Copycat chess is backCopycat Chess (Part 3/3)Copycat Chess (Part 2/3)Copycat Chess (Part 1/3)Chess with symmetric move-squareThe Erasmus rook tourCan you stop the rambling rook?No More Kings puzzleGetting rid of all chess pieces (except the kings) in a sequence consisting only of capturesA Chess Puzzle in ReverseA Battle of Dysfunctional Kings (Chess)The Fastest Queen Trap (Chess)Loser Chess : another proof gameThe Chess 24 GameHow many total checkmates can you possibly make against the enemy king?
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Copycat chess is back
Copycat Chess (Part 3/3)Copycat Chess (Part 2/3)Copycat Chess (Part 1/3)Chess with symmetric move-squareThe Erasmus rook tourCan you stop the rambling rook?No More Kings puzzleGetting rid of all chess pieces (except the kings) in a sequence consisting only of capturesA Chess Puzzle in ReverseA Battle of Dysfunctional Kings (Chess)The Fastest Queen Trap (Chess)Loser Chess : another proof gameThe Chess 24 GameHow many total checkmates can you possibly make against the enemy king?
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This puzzle is inspired by and has similar rules to the series of puzzles by Sleafar.
Definition. A copycat chess opening is a sequence of moves starting from the conventional starting position, where every move by White (including the last one) is copied by Black identically, resulting in a symmetrical position with respect to the mid-horizontal axis. Every move must be legal, but the last move doesn't have to be checkmate, hence the name opening instead of game.
What is the shortest copycat chess opening in which a rook captures another rook?
chess
asked Apr 7 at 23:06
Arnaud MortierArnaud Mortier
2,583828
$endgroup$
add a comment |
$begingroup$
This puzzle is inspired by and has similar rules to the series of puzzles by Sleafar.
Definition. A copycat chess opening is a sequence of moves starting from the conventional starting position, where every move by White (including the last one) is copied by Black identically, resulting in a symmetrical position with respect to the mid-horizontal axis. Every move must be legal, but the last move doesn't have to be checkmate, hence the name opening instead of game.
What is the shortest copycat chess opening in which a rook captures another rook?
chess
asked Apr 7 at 23:06
Arnaud MortierArnaud Mortier
2,583828
$endgroup$
$begingroup$
Does it need to be symmetrical up to the rook capture or after the rook capture?
$endgroup$
– Brandon_J
Apr 7 at 23:10
$begingroup$
@Brandon_J every move, including the last one...
$endgroup$
– Arnaud Mortier
Apr 7 at 23:18
add a comment |
$begingroup$
This puzzle is inspired by and has similar rules to the series of puzzles by Sleafar.
Definition. A copycat chess opening is a sequence of moves starting from the conventional starting position, where every move by White (including the last one) is copied by Black identically, resulting in a symmetrical position with respect to the mid-horizontal axis. Every move must be legal, but the last move doesn't have to be checkmate, hence the name opening instead of game.
What is the shortest copycat chess opening in which a rook captures another rook?
chess
asked Apr 7 at 23:06
Arnaud MortierArnaud Mortier
2,583828
$endgroup$
This puzzle is inspired by and has similar rules to the series of puzzles by Sleafar.
Definition. A copycat chess opening is a sequence of moves starting from the conventional starting position, where every move by White (including the last one) is copied by Black identically, resulting in a symmetrical position with respect to the mid-horizontal axis. Every move must be legal, but the last move doesn't have to be checkmate, hence the name opening instead of game.
What is the shortest copycat chess opening in which a rook captures another rook?
chess
chess
asked Apr 7 at 23:06
Arnaud MortierArnaud Mortier
2,583828
asked Apr 7 at 23:06
Arnaud MortierArnaud Mortier
2,583828
edited Apr 7 at 23:25
Arnaud Mortier
asked Apr 7 at 23:06
Arnaud MortierArnaud Mortier
2,583828
asked Apr 7 at 23:06
Arnaud MortierArnaud Mortier
2,583828
asked Apr 7 at 23:06
Arnaud MortierArnaud Mortier
2,583828
2,583828
$begingroup$
Does it need to be symmetrical up to the rook capture or after the rook capture?
$endgroup$
– Brandon_J
Apr 7 at 23:10
$begingroup$
@Brandon_J every move, including the last one...
$endgroup$
– Arnaud Mortier
Apr 7 at 23:18
add a comment |
$begingroup$
Does it need to be symmetrical up to the rook capture or after the rook capture?
$endgroup$
– Brandon_J
Apr 7 at 23:10
$begingroup$
@Brandon_J every move, including the last one...
$endgroup$
– Arnaud Mortier
Apr 7 at 23:18
$begingroup$
Does it need to be symmetrical up to the rook capture or after the rook capture?
$endgroup$
– Brandon_J
Apr 7 at 23:10
$begingroup$
Does it need to be symmetrical up to the rook capture or after the rook capture?
$endgroup$
– Brandon_J
Apr 7 at 23:10
$begingroup$
@Brandon_J every move, including the last one...
$endgroup$
– Arnaud Mortier
Apr 7 at 23:18
$begingroup$
@Brandon_J every move, including the last one...
$endgroup$
– Arnaud Mortier
Apr 7 at 23:18
add a comment |
5 Answers
5
active
oldest
votes
$begingroup$
How about seven moves each
1) p-a4 p-a5
2) p-b4 p-b5
3) p(b)xp pxp
4) p-a6 p-a3
5) p-a7 p-a2
6) pxN=R pxN=R
7) RxR RxR
answered Apr 7 at 23:21
PenguinoPenguino
7,3072169
$endgroup$
$begingroup$
Made it viewable here: lichess.org/study/CsNAXWW1
$endgroup$
– Matsemann
Apr 9 at 6:20
$begingroup$
A mix of descriptive and algebraic notation
$endgroup$
– trolley813
Apr 9 at 7:13
1
$begingroup$
@trolley813 That's because I am old-school - originally learned P-KR4 etc.
$endgroup$
– Penguino
Apr 9 at 20:27
$begingroup$
@Penguino Here descriptive is even better since you have to write each move only once (e.g. 1. P-QR4 2. P-QKt4 3. KtPxP 4. P-R6 5. P-R7 6. PxKt=R 7. RxR, I probably write it wrong, since in my country DN isn't used at all).
$endgroup$
– trolley813
Apr 11 at 5:56
add a comment |
$begingroup$
I hope this answer doesn't get sniped...
It did get sniped, but @penguino had an answer that I built off of:
1. a4 a5 2. b4 b5 3. bxa5 bxa4 4. a6 a3 5. a7 a2 6. axb8=R axb1=R 7. Rbxa8 Rxa1
Explanation:
We can't have one of white's rooks that's already on the board take one of black's rooks across a file, since that move would not be copyable. Also, it's impossible for the rooks to capture each other along a rank, since that would require the rooks pass each other at some point, which cannot happen as they will mutually block each other each move they make.
The only other way to have a rook takes rook opening would be pawn promotion, whereby the mirrored pawns promote to a rook and then take the already-there rooks. This quickly leads us to the pawns on the a- and b-files (or g- and h-files), and thus, the solution above.
answered Apr 7 at 23:26
PiIsNot3PiIsNot3
2,966541
$endgroup$
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
Apr 7 at 23:27
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
Apr 7 at 23:28
1
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:35
$begingroup$
@ArnaudMortier: for a horizontal rook capture a rook would have to move to the opposite side of the board. This can't be mirrored because the rooks would collide. ie assume no other pieces in the way to move a rook from a1 to a6 is possible but then the opponents rook would need to move from a8 to a3 - impossible due to the rook on a6.
$endgroup$
– Chris
Apr 8 at 11:54
1
$begingroup$
@Chris True. But PilsNot has edited his answer since then to add this point of explanation.
$endgroup$
– Arnaud Mortier
Apr 8 at 11:56
|
show 1 more comment
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Here’s another way, but on the kingside.
1. g4 g5 2. h4 h5 3. gxh5 gxh4 4. h6 h3 5. h7 h2 6. hxg8=R hxg1=R 7. Rhxg1 Rxg8
And while I’m at it, here are the fastest way to do this with all other pieces, minus the kings of course.
Pawns:
1. a4 a5 2. b4 b5 3. bxa5 bxa4
Bishops:
1. b3 b6 2. Bb2 Bb7 3. g3 g6 4. Bg2 Bg7 5. Bxg7 Bxg2
Knights:
1. Nf3 Nf6 2. Ne5 Ne4 3. Nc6 Nc3 4. Nxb8 Nxb1
Queens:
1. b4 b5 2. c4 c5 3. cxb5 cxb4 4. b6 b3 5. b7 b2 6. bxc8=Q bxc1=Q 7. Qdxc1 Qxc8
Now I can say that I have predicted the future! ;¥ ;D
answered Apr 8 at 0:44
Rewan DemontayRewan Demontay
1,062120
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(+1): Wow, I didn't know there could be variations of this puzzle in the way you have shown!
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– Mr Pie
Apr 8 at 1:08
2
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Why thank you! It was a pre-emptive strike by me, seeing how this will become a series for Arnaud Mortier, as he said.
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– Rewan Demontay
Apr 8 at 1:10
1
$begingroup$
Bishops not fastest: 1. b3 b6 2. Ba3 Ba6 3. Bxe7 Bxe2 4. Bxf8 Bxf1.
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– Remellion
Apr 8 at 3:08
1
$begingroup$
It wasn't my intention to make the same puzzle with other pieces. For me the rooks are by far the most interesting because you have to find the trick, otherwise it's not possible (fastest or not).
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– Arnaud Mortier
Apr 8 at 9:44
1
$begingroup$
@trolley813 well, not exactly the same thing: White rooks can't leave the lower half of the board while Black rooks can't leave the upper half. Queens, however, can move diagonally and therefore reach the opposite half of the board easily. The only reason they can't capture another Queen is that there are only two of them. If there were four like the rooks, then you wouldn't need a promotion.
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– Arnaud Mortier
Apr 10 at 21:39
|
show 2 more comments
$begingroup$
Could it be
1. h4 h5
2. g4 g5
3. hxg5 hxg4
4. Rxh8...?
answered Apr 7 at 23:15
El-GuestEl-Guest
22.1k35193
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1
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lol nice answer; beat me to it
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– Brandon_J
Apr 7 at 23:16
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No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
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– El-Guest
Apr 7 at 23:17
1
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I think both of you forgot to read the rules: every move, including the last one... :)
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– Arnaud Mortier
Apr 7 at 23:17
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@Brandon_J this entire puzzling experience has been very meta LOL
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– El-Guest
Apr 7 at 23:17
5
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"I'm So Meta, Even This Acronym" - XKCD
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– Brandon_J
Apr 7 at 23:19
|
show 1 more comment
$begingroup$
Here's
8 moves
lichess study
1. a4 a5 2. b4 b5 3. axb5 axb4 4. Nc3 Nc6 5. b6 b3 6. b7 b2 7. b8=R b1-R 8. Rxb1 Rxb8
answered Apr 7 at 23:16
Brandon_JBrandon_J
3,960447
$endgroup$
$begingroup$
Think I just sniped you, friend!
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– El-Guest
Apr 7 at 23:16
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I think both of you forgot to read the rules: every move, including the last one... :)
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– Arnaud Mortier
Apr 7 at 23:18
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Weeeelll, I'm late to the party again @ArnaudMortier
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– Brandon_J
Apr 7 at 23:27
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@Brandon_J I hope you had fun anyway :)
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– Arnaud Mortier
Apr 7 at 23:28
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
Apr 7 at 23:29
add a comment |
Your Answer
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
How about seven moves each
1) p-a4 p-a5
2) p-b4 p-b5
3) p(b)xp pxp
4) p-a6 p-a3
5) p-a7 p-a2
6) pxN=R pxN=R
7) RxR RxR
answered Apr 7 at 23:21
PenguinoPenguino
7,3072169
$endgroup$
$begingroup$
Made it viewable here: lichess.org/study/CsNAXWW1
$endgroup$
– Matsemann
Apr 9 at 6:20
$begingroup$
A mix of descriptive and algebraic notation
$endgroup$
– trolley813
Apr 9 at 7:13
1
$begingroup$
@trolley813 That's because I am old-school - originally learned P-KR4 etc.
$endgroup$
– Penguino
Apr 9 at 20:27
$begingroup$
@Penguino Here descriptive is even better since you have to write each move only once (e.g. 1. P-QR4 2. P-QKt4 3. KtPxP 4. P-R6 5. P-R7 6. PxKt=R 7. RxR, I probably write it wrong, since in my country DN isn't used at all).
$endgroup$
– trolley813
Apr 11 at 5:56
add a comment |
$begingroup$
How about seven moves each
1) p-a4 p-a5
2) p-b4 p-b5
3) p(b)xp pxp
4) p-a6 p-a3
5) p-a7 p-a2
6) pxN=R pxN=R
7) RxR RxR
answered Apr 7 at 23:21
PenguinoPenguino
7,3072169
$endgroup$
$begingroup$
Made it viewable here: lichess.org/study/CsNAXWW1
$endgroup$
– Matsemann
Apr 9 at 6:20
$begingroup$
A mix of descriptive and algebraic notation
$endgroup$
– trolley813
Apr 9 at 7:13
1
$begingroup$
@trolley813 That's because I am old-school - originally learned P-KR4 etc.
$endgroup$
– Penguino
Apr 9 at 20:27
$begingroup$
@Penguino Here descriptive is even better since you have to write each move only once (e.g. 1. P-QR4 2. P-QKt4 3. KtPxP 4. P-R6 5. P-R7 6. PxKt=R 7. RxR, I probably write it wrong, since in my country DN isn't used at all).
$endgroup$
– trolley813
Apr 11 at 5:56
add a comment |
$begingroup$
How about seven moves each
1) p-a4 p-a5
2) p-b4 p-b5
3) p(b)xp pxp
4) p-a6 p-a3
5) p-a7 p-a2
6) pxN=R pxN=R
7) RxR RxR
answered Apr 7 at 23:21
PenguinoPenguino
7,3072169
$endgroup$
How about seven moves each
1) p-a4 p-a5
2) p-b4 p-b5
3) p(b)xp pxp
4) p-a6 p-a3
5) p-a7 p-a2
6) pxN=R pxN=R
7) RxR RxR
answered Apr 7 at 23:21
PenguinoPenguino
7,3072169
edited Apr 7 at 23:25
answered Apr 7 at 23:21
PenguinoPenguino
7,3072169
answered Apr 7 at 23:21
PenguinoPenguino
7,3072169
answered Apr 7 at 23:21
PenguinoPenguino
7,3072169
7,3072169
$begingroup$
Made it viewable here: lichess.org/study/CsNAXWW1
$endgroup$
– Matsemann
Apr 9 at 6:20
$begingroup$
A mix of descriptive and algebraic notation
$endgroup$
– trolley813
Apr 9 at 7:13
1
$begingroup$
@trolley813 That's because I am old-school - originally learned P-KR4 etc.
$endgroup$
– Penguino
Apr 9 at 20:27
$begingroup$
@Penguino Here descriptive is even better since you have to write each move only once (e.g. 1. P-QR4 2. P-QKt4 3. KtPxP 4. P-R6 5. P-R7 6. PxKt=R 7. RxR, I probably write it wrong, since in my country DN isn't used at all).
$endgroup$
– trolley813
Apr 11 at 5:56
add a comment |
$begingroup$
Made it viewable here: lichess.org/study/CsNAXWW1
$endgroup$
– Matsemann
Apr 9 at 6:20
$begingroup$
A mix of descriptive and algebraic notation
$endgroup$
– trolley813
Apr 9 at 7:13
1
$begingroup$
@trolley813 That's because I am old-school - originally learned P-KR4 etc.
$endgroup$
– Penguino
Apr 9 at 20:27
$begingroup$
@Penguino Here descriptive is even better since you have to write each move only once (e.g. 1. P-QR4 2. P-QKt4 3. KtPxP 4. P-R6 5. P-R7 6. PxKt=R 7. RxR, I probably write it wrong, since in my country DN isn't used at all).
$endgroup$
– trolley813
Apr 11 at 5:56
$begingroup$
Made it viewable here: lichess.org/study/CsNAXWW1
$endgroup$
– Matsemann
Apr 9 at 6:20
$begingroup$
Made it viewable here: lichess.org/study/CsNAXWW1
$endgroup$
– Matsemann
Apr 9 at 6:20
$begingroup$
A mix of descriptive and algebraic notation
$endgroup$
– trolley813
Apr 9 at 7:13
$begingroup$
A mix of descriptive and algebraic notation
$endgroup$
– trolley813
Apr 9 at 7:13
1
1
$begingroup$
@trolley813 That's because I am old-school - originally learned P-KR4 etc.
$endgroup$
– Penguino
Apr 9 at 20:27
$begingroup$
@trolley813 That's because I am old-school - originally learned P-KR4 etc.
$endgroup$
– Penguino
Apr 9 at 20:27
$begingroup$
@Penguino Here descriptive is even better since you have to write each move only once (e.g. 1. P-QR4 2. P-QKt4 3. KtPxP 4. P-R6 5. P-R7 6. PxKt=R 7. RxR, I probably write it wrong, since in my country DN isn't used at all).
$endgroup$
– trolley813
Apr 11 at 5:56
$begingroup$
@Penguino Here descriptive is even better since you have to write each move only once (e.g. 1. P-QR4 2. P-QKt4 3. KtPxP 4. P-R6 5. P-R7 6. PxKt=R 7. RxR, I probably write it wrong, since in my country DN isn't used at all).
$endgroup$
– trolley813
Apr 11 at 5:56
add a comment |
$begingroup$
I hope this answer doesn't get sniped...
It did get sniped, but @penguino had an answer that I built off of:
1. a4 a5 2. b4 b5 3. bxa5 bxa4 4. a6 a3 5. a7 a2 6. axb8=R axb1=R 7. Rbxa8 Rxa1
Explanation:
We can't have one of white's rooks that's already on the board take one of black's rooks across a file, since that move would not be copyable. Also, it's impossible for the rooks to capture each other along a rank, since that would require the rooks pass each other at some point, which cannot happen as they will mutually block each other each move they make.
The only other way to have a rook takes rook opening would be pawn promotion, whereby the mirrored pawns promote to a rook and then take the already-there rooks. This quickly leads us to the pawns on the a- and b-files (or g- and h-files), and thus, the solution above.
answered Apr 7 at 23:26
PiIsNot3PiIsNot3
2,966541
$endgroup$
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
Apr 7 at 23:27
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
Apr 7 at 23:28
1
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:35
$begingroup$
@ArnaudMortier: for a horizontal rook capture a rook would have to move to the opposite side of the board. This can't be mirrored because the rooks would collide. ie assume no other pieces in the way to move a rook from a1 to a6 is possible but then the opponents rook would need to move from a8 to a3 - impossible due to the rook on a6.
$endgroup$
– Chris
Apr 8 at 11:54
1
$begingroup$
@Chris True. But PilsNot has edited his answer since then to add this point of explanation.
$endgroup$
– Arnaud Mortier
Apr 8 at 11:56
|
show 1 more comment
$begingroup$
I hope this answer doesn't get sniped...
It did get sniped, but @penguino had an answer that I built off of:
1. a4 a5 2. b4 b5 3. bxa5 bxa4 4. a6 a3 5. a7 a2 6. axb8=R axb1=R 7. Rbxa8 Rxa1
Explanation:
We can't have one of white's rooks that's already on the board take one of black's rooks across a file, since that move would not be copyable. Also, it's impossible for the rooks to capture each other along a rank, since that would require the rooks pass each other at some point, which cannot happen as they will mutually block each other each move they make.
The only other way to have a rook takes rook opening would be pawn promotion, whereby the mirrored pawns promote to a rook and then take the already-there rooks. This quickly leads us to the pawns on the a- and b-files (or g- and h-files), and thus, the solution above.
answered Apr 7 at 23:26
PiIsNot3PiIsNot3
2,966541
$endgroup$
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
Apr 7 at 23:27
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
Apr 7 at 23:28
1
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:35
$begingroup$
@ArnaudMortier: for a horizontal rook capture a rook would have to move to the opposite side of the board. This can't be mirrored because the rooks would collide. ie assume no other pieces in the way to move a rook from a1 to a6 is possible but then the opponents rook would need to move from a8 to a3 - impossible due to the rook on a6.
$endgroup$
– Chris
Apr 8 at 11:54
1
$begingroup$
@Chris True. But PilsNot has edited his answer since then to add this point of explanation.
$endgroup$
– Arnaud Mortier
Apr 8 at 11:56
|
show 1 more comment
$begingroup$
I hope this answer doesn't get sniped...
It did get sniped, but @penguino had an answer that I built off of:
1. a4 a5 2. b4 b5 3. bxa5 bxa4 4. a6 a3 5. a7 a2 6. axb8=R axb1=R 7. Rbxa8 Rxa1
Explanation:
We can't have one of white's rooks that's already on the board take one of black's rooks across a file, since that move would not be copyable. Also, it's impossible for the rooks to capture each other along a rank, since that would require the rooks pass each other at some point, which cannot happen as they will mutually block each other each move they make.
The only other way to have a rook takes rook opening would be pawn promotion, whereby the mirrored pawns promote to a rook and then take the already-there rooks. This quickly leads us to the pawns on the a- and b-files (or g- and h-files), and thus, the solution above.
answered Apr 7 at 23:26
PiIsNot3PiIsNot3
2,966541
$endgroup$
I hope this answer doesn't get sniped...
It did get sniped, but @penguino had an answer that I built off of:
1. a4 a5 2. b4 b5 3. bxa5 bxa4 4. a6 a3 5. a7 a2 6. axb8=R axb1=R 7. Rbxa8 Rxa1
Explanation:
We can't have one of white's rooks that's already on the board take one of black's rooks across a file, since that move would not be copyable. Also, it's impossible for the rooks to capture each other along a rank, since that would require the rooks pass each other at some point, which cannot happen as they will mutually block each other each move they make.
The only other way to have a rook takes rook opening would be pawn promotion, whereby the mirrored pawns promote to a rook and then take the already-there rooks. This quickly leads us to the pawns on the a- and b-files (or g- and h-files), and thus, the solution above.
answered Apr 7 at 23:26
PiIsNot3PiIsNot3
2,966541
edited Apr 7 at 23:40
answered Apr 7 at 23:26
PiIsNot3PiIsNot3
2,966541
answered Apr 7 at 23:26
PiIsNot3PiIsNot3
2,966541
answered Apr 7 at 23:26
PiIsNot3PiIsNot3
2,966541
2,966541
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
Apr 7 at 23:27
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
Apr 7 at 23:28
1
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:35
$begingroup$
@ArnaudMortier: for a horizontal rook capture a rook would have to move to the opposite side of the board. This can't be mirrored because the rooks would collide. ie assume no other pieces in the way to move a rook from a1 to a6 is possible but then the opponents rook would need to move from a8 to a3 - impossible due to the rook on a6.
$endgroup$
– Chris
Apr 8 at 11:54
1
$begingroup$
@Chris True. But PilsNot has edited his answer since then to add this point of explanation.
$endgroup$
– Arnaud Mortier
Apr 8 at 11:56
|
show 1 more comment
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
Apr 7 at 23:27
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
Apr 7 at 23:28
1
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:35
$begingroup$
@ArnaudMortier: for a horizontal rook capture a rook would have to move to the opposite side of the board. This can't be mirrored because the rooks would collide. ie assume no other pieces in the way to move a rook from a1 to a6 is possible but then the opponents rook would need to move from a8 to a3 - impossible due to the rook on a6.
$endgroup$
– Chris
Apr 8 at 11:54
1
$begingroup$
@Chris True. But PilsNot has edited his answer since then to add this point of explanation.
$endgroup$
– Arnaud Mortier
Apr 8 at 11:56
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
Apr 7 at 23:27
$begingroup$
Yes you did :) +1 though.
$endgroup$
– Arnaud Mortier
Apr 7 at 23:27
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
Apr 7 at 23:28
$begingroup$
Maybe if I added an explanation...
$endgroup$
– PiIsNot3
Apr 7 at 23:28
1
1
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:35
$begingroup$
Regarding your explanation, it's a tiny bit trickier: why couldn't the capture occur horizontally and hence be possible to copy? (with the 4 rooks involved...)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:35
$begingroup$
@ArnaudMortier: for a horizontal rook capture a rook would have to move to the opposite side of the board. This can't be mirrored because the rooks would collide. ie assume no other pieces in the way to move a rook from a1 to a6 is possible but then the opponents rook would need to move from a8 to a3 - impossible due to the rook on a6.
$endgroup$
– Chris
Apr 8 at 11:54
$begingroup$
@ArnaudMortier: for a horizontal rook capture a rook would have to move to the opposite side of the board. This can't be mirrored because the rooks would collide. ie assume no other pieces in the way to move a rook from a1 to a6 is possible but then the opponents rook would need to move from a8 to a3 - impossible due to the rook on a6.
$endgroup$
– Chris
Apr 8 at 11:54
1
1
$begingroup$
@Chris True. But PilsNot has edited his answer since then to add this point of explanation.
$endgroup$
– Arnaud Mortier
Apr 8 at 11:56
$begingroup$
@Chris True. But PilsNot has edited his answer since then to add this point of explanation.
$endgroup$
– Arnaud Mortier
Apr 8 at 11:56
|
show 1 more comment
$begingroup$
Here’s another way, but on the kingside.
1. g4 g5 2. h4 h5 3. gxh5 gxh4 4. h6 h3 5. h7 h2 6. hxg8=R hxg1=R 7. Rhxg1 Rxg8
And while I’m at it, here are the fastest way to do this with all other pieces, minus the kings of course.
Pawns:
1. a4 a5 2. b4 b5 3. bxa5 bxa4
Bishops:
1. b3 b6 2. Bb2 Bb7 3. g3 g6 4. Bg2 Bg7 5. Bxg7 Bxg2
Knights:
1. Nf3 Nf6 2. Ne5 Ne4 3. Nc6 Nc3 4. Nxb8 Nxb1
Queens:
1. b4 b5 2. c4 c5 3. cxb5 cxb4 4. b6 b3 5. b7 b2 6. bxc8=Q bxc1=Q 7. Qdxc1 Qxc8
Now I can say that I have predicted the future! ;¥ ;D
answered Apr 8 at 0:44
Rewan DemontayRewan Demontay
1,062120
$endgroup$
$begingroup$
(+1): Wow, I didn't know there could be variations of this puzzle in the way you have shown!
$endgroup$
– Mr Pie
Apr 8 at 1:08
2
$begingroup$
Why thank you! It was a pre-emptive strike by me, seeing how this will become a series for Arnaud Mortier, as he said.
$endgroup$
– Rewan Demontay
Apr 8 at 1:10
1
$begingroup$
Bishops not fastest: 1. b3 b6 2. Ba3 Ba6 3. Bxe7 Bxe2 4. Bxf8 Bxf1.
$endgroup$
– Remellion
Apr 8 at 3:08
1
$begingroup$
It wasn't my intention to make the same puzzle with other pieces. For me the rooks are by far the most interesting because you have to find the trick, otherwise it's not possible (fastest or not).
$endgroup$
– Arnaud Mortier
Apr 8 at 9:44
1
$begingroup$
@trolley813 well, not exactly the same thing: White rooks can't leave the lower half of the board while Black rooks can't leave the upper half. Queens, however, can move diagonally and therefore reach the opposite half of the board easily. The only reason they can't capture another Queen is that there are only two of them. If there were four like the rooks, then you wouldn't need a promotion.
$endgroup$
– Arnaud Mortier
Apr 10 at 21:39
|
show 2 more comments
$begingroup$
Here’s another way, but on the kingside.
1. g4 g5 2. h4 h5 3. gxh5 gxh4 4. h6 h3 5. h7 h2 6. hxg8=R hxg1=R 7. Rhxg1 Rxg8
And while I’m at it, here are the fastest way to do this with all other pieces, minus the kings of course.
Pawns:
1. a4 a5 2. b4 b5 3. bxa5 bxa4
Bishops:
1. b3 b6 2. Bb2 Bb7 3. g3 g6 4. Bg2 Bg7 5. Bxg7 Bxg2
Knights:
1. Nf3 Nf6 2. Ne5 Ne4 3. Nc6 Nc3 4. Nxb8 Nxb1
Queens:
1. b4 b5 2. c4 c5 3. cxb5 cxb4 4. b6 b3 5. b7 b2 6. bxc8=Q bxc1=Q 7. Qdxc1 Qxc8
Now I can say that I have predicted the future! ;¥ ;D
answered Apr 8 at 0:44
Rewan DemontayRewan Demontay
1,062120
$endgroup$
$begingroup$
(+1): Wow, I didn't know there could be variations of this puzzle in the way you have shown!
$endgroup$
– Mr Pie
Apr 8 at 1:08
2
$begingroup$
Why thank you! It was a pre-emptive strike by me, seeing how this will become a series for Arnaud Mortier, as he said.
$endgroup$
– Rewan Demontay
Apr 8 at 1:10
1
$begingroup$
Bishops not fastest: 1. b3 b6 2. Ba3 Ba6 3. Bxe7 Bxe2 4. Bxf8 Bxf1.
$endgroup$
– Remellion
Apr 8 at 3:08
1
$begingroup$
It wasn't my intention to make the same puzzle with other pieces. For me the rooks are by far the most interesting because you have to find the trick, otherwise it's not possible (fastest or not).
$endgroup$
– Arnaud Mortier
Apr 8 at 9:44
1
$begingroup$
@trolley813 well, not exactly the same thing: White rooks can't leave the lower half of the board while Black rooks can't leave the upper half. Queens, however, can move diagonally and therefore reach the opposite half of the board easily. The only reason they can't capture another Queen is that there are only two of them. If there were four like the rooks, then you wouldn't need a promotion.
$endgroup$
– Arnaud Mortier
Apr 10 at 21:39
|
show 2 more comments
$begingroup$
Here’s another way, but on the kingside.
1. g4 g5 2. h4 h5 3. gxh5 gxh4 4. h6 h3 5. h7 h2 6. hxg8=R hxg1=R 7. Rhxg1 Rxg8
And while I’m at it, here are the fastest way to do this with all other pieces, minus the kings of course.
Pawns:
1. a4 a5 2. b4 b5 3. bxa5 bxa4
Bishops:
1. b3 b6 2. Bb2 Bb7 3. g3 g6 4. Bg2 Bg7 5. Bxg7 Bxg2
Knights:
1. Nf3 Nf6 2. Ne5 Ne4 3. Nc6 Nc3 4. Nxb8 Nxb1
Queens:
1. b4 b5 2. c4 c5 3. cxb5 cxb4 4. b6 b3 5. b7 b2 6. bxc8=Q bxc1=Q 7. Qdxc1 Qxc8
Now I can say that I have predicted the future! ;¥ ;D
answered Apr 8 at 0:44
Rewan DemontayRewan Demontay
1,062120
$endgroup$
Here’s another way, but on the kingside.
1. g4 g5 2. h4 h5 3. gxh5 gxh4 4. h6 h3 5. h7 h2 6. hxg8=R hxg1=R 7. Rhxg1 Rxg8
And while I’m at it, here are the fastest way to do this with all other pieces, minus the kings of course.
Pawns:
1. a4 a5 2. b4 b5 3. bxa5 bxa4
Bishops:
1. b3 b6 2. Bb2 Bb7 3. g3 g6 4. Bg2 Bg7 5. Bxg7 Bxg2
Knights:
1. Nf3 Nf6 2. Ne5 Ne4 3. Nc6 Nc3 4. Nxb8 Nxb1
Queens:
1. b4 b5 2. c4 c5 3. cxb5 cxb4 4. b6 b3 5. b7 b2 6. bxc8=Q bxc1=Q 7. Qdxc1 Qxc8
Now I can say that I have predicted the future! ;¥ ;D
answered Apr 8 at 0:44
Rewan DemontayRewan Demontay
1,062120
edited Apr 8 at 0:55
answered Apr 8 at 0:44
Rewan DemontayRewan Demontay
1,062120
answered Apr 8 at 0:44
Rewan DemontayRewan Demontay
1,062120
answered Apr 8 at 0:44
Rewan DemontayRewan Demontay
1,062120
1,062120
$begingroup$
(+1): Wow, I didn't know there could be variations of this puzzle in the way you have shown!
$endgroup$
– Mr Pie
Apr 8 at 1:08
2
$begingroup$
Why thank you! It was a pre-emptive strike by me, seeing how this will become a series for Arnaud Mortier, as he said.
$endgroup$
– Rewan Demontay
Apr 8 at 1:10
1
$begingroup$
Bishops not fastest: 1. b3 b6 2. Ba3 Ba6 3. Bxe7 Bxe2 4. Bxf8 Bxf1.
$endgroup$
– Remellion
Apr 8 at 3:08
1
$begingroup$
It wasn't my intention to make the same puzzle with other pieces. For me the rooks are by far the most interesting because you have to find the trick, otherwise it's not possible (fastest or not).
$endgroup$
– Arnaud Mortier
Apr 8 at 9:44
1
$begingroup$
@trolley813 well, not exactly the same thing: White rooks can't leave the lower half of the board while Black rooks can't leave the upper half. Queens, however, can move diagonally and therefore reach the opposite half of the board easily. The only reason they can't capture another Queen is that there are only two of them. If there were four like the rooks, then you wouldn't need a promotion.
$endgroup$
– Arnaud Mortier
Apr 10 at 21:39
|
show 2 more comments
$begingroup$
(+1): Wow, I didn't know there could be variations of this puzzle in the way you have shown!
$endgroup$
– Mr Pie
Apr 8 at 1:08
2
$begingroup$
Why thank you! It was a pre-emptive strike by me, seeing how this will become a series for Arnaud Mortier, as he said.
$endgroup$
– Rewan Demontay
Apr 8 at 1:10
1
$begingroup$
Bishops not fastest: 1. b3 b6 2. Ba3 Ba6 3. Bxe7 Bxe2 4. Bxf8 Bxf1.
$endgroup$
– Remellion
Apr 8 at 3:08
1
$begingroup$
It wasn't my intention to make the same puzzle with other pieces. For me the rooks are by far the most interesting because you have to find the trick, otherwise it's not possible (fastest or not).
$endgroup$
– Arnaud Mortier
Apr 8 at 9:44
1
$begingroup$
@trolley813 well, not exactly the same thing: White rooks can't leave the lower half of the board while Black rooks can't leave the upper half. Queens, however, can move diagonally and therefore reach the opposite half of the board easily. The only reason they can't capture another Queen is that there are only two of them. If there were four like the rooks, then you wouldn't need a promotion.
$endgroup$
– Arnaud Mortier
Apr 10 at 21:39
$begingroup$
(+1): Wow, I didn't know there could be variations of this puzzle in the way you have shown!
$endgroup$
– Mr Pie
Apr 8 at 1:08
$begingroup$
(+1): Wow, I didn't know there could be variations of this puzzle in the way you have shown!
$endgroup$
– Mr Pie
Apr 8 at 1:08
2
2
$begingroup$
Why thank you! It was a pre-emptive strike by me, seeing how this will become a series for Arnaud Mortier, as he said.
$endgroup$
– Rewan Demontay
Apr 8 at 1:10
$begingroup$
Why thank you! It was a pre-emptive strike by me, seeing how this will become a series for Arnaud Mortier, as he said.
$endgroup$
– Rewan Demontay
Apr 8 at 1:10
1
1
$begingroup$
Bishops not fastest: 1. b3 b6 2. Ba3 Ba6 3. Bxe7 Bxe2 4. Bxf8 Bxf1.
$endgroup$
– Remellion
Apr 8 at 3:08
$begingroup$
Bishops not fastest: 1. b3 b6 2. Ba3 Ba6 3. Bxe7 Bxe2 4. Bxf8 Bxf1.
$endgroup$
– Remellion
Apr 8 at 3:08
1
1
$begingroup$
It wasn't my intention to make the same puzzle with other pieces. For me the rooks are by far the most interesting because you have to find the trick, otherwise it's not possible (fastest or not).
$endgroup$
– Arnaud Mortier
Apr 8 at 9:44
$begingroup$
It wasn't my intention to make the same puzzle with other pieces. For me the rooks are by far the most interesting because you have to find the trick, otherwise it's not possible (fastest or not).
$endgroup$
– Arnaud Mortier
Apr 8 at 9:44
1
1
$begingroup$
@trolley813 well, not exactly the same thing: White rooks can't leave the lower half of the board while Black rooks can't leave the upper half. Queens, however, can move diagonally and therefore reach the opposite half of the board easily. The only reason they can't capture another Queen is that there are only two of them. If there were four like the rooks, then you wouldn't need a promotion.
$endgroup$
– Arnaud Mortier
Apr 10 at 21:39
$begingroup$
@trolley813 well, not exactly the same thing: White rooks can't leave the lower half of the board while Black rooks can't leave the upper half. Queens, however, can move diagonally and therefore reach the opposite half of the board easily. The only reason they can't capture another Queen is that there are only two of them. If there were four like the rooks, then you wouldn't need a promotion.
$endgroup$
– Arnaud Mortier
Apr 10 at 21:39
|
show 2 more comments
$begingroup$
Could it be
1. h4 h5
2. g4 g5
3. hxg5 hxg4
4. Rxh8...?
answered Apr 7 at 23:15
El-GuestEl-Guest
22.1k35193
$endgroup$
1
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
Apr 7 at 23:16
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
Apr 7 at 23:17
1
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:17
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
Apr 7 at 23:17
5
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
Apr 7 at 23:19
|
show 1 more comment
$begingroup$
Could it be
1. h4 h5
2. g4 g5
3. hxg5 hxg4
4. Rxh8...?
answered Apr 7 at 23:15
El-GuestEl-Guest
22.1k35193
$endgroup$
1
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
Apr 7 at 23:16
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
Apr 7 at 23:17
1
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:17
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
Apr 7 at 23:17
5
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
Apr 7 at 23:19
|
show 1 more comment
$begingroup$
Could it be
1. h4 h5
2. g4 g5
3. hxg5 hxg4
4. Rxh8...?
answered Apr 7 at 23:15
El-GuestEl-Guest
22.1k35193
$endgroup$
Could it be
1. h4 h5
2. g4 g5
3. hxg5 hxg4
4. Rxh8...?
answered Apr 7 at 23:15
El-GuestEl-Guest
22.1k35193
answered Apr 7 at 23:15
El-GuestEl-Guest
22.1k35193
answered Apr 7 at 23:15
El-GuestEl-Guest
22.1k35193
answered Apr 7 at 23:15
El-GuestEl-Guest
22.1k35193
22.1k35193
1
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
Apr 7 at 23:16
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
Apr 7 at 23:17
1
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:17
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
Apr 7 at 23:17
5
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
Apr 7 at 23:19
|
show 1 more comment
1
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
Apr 7 at 23:16
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
Apr 7 at 23:17
1
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:17
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
Apr 7 at 23:17
5
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
Apr 7 at 23:19
1
1
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
Apr 7 at 23:16
$begingroup$
lol nice answer; beat me to it
$endgroup$
– Brandon_J
Apr 7 at 23:16
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
Apr 7 at 23:17
$begingroup$
No idea if it’s right or not but that’s the first thing I thought of haha @Brandon_J
$endgroup$
– El-Guest
Apr 7 at 23:17
1
1
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:17
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:17
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
Apr 7 at 23:17
$begingroup$
@Brandon_J this entire puzzling experience has been very meta LOL
$endgroup$
– El-Guest
Apr 7 at 23:17
5
5
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
Apr 7 at 23:19
$begingroup$
"I'm So Meta, Even This Acronym" - XKCD
$endgroup$
– Brandon_J
Apr 7 at 23:19
|
show 1 more comment
$begingroup$
Here's
8 moves
lichess study
1. a4 a5 2. b4 b5 3. axb5 axb4 4. Nc3 Nc6 5. b6 b3 6. b7 b2 7. b8=R b1-R 8. Rxb1 Rxb8
answered Apr 7 at 23:16
Brandon_JBrandon_J
3,960447
$endgroup$
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
Apr 7 at 23:16
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:18
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
Apr 7 at 23:27
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:28
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
Apr 7 at 23:29
add a comment |
$begingroup$
Here's
8 moves
lichess study
1. a4 a5 2. b4 b5 3. axb5 axb4 4. Nc3 Nc6 5. b6 b3 6. b7 b2 7. b8=R b1-R 8. Rxb1 Rxb8
answered Apr 7 at 23:16
Brandon_JBrandon_J
3,960447
$endgroup$
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
Apr 7 at 23:16
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:18
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
Apr 7 at 23:27
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:28
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
Apr 7 at 23:29
add a comment |
$begingroup$
Here's
8 moves
lichess study
1. a4 a5 2. b4 b5 3. axb5 axb4 4. Nc3 Nc6 5. b6 b3 6. b7 b2 7. b8=R b1-R 8. Rxb1 Rxb8
answered Apr 7 at 23:16
Brandon_JBrandon_J
3,960447
$endgroup$
Here's
8 moves
lichess study
1. a4 a5 2. b4 b5 3. axb5 axb4 4. Nc3 Nc6 5. b6 b3 6. b7 b2 7. b8=R b1-R 8. Rxb1 Rxb8
answered Apr 7 at 23:16
Brandon_JBrandon_J
3,960447
edited Apr 7 at 23:26
answered Apr 7 at 23:16
Brandon_JBrandon_J
3,960447
answered Apr 7 at 23:16
Brandon_JBrandon_J
3,960447
answered Apr 7 at 23:16
Brandon_JBrandon_J
3,960447
3,960447
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
Apr 7 at 23:16
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:18
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
Apr 7 at 23:27
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:28
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
Apr 7 at 23:29
add a comment |
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
Apr 7 at 23:16
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:18
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
Apr 7 at 23:27
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:28
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
Apr 7 at 23:29
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
Apr 7 at 23:16
$begingroup$
Think I just sniped you, friend!
$endgroup$
– El-Guest
Apr 7 at 23:16
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:18
$begingroup$
I think both of you forgot to read the rules: every move, including the last one... :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:18
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
Apr 7 at 23:27
$begingroup$
Weeeelll, I'm late to the party again @ArnaudMortier
$endgroup$
– Brandon_J
Apr 7 at 23:27
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:28
$begingroup$
@Brandon_J I hope you had fun anyway :)
$endgroup$
– Arnaud Mortier
Apr 7 at 23:28
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
Apr 7 at 23:29
$begingroup$
I did. Thanks for the puzzle!
$endgroup$
– Brandon_J
Apr 7 at 23:29
add a comment |
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$begingroup$
Does it need to be symmetrical up to the rook capture or after the rook capture?
$endgroup$
– Brandon_J
Apr 7 at 23:10
$begingroup$
@Brandon_J every move, including the last one...
$endgroup$
– Arnaud Mortier
Apr 7 at 23:18