=-1em]R4.south east) $F$;
draw[densely dotted] ([yshift=-1em]R3.south east-|R4.south east)
rectangle (F.east|-R3.north);
foreach X [evaluate=X as Y using int(40+10*X)] in 0,1,2,4
-RX.north);
endscope
path (mat1.south west) -- (mat1.north east)
node[pos=0.3,font=Large] $0$ node[pos=0.7,font=Large] $0$;
draw[thick] ([xshift=0.7em]mat1.north west) -| (mat1.south west) -- ++ (0.7em,0)
([xshift=-0.7em]mat1.north east) -| (mat1.south east) -- ++ (-0.7em,0);
%
beginscope[local bounding box=mat2]
foreach X [remember=X as lastX (initially 0)] in 1,2,3
-RlastX.north) --
([xshift=2.5em]mat1.east
path ([xshift=1em]mat1.east|-R4.north) --
([xshift=2.5em]mat1.east|-b4) node[midway] (aM) $a_M$;
node[below=0.5em of aM] (b) $b$;
endscope
draw[thick] ([xshift=0.5em]mat2.north west) -| (mat2.south west) -- ++
(0.5em,0)
([xshift=-0.5em]mat2.north east) -| (mat2.south east) -- ++ (-0.5em,0);
foreach X in 0,...,4
-bX) -- (mat2.east
%
node[anchor=west] (eq) at (mat2.east|-mat1.center) $=$;
%
beginscope[local bounding box=mat3]
node[pattern=dots,anchor=north west,pattern color=yellow!60!orange,
minimum height=6em] (f) at ([xshift=0.1em]eq.east|-F.north) $f$;
foreach X [remember=X as lastX (initially 0),
evaluate=X as Y using int(30*X+10)] in 1,2,3
fill[yellow!Y] ([xshift=0.1em]eq.east
fill[yellow] ([xshift=0.1em]eq.east|-R4.north) rectangle
(f.east|-b4);
draw[densely dotted] (f.center|-b2) -- (f.center|-b3);
endscope
foreach X in 0,...,4
draw (mat3.west
draw[thick] ([xshift=0.3em]mat3.north west) -| (mat3.south west) -- ++
(0.3em,0)
([xshift=-0.3em]mat3.north east) -| (mat3.south east) -- ++ (-0.3em,0);
endtikzpicture
enddocument
edited Mar 17 at 15:05
answered Mar 17 at 10:47
marmotmarmot
110k5136255
110k5136255
1
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
Mar 17 at 12:50
@Sebastiano Mille grazie!
– marmot
Mar 17 at 14:42
1
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
Mar 17 at 15:06
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
2 days ago
add a comment |
1
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
Mar 17 at 12:50
@Sebastiano Mille grazie!
– marmot
Mar 17 at 14:42
1
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
Mar 17 at 15:06
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
2 days ago
1
1
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
Mar 17 at 12:50
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
Mar 17 at 12:50
@Sebastiano Mille grazie!
– marmot
Mar 17 at 14:42
@Sebastiano Mille grazie!
– marmot
Mar 17 at 14:42
1
1
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
Mar 17 at 15:06
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
Mar 17 at 15:06
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
2 days ago
add a comment |
Tarini Ramsewak is a new contributor. Be nice, and check out our Code of Conduct.
Tarini Ramsewak is a new contributor. Be nice, and check out our Code of Conduct.
Tarini Ramsewak is a new contributor. Be nice, and check out our Code of Conduct.
Tarini Ramsewak is a new contributor. Be nice, and check out our Code of Conduct.
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