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Problem with FindRoot


Problem with FindRoot applied to functionsFindRoot with GradFindRoot with NIntegrate giving errorsProblem with FindRoot + NDSolve + InterpolatingFunctionDomainProblem using ConstantArray in FindRootProblem with FindRoot outputError to converge NIntegrate with FindRootA difficult problem about the “FindRoot”A problem with FindRootProblem with FindRoot, NIntegrate, and ImplicitRegion













2












$begingroup$


Maxwell Construction is just integral of area and finding root to find vapor pressure.



This must be exactly the same where Gibbs energy graph cross at a point i found it p = 0.81.



The problem my areadifferential doesn't work properly to return a value p=0.81;



What mistake i have done in coding!?



t = 0.95; 

p[v_] := (8*t)/(3*v - 1) - 3/v^2;

Plot[p[v], v, 0.5, 3, PlotRange -> 0, 3, 0.6, 1, AxesLabel -> V/Vc, P/Pc]


g[v_] := (-t)*Log[3*v - 1] + 0.95/(3*v - 1) - 9/(4*v);

ParametricPlot[p[v],g[v],v,.65,2.25,AxesLabel->P/Pc,G/NKT,
PlotLabel->"Gibbs Free Energy Vs. P/Pc"]


That's Return pressure p=P/Pc=0.81 in plot which is correct



enter image description here



This is the error Maxwell Construction "area differential" Part



pint[v_] := (8/3)*t*Log[3*v - 1] + 3/v;

areadifferential[p0_, v1guess_, v2guess_] :=
(v1 = FindRoot[p[v] == p0, v, v1guess][[1,2]];
v2 = FindRoot[p[v] == p0, v, v2guess][[1,2]];
pint[v2] - pint[v1] - p0*(v2 - v1))

FindRoot[areadifferential[p0, 0.7, 2] == 0, p0, 0.8, 0.82]









share|improve this question









New contributor




Alrubaie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$
















    2












    $begingroup$


    Maxwell Construction is just integral of area and finding root to find vapor pressure.



    This must be exactly the same where Gibbs energy graph cross at a point i found it p = 0.81.



    The problem my areadifferential doesn't work properly to return a value p=0.81;



    What mistake i have done in coding!?



    t = 0.95; 

    p[v_] := (8*t)/(3*v - 1) - 3/v^2;

    Plot[p[v], v, 0.5, 3, PlotRange -> 0, 3, 0.6, 1, AxesLabel -> V/Vc, P/Pc]


    g[v_] := (-t)*Log[3*v - 1] + 0.95/(3*v - 1) - 9/(4*v);

    ParametricPlot[p[v],g[v],v,.65,2.25,AxesLabel->P/Pc,G/NKT,
    PlotLabel->"Gibbs Free Energy Vs. P/Pc"]


    That's Return pressure p=P/Pc=0.81 in plot which is correct



    enter image description here



    This is the error Maxwell Construction "area differential" Part



    pint[v_] := (8/3)*t*Log[3*v - 1] + 3/v;

    areadifferential[p0_, v1guess_, v2guess_] :=
    (v1 = FindRoot[p[v] == p0, v, v1guess][[1,2]];
    v2 = FindRoot[p[v] == p0, v, v2guess][[1,2]];
    pint[v2] - pint[v1] - p0*(v2 - v1))

    FindRoot[areadifferential[p0, 0.7, 2] == 0, p0, 0.8, 0.82]









    share|improve this question









    New contributor




    Alrubaie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      2












      2








      2





      $begingroup$


      Maxwell Construction is just integral of area and finding root to find vapor pressure.



      This must be exactly the same where Gibbs energy graph cross at a point i found it p = 0.81.



      The problem my areadifferential doesn't work properly to return a value p=0.81;



      What mistake i have done in coding!?



      t = 0.95; 

      p[v_] := (8*t)/(3*v - 1) - 3/v^2;

      Plot[p[v], v, 0.5, 3, PlotRange -> 0, 3, 0.6, 1, AxesLabel -> V/Vc, P/Pc]


      g[v_] := (-t)*Log[3*v - 1] + 0.95/(3*v - 1) - 9/(4*v);

      ParametricPlot[p[v],g[v],v,.65,2.25,AxesLabel->P/Pc,G/NKT,
      PlotLabel->"Gibbs Free Energy Vs. P/Pc"]


      That's Return pressure p=P/Pc=0.81 in plot which is correct



      enter image description here



      This is the error Maxwell Construction "area differential" Part



      pint[v_] := (8/3)*t*Log[3*v - 1] + 3/v;

      areadifferential[p0_, v1guess_, v2guess_] :=
      (v1 = FindRoot[p[v] == p0, v, v1guess][[1,2]];
      v2 = FindRoot[p[v] == p0, v, v2guess][[1,2]];
      pint[v2] - pint[v1] - p0*(v2 - v1))

      FindRoot[areadifferential[p0, 0.7, 2] == 0, p0, 0.8, 0.82]









      share|improve this question









      New contributor




      Alrubaie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      Maxwell Construction is just integral of area and finding root to find vapor pressure.



      This must be exactly the same where Gibbs energy graph cross at a point i found it p = 0.81.



      The problem my areadifferential doesn't work properly to return a value p=0.81;



      What mistake i have done in coding!?



      t = 0.95; 

      p[v_] := (8*t)/(3*v - 1) - 3/v^2;

      Plot[p[v], v, 0.5, 3, PlotRange -> 0, 3, 0.6, 1, AxesLabel -> V/Vc, P/Pc]


      g[v_] := (-t)*Log[3*v - 1] + 0.95/(3*v - 1) - 9/(4*v);

      ParametricPlot[p[v],g[v],v,.65,2.25,AxesLabel->P/Pc,G/NKT,
      PlotLabel->"Gibbs Free Energy Vs. P/Pc"]


      That's Return pressure p=P/Pc=0.81 in plot which is correct



      enter image description here



      This is the error Maxwell Construction "area differential" Part



      pint[v_] := (8/3)*t*Log[3*v - 1] + 3/v;

      areadifferential[p0_, v1guess_, v2guess_] :=
      (v1 = FindRoot[p[v] == p0, v, v1guess][[1,2]];
      v2 = FindRoot[p[v] == p0, v, v2guess][[1,2]];
      pint[v2] - pint[v1] - p0*(v2 - v1))

      FindRoot[areadifferential[p0, 0.7, 2] == 0, p0, 0.8, 0.82]






      equation-solving numerical-integration differentials






      share|improve this question









      New contributor




      Alrubaie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      Alrubaie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      share|improve this question




      share|improve this question








      edited 3 hours ago









      user64494

      3,51811021




      3,51811021






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      asked 4 hours ago









      AlrubaieAlrubaie

      438




      438




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      New contributor





      Alrubaie is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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          1 Answer
          1






          active

          oldest

          votes


















          3












          $begingroup$

          Good job on describing your problem.



          Copying your definitions from your question



          p[v_] := (8 t)/(3 v - 1) - 3/v^2
          g[v_] := t/(3 v - 1) - t Log[-1 + 3 v] - 9/(4 v)
          pint[v_] := 8/3 t Log[-1 + 3 v] + 3/v
          t = 0.95


          I found the value 0.81188 to be the value that minimized your areadifferential function (shown at the bottom).



          Look at the plot of P/Pc vs V/Vc and note the three points corresponding to three different V/Vc values resulting in p[v] = 0.8118.



          Module[

          v1 = v /. FindRoot[p[v] == 0.8118, v, 0.5],
          p1,
          v2 = v /. FindRoot[p[v] == 0.8118, v, 1],
          p2,
          v3 = v /. FindRoot[p[v] == 0.8118, v, 2],
          p3
          ,
          p1 = p[v1];
          p2 = p[v2];
          p3 = p[v3];
          Show[
          Plot[p[v], v, 0.65, 2.25, PlotRange -> 0, 3, 0.6, 1,
          AxesLabel -> "V/Vc", "P/Pc"],
          Graphics[

          PointSize[0.03],
          Red,
          Point[v1, p1],
          Green,
          Point[v2, p2],
          Black,
          Point[v3, p3]

          ]
          ]
          ]


          Mathematica graphics



          The problem that you are experiencing is because the value of 0.7 for v1guess is just to the right of the valley so it converges on the wrong point (i.e., the green point).



          Change v1guess to 0.5 and you will be fine, it will converge on the red point. Using v2guess of 2.0 works fine causing convergence on the black point.



          I slightly modified the areadifferential function to use Module rather than parenthesis. One needs to constrain the input arguments to be numeric so FindRoot doesn't complain (FindFoot first tries to work with symbolic arguments which doesn't work with your problem).



          areadifferential[
          p0_?NumericQ,
          v1guess_?NumericQ,
          v2guess_?NumericQ] := Module[

          v1 = FindRoot[p[v] == p0, v, v1guess][[1, 2]],
          v2 = FindRoot[p[v] == p0, v, v2guess][[1, 2]]
          ,
          pint[v2] - pint[v1] - p0*(v2 - v1)
          ]


          and then



          FindRoot[areadifferential[p0, 0.5, 2] == 0, p0, 0.8, 0.82]
          (* p0 -> 0.811879 *)





          share|improve this answer









          $endgroup$












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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3












            $begingroup$

            Good job on describing your problem.



            Copying your definitions from your question



            p[v_] := (8 t)/(3 v - 1) - 3/v^2
            g[v_] := t/(3 v - 1) - t Log[-1 + 3 v] - 9/(4 v)
            pint[v_] := 8/3 t Log[-1 + 3 v] + 3/v
            t = 0.95


            I found the value 0.81188 to be the value that minimized your areadifferential function (shown at the bottom).



            Look at the plot of P/Pc vs V/Vc and note the three points corresponding to three different V/Vc values resulting in p[v] = 0.8118.



            Module[

            v1 = v /. FindRoot[p[v] == 0.8118, v, 0.5],
            p1,
            v2 = v /. FindRoot[p[v] == 0.8118, v, 1],
            p2,
            v3 = v /. FindRoot[p[v] == 0.8118, v, 2],
            p3
            ,
            p1 = p[v1];
            p2 = p[v2];
            p3 = p[v3];
            Show[
            Plot[p[v], v, 0.65, 2.25, PlotRange -> 0, 3, 0.6, 1,
            AxesLabel -> "V/Vc", "P/Pc"],
            Graphics[

            PointSize[0.03],
            Red,
            Point[v1, p1],
            Green,
            Point[v2, p2],
            Black,
            Point[v3, p3]

            ]
            ]
            ]


            Mathematica graphics



            The problem that you are experiencing is because the value of 0.7 for v1guess is just to the right of the valley so it converges on the wrong point (i.e., the green point).



            Change v1guess to 0.5 and you will be fine, it will converge on the red point. Using v2guess of 2.0 works fine causing convergence on the black point.



            I slightly modified the areadifferential function to use Module rather than parenthesis. One needs to constrain the input arguments to be numeric so FindRoot doesn't complain (FindFoot first tries to work with symbolic arguments which doesn't work with your problem).



            areadifferential[
            p0_?NumericQ,
            v1guess_?NumericQ,
            v2guess_?NumericQ] := Module[

            v1 = FindRoot[p[v] == p0, v, v1guess][[1, 2]],
            v2 = FindRoot[p[v] == p0, v, v2guess][[1, 2]]
            ,
            pint[v2] - pint[v1] - p0*(v2 - v1)
            ]


            and then



            FindRoot[areadifferential[p0, 0.5, 2] == 0, p0, 0.8, 0.82]
            (* p0 -> 0.811879 *)





            share|improve this answer









            $endgroup$

















              3












              $begingroup$

              Good job on describing your problem.



              Copying your definitions from your question



              p[v_] := (8 t)/(3 v - 1) - 3/v^2
              g[v_] := t/(3 v - 1) - t Log[-1 + 3 v] - 9/(4 v)
              pint[v_] := 8/3 t Log[-1 + 3 v] + 3/v
              t = 0.95


              I found the value 0.81188 to be the value that minimized your areadifferential function (shown at the bottom).



              Look at the plot of P/Pc vs V/Vc and note the three points corresponding to three different V/Vc values resulting in p[v] = 0.8118.



              Module[

              v1 = v /. FindRoot[p[v] == 0.8118, v, 0.5],
              p1,
              v2 = v /. FindRoot[p[v] == 0.8118, v, 1],
              p2,
              v3 = v /. FindRoot[p[v] == 0.8118, v, 2],
              p3
              ,
              p1 = p[v1];
              p2 = p[v2];
              p3 = p[v3];
              Show[
              Plot[p[v], v, 0.65, 2.25, PlotRange -> 0, 3, 0.6, 1,
              AxesLabel -> "V/Vc", "P/Pc"],
              Graphics[

              PointSize[0.03],
              Red,
              Point[v1, p1],
              Green,
              Point[v2, p2],
              Black,
              Point[v3, p3]

              ]
              ]
              ]


              Mathematica graphics



              The problem that you are experiencing is because the value of 0.7 for v1guess is just to the right of the valley so it converges on the wrong point (i.e., the green point).



              Change v1guess to 0.5 and you will be fine, it will converge on the red point. Using v2guess of 2.0 works fine causing convergence on the black point.



              I slightly modified the areadifferential function to use Module rather than parenthesis. One needs to constrain the input arguments to be numeric so FindRoot doesn't complain (FindFoot first tries to work with symbolic arguments which doesn't work with your problem).



              areadifferential[
              p0_?NumericQ,
              v1guess_?NumericQ,
              v2guess_?NumericQ] := Module[

              v1 = FindRoot[p[v] == p0, v, v1guess][[1, 2]],
              v2 = FindRoot[p[v] == p0, v, v2guess][[1, 2]]
              ,
              pint[v2] - pint[v1] - p0*(v2 - v1)
              ]


              and then



              FindRoot[areadifferential[p0, 0.5, 2] == 0, p0, 0.8, 0.82]
              (* p0 -> 0.811879 *)





              share|improve this answer









              $endgroup$















                3












                3








                3





                $begingroup$

                Good job on describing your problem.



                Copying your definitions from your question



                p[v_] := (8 t)/(3 v - 1) - 3/v^2
                g[v_] := t/(3 v - 1) - t Log[-1 + 3 v] - 9/(4 v)
                pint[v_] := 8/3 t Log[-1 + 3 v] + 3/v
                t = 0.95


                I found the value 0.81188 to be the value that minimized your areadifferential function (shown at the bottom).



                Look at the plot of P/Pc vs V/Vc and note the three points corresponding to three different V/Vc values resulting in p[v] = 0.8118.



                Module[

                v1 = v /. FindRoot[p[v] == 0.8118, v, 0.5],
                p1,
                v2 = v /. FindRoot[p[v] == 0.8118, v, 1],
                p2,
                v3 = v /. FindRoot[p[v] == 0.8118, v, 2],
                p3
                ,
                p1 = p[v1];
                p2 = p[v2];
                p3 = p[v3];
                Show[
                Plot[p[v], v, 0.65, 2.25, PlotRange -> 0, 3, 0.6, 1,
                AxesLabel -> "V/Vc", "P/Pc"],
                Graphics[

                PointSize[0.03],
                Red,
                Point[v1, p1],
                Green,
                Point[v2, p2],
                Black,
                Point[v3, p3]

                ]
                ]
                ]


                Mathematica graphics



                The problem that you are experiencing is because the value of 0.7 for v1guess is just to the right of the valley so it converges on the wrong point (i.e., the green point).



                Change v1guess to 0.5 and you will be fine, it will converge on the red point. Using v2guess of 2.0 works fine causing convergence on the black point.



                I slightly modified the areadifferential function to use Module rather than parenthesis. One needs to constrain the input arguments to be numeric so FindRoot doesn't complain (FindFoot first tries to work with symbolic arguments which doesn't work with your problem).



                areadifferential[
                p0_?NumericQ,
                v1guess_?NumericQ,
                v2guess_?NumericQ] := Module[

                v1 = FindRoot[p[v] == p0, v, v1guess][[1, 2]],
                v2 = FindRoot[p[v] == p0, v, v2guess][[1, 2]]
                ,
                pint[v2] - pint[v1] - p0*(v2 - v1)
                ]


                and then



                FindRoot[areadifferential[p0, 0.5, 2] == 0, p0, 0.8, 0.82]
                (* p0 -> 0.811879 *)





                share|improve this answer









                $endgroup$



                Good job on describing your problem.



                Copying your definitions from your question



                p[v_] := (8 t)/(3 v - 1) - 3/v^2
                g[v_] := t/(3 v - 1) - t Log[-1 + 3 v] - 9/(4 v)
                pint[v_] := 8/3 t Log[-1 + 3 v] + 3/v
                t = 0.95


                I found the value 0.81188 to be the value that minimized your areadifferential function (shown at the bottom).



                Look at the plot of P/Pc vs V/Vc and note the three points corresponding to three different V/Vc values resulting in p[v] = 0.8118.



                Module[

                v1 = v /. FindRoot[p[v] == 0.8118, v, 0.5],
                p1,
                v2 = v /. FindRoot[p[v] == 0.8118, v, 1],
                p2,
                v3 = v /. FindRoot[p[v] == 0.8118, v, 2],
                p3
                ,
                p1 = p[v1];
                p2 = p[v2];
                p3 = p[v3];
                Show[
                Plot[p[v], v, 0.65, 2.25, PlotRange -> 0, 3, 0.6, 1,
                AxesLabel -> "V/Vc", "P/Pc"],
                Graphics[

                PointSize[0.03],
                Red,
                Point[v1, p1],
                Green,
                Point[v2, p2],
                Black,
                Point[v3, p3]

                ]
                ]
                ]


                Mathematica graphics



                The problem that you are experiencing is because the value of 0.7 for v1guess is just to the right of the valley so it converges on the wrong point (i.e., the green point).



                Change v1guess to 0.5 and you will be fine, it will converge on the red point. Using v2guess of 2.0 works fine causing convergence on the black point.



                I slightly modified the areadifferential function to use Module rather than parenthesis. One needs to constrain the input arguments to be numeric so FindRoot doesn't complain (FindFoot first tries to work with symbolic arguments which doesn't work with your problem).



                areadifferential[
                p0_?NumericQ,
                v1guess_?NumericQ,
                v2guess_?NumericQ] := Module[

                v1 = FindRoot[p[v] == p0, v, v1guess][[1, 2]],
                v2 = FindRoot[p[v] == p0, v, v2guess][[1, 2]]
                ,
                pint[v2] - pint[v1] - p0*(v2 - v1)
                ]


                and then



                FindRoot[areadifferential[p0, 0.5, 2] == 0, p0, 0.8, 0.82]
                (* p0 -> 0.811879 *)






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 2 hours ago









                Jack LaVigneJack LaVigne

                11.9k21632




                11.9k21632




















                    Alrubaie is a new contributor. Be nice, and check out our Code of Conduct.









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