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What does it mean to take the “average” of two decision trees by 'voting'



2019 Community Moderator ElectionQuestion on decision tree in the book Programming Collective IntelligenceHow do I deal with non-IID data in gradient boosted random forest (for stock market)?what is the difference between “fully developed decision trees” and “shallow decision trees”?How important is lookahead search in decision trees?Machine Learning to Get X, Y Coordinates From Picture of PlotDetecting spammers with artificially generated target classDecision Trees - C4.5 vs CART - rule setsDetails on soft decision treesUsing Decision Trees to interpret good factor values










4












$begingroup$


I have heard, in relation to random forest algorithm, that the algorithm will fit many decision trees and take the average of them by votes. (This is related to bagging as well)



I understand what the average means for something example such as $vecx=[1,2,3], ; barx =2 $. But I don't know what it would mean if I had two decision trees.



Could anyone please provide a simple example / explanation of this averaging process for a couple of decision trees?










share|improve this question









$endgroup$
















    4












    $begingroup$


    I have heard, in relation to random forest algorithm, that the algorithm will fit many decision trees and take the average of them by votes. (This is related to bagging as well)



    I understand what the average means for something example such as $vecx=[1,2,3], ; barx =2 $. But I don't know what it would mean if I had two decision trees.



    Could anyone please provide a simple example / explanation of this averaging process for a couple of decision trees?










    share|improve this question









    $endgroup$














      4












      4








      4


      1



      $begingroup$


      I have heard, in relation to random forest algorithm, that the algorithm will fit many decision trees and take the average of them by votes. (This is related to bagging as well)



      I understand what the average means for something example such as $vecx=[1,2,3], ; barx =2 $. But I don't know what it would mean if I had two decision trees.



      Could anyone please provide a simple example / explanation of this averaging process for a couple of decision trees?










      share|improve this question









      $endgroup$




      I have heard, in relation to random forest algorithm, that the algorithm will fit many decision trees and take the average of them by votes. (This is related to bagging as well)



      I understand what the average means for something example such as $vecx=[1,2,3], ; barx =2 $. But I don't know what it would mean if I had two decision trees.



      Could anyone please provide a simple example / explanation of this averaging process for a couple of decision trees?







      machine-learning random-forest decision-trees






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 30 at 17:19









      baxxbaxx

      1314




      1314




















          1 Answer
          1






          active

          oldest

          votes


















          2












          $begingroup$

          I think that you are mixing together two different things - random forests
          for regression and for classification. Regression means to predict a
          continuous value (number). Random forest can construct multiple regression
          trees, each of which makes a prediction about the number. In that case,
          it is simple to understand. The numerical predictions are averaged to give
          a robust prediction of the true number value.



          However, I think that you are asking about classification - predicting a
          nominal value (also called categorical or factor). In this case, each
          decision tree predicts a category. Usually, it does not make sense to
          talk about averaging categories. Instead, the multiple decision trees
          "vote" - that is one counts how many times each category was predicted
          and takes the category that received the most votes as the prediction.
          There is no averaging, only counting.



          Here is a simple example.



          Data



          V1 V2 V3 Class
          A C E X
          A C F X
          B C F Y
          B D F Y
          B D E X


          Decision Tree 1 uses only feature V1:

          If V1 = A, predict X, otherwise predict Y



          Decision Tree 2 uses only feature V2:

          If V2 = C, predict X, otherwise predict Y



          Decision Tree 3 uses only feature V3:

          If V3 = E, predict X, otherwise predict Y



          Now we want to predict the class of a new point (A, C, F):

          - Decision Tree 1 sees V1 = A and predicts Class=X

          - Decision Tree 2 sees V2 = C and predicts Class=X

          - Decision Tree 3 sees V3 = F and predicts Class=Y

          There were two votes for X and one vote for Y, so the forest predicts X,
          the class that received the majority of the votes.






          share|improve this answer











          $endgroup$












          • $begingroup$
            Some implementations instead average the probability scores across trees, see e.g. scikit-learn.org/stable/modules/ensemble.html#random-forests
            $endgroup$
            – Ben Reiniger
            Apr 3 at 2:44











          Your Answer





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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2












          $begingroup$

          I think that you are mixing together two different things - random forests
          for regression and for classification. Regression means to predict a
          continuous value (number). Random forest can construct multiple regression
          trees, each of which makes a prediction about the number. In that case,
          it is simple to understand. The numerical predictions are averaged to give
          a robust prediction of the true number value.



          However, I think that you are asking about classification - predicting a
          nominal value (also called categorical or factor). In this case, each
          decision tree predicts a category. Usually, it does not make sense to
          talk about averaging categories. Instead, the multiple decision trees
          "vote" - that is one counts how many times each category was predicted
          and takes the category that received the most votes as the prediction.
          There is no averaging, only counting.



          Here is a simple example.



          Data



          V1 V2 V3 Class
          A C E X
          A C F X
          B C F Y
          B D F Y
          B D E X


          Decision Tree 1 uses only feature V1:

          If V1 = A, predict X, otherwise predict Y



          Decision Tree 2 uses only feature V2:

          If V2 = C, predict X, otherwise predict Y



          Decision Tree 3 uses only feature V3:

          If V3 = E, predict X, otherwise predict Y



          Now we want to predict the class of a new point (A, C, F):

          - Decision Tree 1 sees V1 = A and predicts Class=X

          - Decision Tree 2 sees V2 = C and predicts Class=X

          - Decision Tree 3 sees V3 = F and predicts Class=Y

          There were two votes for X and one vote for Y, so the forest predicts X,
          the class that received the majority of the votes.






          share|improve this answer











          $endgroup$












          • $begingroup$
            Some implementations instead average the probability scores across trees, see e.g. scikit-learn.org/stable/modules/ensemble.html#random-forests
            $endgroup$
            – Ben Reiniger
            Apr 3 at 2:44















          2












          $begingroup$

          I think that you are mixing together two different things - random forests
          for regression and for classification. Regression means to predict a
          continuous value (number). Random forest can construct multiple regression
          trees, each of which makes a prediction about the number. In that case,
          it is simple to understand. The numerical predictions are averaged to give
          a robust prediction of the true number value.



          However, I think that you are asking about classification - predicting a
          nominal value (also called categorical or factor). In this case, each
          decision tree predicts a category. Usually, it does not make sense to
          talk about averaging categories. Instead, the multiple decision trees
          "vote" - that is one counts how many times each category was predicted
          and takes the category that received the most votes as the prediction.
          There is no averaging, only counting.



          Here is a simple example.



          Data



          V1 V2 V3 Class
          A C E X
          A C F X
          B C F Y
          B D F Y
          B D E X


          Decision Tree 1 uses only feature V1:

          If V1 = A, predict X, otherwise predict Y



          Decision Tree 2 uses only feature V2:

          If V2 = C, predict X, otherwise predict Y



          Decision Tree 3 uses only feature V3:

          If V3 = E, predict X, otherwise predict Y



          Now we want to predict the class of a new point (A, C, F):

          - Decision Tree 1 sees V1 = A and predicts Class=X

          - Decision Tree 2 sees V2 = C and predicts Class=X

          - Decision Tree 3 sees V3 = F and predicts Class=Y

          There were two votes for X and one vote for Y, so the forest predicts X,
          the class that received the majority of the votes.






          share|improve this answer











          $endgroup$












          • $begingroup$
            Some implementations instead average the probability scores across trees, see e.g. scikit-learn.org/stable/modules/ensemble.html#random-forests
            $endgroup$
            – Ben Reiniger
            Apr 3 at 2:44













          2












          2








          2





          $begingroup$

          I think that you are mixing together two different things - random forests
          for regression and for classification. Regression means to predict a
          continuous value (number). Random forest can construct multiple regression
          trees, each of which makes a prediction about the number. In that case,
          it is simple to understand. The numerical predictions are averaged to give
          a robust prediction of the true number value.



          However, I think that you are asking about classification - predicting a
          nominal value (also called categorical or factor). In this case, each
          decision tree predicts a category. Usually, it does not make sense to
          talk about averaging categories. Instead, the multiple decision trees
          "vote" - that is one counts how many times each category was predicted
          and takes the category that received the most votes as the prediction.
          There is no averaging, only counting.



          Here is a simple example.



          Data



          V1 V2 V3 Class
          A C E X
          A C F X
          B C F Y
          B D F Y
          B D E X


          Decision Tree 1 uses only feature V1:

          If V1 = A, predict X, otherwise predict Y



          Decision Tree 2 uses only feature V2:

          If V2 = C, predict X, otherwise predict Y



          Decision Tree 3 uses only feature V3:

          If V3 = E, predict X, otherwise predict Y



          Now we want to predict the class of a new point (A, C, F):

          - Decision Tree 1 sees V1 = A and predicts Class=X

          - Decision Tree 2 sees V2 = C and predicts Class=X

          - Decision Tree 3 sees V3 = F and predicts Class=Y

          There were two votes for X and one vote for Y, so the forest predicts X,
          the class that received the majority of the votes.






          share|improve this answer











          $endgroup$



          I think that you are mixing together two different things - random forests
          for regression and for classification. Regression means to predict a
          continuous value (number). Random forest can construct multiple regression
          trees, each of which makes a prediction about the number. In that case,
          it is simple to understand. The numerical predictions are averaged to give
          a robust prediction of the true number value.



          However, I think that you are asking about classification - predicting a
          nominal value (also called categorical or factor). In this case, each
          decision tree predicts a category. Usually, it does not make sense to
          talk about averaging categories. Instead, the multiple decision trees
          "vote" - that is one counts how many times each category was predicted
          and takes the category that received the most votes as the prediction.
          There is no averaging, only counting.



          Here is a simple example.



          Data



          V1 V2 V3 Class
          A C E X
          A C F X
          B C F Y
          B D F Y
          B D E X


          Decision Tree 1 uses only feature V1:

          If V1 = A, predict X, otherwise predict Y



          Decision Tree 2 uses only feature V2:

          If V2 = C, predict X, otherwise predict Y



          Decision Tree 3 uses only feature V3:

          If V3 = E, predict X, otherwise predict Y



          Now we want to predict the class of a new point (A, C, F):

          - Decision Tree 1 sees V1 = A and predicts Class=X

          - Decision Tree 2 sees V2 = C and predicts Class=X

          - Decision Tree 3 sees V3 = F and predicts Class=Y

          There were two votes for X and one vote for Y, so the forest predicts X,
          the class that received the majority of the votes.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 31 at 9:40









          Esmailian

          2,680318




          2,680318










          answered Mar 31 at 0:56









          G5WG5W

          217310




          217310











          • $begingroup$
            Some implementations instead average the probability scores across trees, see e.g. scikit-learn.org/stable/modules/ensemble.html#random-forests
            $endgroup$
            – Ben Reiniger
            Apr 3 at 2:44
















          • $begingroup$
            Some implementations instead average the probability scores across trees, see e.g. scikit-learn.org/stable/modules/ensemble.html#random-forests
            $endgroup$
            – Ben Reiniger
            Apr 3 at 2:44















          $begingroup$
          Some implementations instead average the probability scores across trees, see e.g. scikit-learn.org/stable/modules/ensemble.html#random-forests
          $endgroup$
          – Ben Reiniger
          Apr 3 at 2:44




          $begingroup$
          Some implementations instead average the probability scores across trees, see e.g. scikit-learn.org/stable/modules/ensemble.html#random-forests
          $endgroup$
          – Ben Reiniger
          Apr 3 at 2:44

















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