Coordinate position not preciseWith TikZ, How do I use a labeled coordinate that's inside a node?Rotate a node but not its content: the case of the ellipse decorationTikZ: text along path as nodeHow to define the default vertical distance between nodes?TikZ scaling graphic and adjust node position and keep font sizeNumerical conditional within tikz keys?TikZ/ERD: node (=Entity) label on the insideTikZ: Drawing an arc from an intersection to an intersectionDrawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of them

Can I make popcorn with any corn?

Client team has low performances and low technical skills: we always fix their work and now they stop collaborate with us. How to solve?

Operational amplifier as comparator at high frequency

Has there ever been an airliner design involving reducing generator load by installing solar panels?

Accidentally leaked the solution to an assignment, what to do now? (I'm the prof)

Convert two switches to a dual stack, and add outlet - possible here?

I'm flying to France today and my passport expires in less than 2 months

What does "Puller Prush Person" mean?

How to regain access to running applications after accidentally zapping X.org?

Roll the carpet

Why do I get two different answers for this counting problem?

Paid for article while in US on F1 visa?

Is it unprofessional to ask if a job posting on GlassDoor is real?

Java Casting: Java 11 throws LambdaConversionException while 1.8 does not

meaning of に in 本当に?

Could an aircraft fly or hover using only jets of compressed air?

How do I gain back my faith in my PhD degree?

What's the point of deactivating Num Lock on login screens?

How is the claim "I am in New York only if I am in America" the same as "If I am in New York, then I am in America?

What typically incentivizes a professor to change jobs to a lower ranking university?

Important Resources for Dark Age Civilizations?

Was any UN Security Council vote triple-vetoed?

Filter any system log file by date or date range

Maximum likelihood parameters deviate from posterior distributions



Coordinate position not precise


With TikZ, How do I use a labeled coordinate that's inside a node?Rotate a node but not its content: the case of the ellipse decorationTikZ: text along path as nodeHow to define the default vertical distance between nodes?TikZ scaling graphic and adjust node position and keep font sizeNumerical conditional within tikz keys?TikZ/ERD: node (=Entity) label on the insideTikZ: Drawing an arc from an intersection to an intersectionDrawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of them













3















documentclassstandalone
usepackagetikz
usetikzlibrarycalc,intersections
usepackageamsmath

begindocument

begintikzpicture[scale=0.5]
draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

draw[dotted, name path = ACL] (0,0) plot [domain=0.7:9] (x,0.75*x + 0.8) node[label=right:AC$_L$ = S$_L$](A1);
coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
draw[thick, blue, name path = ACLt] let p1 = (H) in (0,y1) node[left, red]$w_u$ -- (x1,y1) --(A1);
endtikzpicture

enddocument


My problem is as follows:



  • I have attempted to define a coordinate (A1) at the end of the first line (name path ACL).

  • I then use this coordinate (A1) as the last coordinate in the second line (name path ACLt).

It seems that the coordinate is not truly at the end of the line, since the dotted line is extending slightly beyond the thick blue line:



enter image description here



Why is this occurring?










share|improve this question

















  • 1





    Node's have finite size and you can simply say draw[thick, blue, name path = ACLt] (0,0|-H)-- (H) --(A1); which will work fine when A1 is a coordinate.

    – marmot
    Mar 26 at 20:32















3















documentclassstandalone
usepackagetikz
usetikzlibrarycalc,intersections
usepackageamsmath

begindocument

begintikzpicture[scale=0.5]
draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

draw[dotted, name path = ACL] (0,0) plot [domain=0.7:9] (x,0.75*x + 0.8) node[label=right:AC$_L$ = S$_L$](A1);
coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
draw[thick, blue, name path = ACLt] let p1 = (H) in (0,y1) node[left, red]$w_u$ -- (x1,y1) --(A1);
endtikzpicture

enddocument


My problem is as follows:



  • I have attempted to define a coordinate (A1) at the end of the first line (name path ACL).

  • I then use this coordinate (A1) as the last coordinate in the second line (name path ACLt).

It seems that the coordinate is not truly at the end of the line, since the dotted line is extending slightly beyond the thick blue line:



enter image description here



Why is this occurring?










share|improve this question

















  • 1





    Node's have finite size and you can simply say draw[thick, blue, name path = ACLt] (0,0|-H)-- (H) --(A1); which will work fine when A1 is a coordinate.

    – marmot
    Mar 26 at 20:32













3












3








3








documentclassstandalone
usepackagetikz
usetikzlibrarycalc,intersections
usepackageamsmath

begindocument

begintikzpicture[scale=0.5]
draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

draw[dotted, name path = ACL] (0,0) plot [domain=0.7:9] (x,0.75*x + 0.8) node[label=right:AC$_L$ = S$_L$](A1);
coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
draw[thick, blue, name path = ACLt] let p1 = (H) in (0,y1) node[left, red]$w_u$ -- (x1,y1) --(A1);
endtikzpicture

enddocument


My problem is as follows:



  • I have attempted to define a coordinate (A1) at the end of the first line (name path ACL).

  • I then use this coordinate (A1) as the last coordinate in the second line (name path ACLt).

It seems that the coordinate is not truly at the end of the line, since the dotted line is extending slightly beyond the thick blue line:



enter image description here



Why is this occurring?










share|improve this question














documentclassstandalone
usepackagetikz
usetikzlibrarycalc,intersections
usepackageamsmath

begindocument

begintikzpicture[scale=0.5]
draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

draw[dotted, name path = ACL] (0,0) plot [domain=0.7:9] (x,0.75*x + 0.8) node[label=right:AC$_L$ = S$_L$](A1);
coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
draw[thick, blue, name path = ACLt] let p1 = (H) in (0,y1) node[left, red]$w_u$ -- (x1,y1) --(A1);
endtikzpicture

enddocument


My problem is as follows:



  • I have attempted to define a coordinate (A1) at the end of the first line (name path ACL).

  • I then use this coordinate (A1) as the last coordinate in the second line (name path ACLt).

It seems that the coordinate is not truly at the end of the line, since the dotted line is extending slightly beyond the thick blue line:



enter image description here



Why is this occurring?







tikz-pgf coordinates






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 26 at 20:26









Thevesh ThevaThevesh Theva

524114




524114







  • 1





    Node's have finite size and you can simply say draw[thick, blue, name path = ACLt] (0,0|-H)-- (H) --(A1); which will work fine when A1 is a coordinate.

    – marmot
    Mar 26 at 20:32












  • 1





    Node's have finite size and you can simply say draw[thick, blue, name path = ACLt] (0,0|-H)-- (H) --(A1); which will work fine when A1 is a coordinate.

    – marmot
    Mar 26 at 20:32







1




1





Node's have finite size and you can simply say draw[thick, blue, name path = ACLt] (0,0|-H)-- (H) --(A1); which will work fine when A1 is a coordinate.

– marmot
Mar 26 at 20:32





Node's have finite size and you can simply say draw[thick, blue, name path = ACLt] (0,0|-H)-- (H) --(A1); which will work fine when A1 is a coordinate.

– marmot
Mar 26 at 20:32










2 Answers
2






active

oldest

votes


















5














Well, Zarko has turned my comment into "his" answer, but here it is again: use coordinate instead of node because the latter has a finite size (by default). And my answer and comment come with an arguably simpler construction of the path.



documentclassstandalone
usepackagetikz
usetikzlibrarycalc,intersections
usepackageamsmath

begindocument

begintikzpicture[scale=0.5]
draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

draw[dotted, name path = ACL] (0,0) plot [domain=0.7:9] (x,0.75*x + 0.8)
coordinate[label=right:AC$_L$ = S$_L$] (A1);
coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
draw[thick, blue, name path = ACLt] (0,0|-H) node[left, red]$w_u$ -- (H) --(A1);
endtikzpicture

enddocument


enter image description here






share|improve this answer


















  • 1





    Upvoted both answers; accepted yours because your comment was sufficient for me to solve my problem before I saw either answer (I hadn't realised that nodes had a finite size even when I left the label empty). Thanks!

    – Thevesh Theva
    Mar 26 at 20:48







  • 3





    I think that Zarko do not need your comment to see the difference between node and coordinate. TeX.SX is not a competition site "who will answer first" and we are not here to claim paternity of "greate" ideas, but just to help, IMHO.

    – Kpym
    Mar 26 at 22:03











  • @Kpym This is IMHO not the question. The question is whether or not one should acknowledge an earlier post saying the same thing. If you acknowledge this, it does not mean you didn't know that. It is just fair play.

    – marmot
    Mar 26 at 22:41


















8














calculation of coordinate is sufficient accurate, problem is that for it you use node, replace node with coordinate and result will become as you wish:



enter image description here



documentclassstandalone
usepackagetikz
usetikzlibrarycalc,intersections
usepackageamsmath

begindocument

begintikzpicture[scale=0.5]
draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

draw[dotted, name path = ACL]
plot [domain=0.7:9] (x,0.75*x + 0.8) coordinate[label=right:AC$_L$ = S$_L$] (A1);
coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
draw[thick, blue, name path = ACLt] let p1 = (H) in (0,y1) node[left, red]$w_u$ -- (x1,y1) --(A1);
endtikzpicture

enddocument


difference between node and coordinate arise since node has some width regardless if it is empty. it is determined by default value of inner sep. if you set it to zero: inner sep=0pt the result will be the same.



off-topic: in your diagram you not use intersections library, so you can remove line names from code (as i do in aboveo mwe)






share|improve this answer

























    Your Answer








    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "85"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f481586%2fcoordinate-position-not-precise%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    5














    Well, Zarko has turned my comment into "his" answer, but here it is again: use coordinate instead of node because the latter has a finite size (by default). And my answer and comment come with an arguably simpler construction of the path.



    documentclassstandalone
    usepackagetikz
    usetikzlibrarycalc,intersections
    usepackageamsmath

    begindocument

    begintikzpicture[scale=0.5]
    draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

    draw[dotted, name path = ACL] (0,0) plot [domain=0.7:9] (x,0.75*x + 0.8)
    coordinate[label=right:AC$_L$ = S$_L$] (A1);
    coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
    draw[thick, blue, name path = ACLt] (0,0|-H) node[left, red]$w_u$ -- (H) --(A1);
    endtikzpicture

    enddocument


    enter image description here






    share|improve this answer


















    • 1





      Upvoted both answers; accepted yours because your comment was sufficient for me to solve my problem before I saw either answer (I hadn't realised that nodes had a finite size even when I left the label empty). Thanks!

      – Thevesh Theva
      Mar 26 at 20:48







    • 3





      I think that Zarko do not need your comment to see the difference between node and coordinate. TeX.SX is not a competition site "who will answer first" and we are not here to claim paternity of "greate" ideas, but just to help, IMHO.

      – Kpym
      Mar 26 at 22:03











    • @Kpym This is IMHO not the question. The question is whether or not one should acknowledge an earlier post saying the same thing. If you acknowledge this, it does not mean you didn't know that. It is just fair play.

      – marmot
      Mar 26 at 22:41















    5














    Well, Zarko has turned my comment into "his" answer, but here it is again: use coordinate instead of node because the latter has a finite size (by default). And my answer and comment come with an arguably simpler construction of the path.



    documentclassstandalone
    usepackagetikz
    usetikzlibrarycalc,intersections
    usepackageamsmath

    begindocument

    begintikzpicture[scale=0.5]
    draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

    draw[dotted, name path = ACL] (0,0) plot [domain=0.7:9] (x,0.75*x + 0.8)
    coordinate[label=right:AC$_L$ = S$_L$] (A1);
    coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
    draw[thick, blue, name path = ACLt] (0,0|-H) node[left, red]$w_u$ -- (H) --(A1);
    endtikzpicture

    enddocument


    enter image description here






    share|improve this answer


















    • 1





      Upvoted both answers; accepted yours because your comment was sufficient for me to solve my problem before I saw either answer (I hadn't realised that nodes had a finite size even when I left the label empty). Thanks!

      – Thevesh Theva
      Mar 26 at 20:48







    • 3





      I think that Zarko do not need your comment to see the difference between node and coordinate. TeX.SX is not a competition site "who will answer first" and we are not here to claim paternity of "greate" ideas, but just to help, IMHO.

      – Kpym
      Mar 26 at 22:03











    • @Kpym This is IMHO not the question. The question is whether or not one should acknowledge an earlier post saying the same thing. If you acknowledge this, it does not mean you didn't know that. It is just fair play.

      – marmot
      Mar 26 at 22:41













    5












    5








    5







    Well, Zarko has turned my comment into "his" answer, but here it is again: use coordinate instead of node because the latter has a finite size (by default). And my answer and comment come with an arguably simpler construction of the path.



    documentclassstandalone
    usepackagetikz
    usetikzlibrarycalc,intersections
    usepackageamsmath

    begindocument

    begintikzpicture[scale=0.5]
    draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

    draw[dotted, name path = ACL] (0,0) plot [domain=0.7:9] (x,0.75*x + 0.8)
    coordinate[label=right:AC$_L$ = S$_L$] (A1);
    coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
    draw[thick, blue, name path = ACLt] (0,0|-H) node[left, red]$w_u$ -- (H) --(A1);
    endtikzpicture

    enddocument


    enter image description here






    share|improve this answer













    Well, Zarko has turned my comment into "his" answer, but here it is again: use coordinate instead of node because the latter has a finite size (by default). And my answer and comment come with an arguably simpler construction of the path.



    documentclassstandalone
    usepackagetikz
    usetikzlibrarycalc,intersections
    usepackageamsmath

    begindocument

    begintikzpicture[scale=0.5]
    draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

    draw[dotted, name path = ACL] (0,0) plot [domain=0.7:9] (x,0.75*x + 0.8)
    coordinate[label=right:AC$_L$ = S$_L$] (A1);
    coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
    draw[thick, blue, name path = ACLt] (0,0|-H) node[left, red]$w_u$ -- (H) --(A1);
    endtikzpicture

    enddocument


    enter image description here







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Mar 26 at 20:41









    marmotmarmot

    114k5145276




    114k5145276







    • 1





      Upvoted both answers; accepted yours because your comment was sufficient for me to solve my problem before I saw either answer (I hadn't realised that nodes had a finite size even when I left the label empty). Thanks!

      – Thevesh Theva
      Mar 26 at 20:48







    • 3





      I think that Zarko do not need your comment to see the difference between node and coordinate. TeX.SX is not a competition site "who will answer first" and we are not here to claim paternity of "greate" ideas, but just to help, IMHO.

      – Kpym
      Mar 26 at 22:03











    • @Kpym This is IMHO not the question. The question is whether or not one should acknowledge an earlier post saying the same thing. If you acknowledge this, it does not mean you didn't know that. It is just fair play.

      – marmot
      Mar 26 at 22:41












    • 1





      Upvoted both answers; accepted yours because your comment was sufficient for me to solve my problem before I saw either answer (I hadn't realised that nodes had a finite size even when I left the label empty). Thanks!

      – Thevesh Theva
      Mar 26 at 20:48







    • 3





      I think that Zarko do not need your comment to see the difference between node and coordinate. TeX.SX is not a competition site "who will answer first" and we are not here to claim paternity of "greate" ideas, but just to help, IMHO.

      – Kpym
      Mar 26 at 22:03











    • @Kpym This is IMHO not the question. The question is whether or not one should acknowledge an earlier post saying the same thing. If you acknowledge this, it does not mean you didn't know that. It is just fair play.

      – marmot
      Mar 26 at 22:41







    1




    1





    Upvoted both answers; accepted yours because your comment was sufficient for me to solve my problem before I saw either answer (I hadn't realised that nodes had a finite size even when I left the label empty). Thanks!

    – Thevesh Theva
    Mar 26 at 20:48






    Upvoted both answers; accepted yours because your comment was sufficient for me to solve my problem before I saw either answer (I hadn't realised that nodes had a finite size even when I left the label empty). Thanks!

    – Thevesh Theva
    Mar 26 at 20:48





    3




    3





    I think that Zarko do not need your comment to see the difference between node and coordinate. TeX.SX is not a competition site "who will answer first" and we are not here to claim paternity of "greate" ideas, but just to help, IMHO.

    – Kpym
    Mar 26 at 22:03





    I think that Zarko do not need your comment to see the difference between node and coordinate. TeX.SX is not a competition site "who will answer first" and we are not here to claim paternity of "greate" ideas, but just to help, IMHO.

    – Kpym
    Mar 26 at 22:03













    @Kpym This is IMHO not the question. The question is whether or not one should acknowledge an earlier post saying the same thing. If you acknowledge this, it does not mean you didn't know that. It is just fair play.

    – marmot
    Mar 26 at 22:41





    @Kpym This is IMHO not the question. The question is whether or not one should acknowledge an earlier post saying the same thing. If you acknowledge this, it does not mean you didn't know that. It is just fair play.

    – marmot
    Mar 26 at 22:41











    8














    calculation of coordinate is sufficient accurate, problem is that for it you use node, replace node with coordinate and result will become as you wish:



    enter image description here



    documentclassstandalone
    usepackagetikz
    usetikzlibrarycalc,intersections
    usepackageamsmath

    begindocument

    begintikzpicture[scale=0.5]
    draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

    draw[dotted, name path = ACL]
    plot [domain=0.7:9] (x,0.75*x + 0.8) coordinate[label=right:AC$_L$ = S$_L$] (A1);
    coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
    draw[thick, blue, name path = ACLt] let p1 = (H) in (0,y1) node[left, red]$w_u$ -- (x1,y1) --(A1);
    endtikzpicture

    enddocument


    difference between node and coordinate arise since node has some width regardless if it is empty. it is determined by default value of inner sep. if you set it to zero: inner sep=0pt the result will be the same.



    off-topic: in your diagram you not use intersections library, so you can remove line names from code (as i do in aboveo mwe)






    share|improve this answer





























      8














      calculation of coordinate is sufficient accurate, problem is that for it you use node, replace node with coordinate and result will become as you wish:



      enter image description here



      documentclassstandalone
      usepackagetikz
      usetikzlibrarycalc,intersections
      usepackageamsmath

      begindocument

      begintikzpicture[scale=0.5]
      draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

      draw[dotted, name path = ACL]
      plot [domain=0.7:9] (x,0.75*x + 0.8) coordinate[label=right:AC$_L$ = S$_L$] (A1);
      coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
      draw[thick, blue, name path = ACLt] let p1 = (H) in (0,y1) node[left, red]$w_u$ -- (x1,y1) --(A1);
      endtikzpicture

      enddocument


      difference between node and coordinate arise since node has some width regardless if it is empty. it is determined by default value of inner sep. if you set it to zero: inner sep=0pt the result will be the same.



      off-topic: in your diagram you not use intersections library, so you can remove line names from code (as i do in aboveo mwe)






      share|improve this answer



























        8












        8








        8







        calculation of coordinate is sufficient accurate, problem is that for it you use node, replace node with coordinate and result will become as you wish:



        enter image description here



        documentclassstandalone
        usepackagetikz
        usetikzlibrarycalc,intersections
        usepackageamsmath

        begindocument

        begintikzpicture[scale=0.5]
        draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

        draw[dotted, name path = ACL]
        plot [domain=0.7:9] (x,0.75*x + 0.8) coordinate[label=right:AC$_L$ = S$_L$] (A1);
        coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
        draw[thick, blue, name path = ACLt] let p1 = (H) in (0,y1) node[left, red]$w_u$ -- (x1,y1) --(A1);
        endtikzpicture

        enddocument


        difference between node and coordinate arise since node has some width regardless if it is empty. it is determined by default value of inner sep. if you set it to zero: inner sep=0pt the result will be the same.



        off-topic: in your diagram you not use intersections library, so you can remove line names from code (as i do in aboveo mwe)






        share|improve this answer















        calculation of coordinate is sufficient accurate, problem is that for it you use node, replace node with coordinate and result will become as you wish:



        enter image description here



        documentclassstandalone
        usepackagetikz
        usetikzlibrarycalc,intersections
        usepackageamsmath

        begindocument

        begintikzpicture[scale=0.5]
        draw[<->] (0,12) node[above]$w$ |- (12,0) node[right]$q_L$;

        draw[dotted, name path = ACL]
        plot [domain=0.7:9] (x,0.75*x + 0.8) coordinate[label=right:AC$_L$ = S$_L$] (A1);
        coordinate (H) at ($(5.6/0.75,5.6) - (0.8/0.75,0)$);
        draw[thick, blue, name path = ACLt] let p1 = (H) in (0,y1) node[left, red]$w_u$ -- (x1,y1) --(A1);
        endtikzpicture

        enddocument


        difference between node and coordinate arise since node has some width regardless if it is empty. it is determined by default value of inner sep. if you set it to zero: inner sep=0pt the result will be the same.



        off-topic: in your diagram you not use intersections library, so you can remove line names from code (as i do in aboveo mwe)







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Mar 26 at 20:39

























        answered Mar 26 at 20:32









        ZarkoZarko

        129k868169




        129k868169



























            draft saved

            draft discarded
















































            Thanks for contributing an answer to TeX - LaTeX Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f481586%2fcoordinate-position-not-precise%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Adding axes to figuresAdding axes labels to LaTeX figuresLaTeX equivalent of ConTeXt buffersRotate a node but not its content: the case of the ellipse decorationHow to define the default vertical distance between nodes?TikZ scaling graphic and adjust node position and keep font sizeNumerical conditional within tikz keys?adding axes to shapesAlign axes across subfiguresAdding figures with a certain orderLine up nested tikz enviroments or how to get rid of themAdding axes labels to LaTeX figures

            Tähtien Talli Jäsenet | Lähteet | NavigointivalikkoSuomen Hippos – Tähtien Talli

            Do these cracks on my tires look bad? The Next CEO of Stack OverflowDry rot tire should I replace?Having to replace tiresFishtailed so easily? Bad tires? ABS?Filling the tires with something other than air, to avoid puncture hassles?Used Michelin tires safe to install?Do these tyre cracks necessitate replacement?Rumbling noise: tires or mechanicalIs it possible to fix noisy feathered tires?Are bad winter tires still better than summer tires in winter?Torque converter failure - Related to replacing only 2 tires?Why use snow tires on all 4 wheels on 2-wheel-drive cars?