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Magento 1 : each() function is deprecated


Fatal error: Call to a member function getBackend() on a non-objectwhere condition in customer collectionCan't retrieve entity config Error join credit_memo collectionAdding to cart: E_ERROR: Allowed memory size of 2147483648 bytes exhausted (tried to allocate 24 bytes)Get all featured products collectionError Call to a member function getDescription()The each() function is deprecated. Magento 2 , php 7.2Magento 1.9 - There has been an error processing your requestPatch for php 7.2, many deprecated functionsMagento 1 with Php 7.2, add to cart error if product have option













3















In Magento 1, I have been getting this error:




Deprecated: The each() function is deprecated. This message will be suppressed on further calls in /var/www/html/test/app/code/core/Mage/Eav/Model/Entity/Collection/Abstract.php on line 757




Code:



if (is_array($table)) 
list($tableAlias, $tableName) = each($table);
else
$tableName = $table;



How to solve this?



Any help would be much appreciated.










share|improve this question
























  • It's too much different question which you duplicated. First of all, please read it :)

    – Ansuman
    Mar 19 at 10:20











  • apologies for the inconvenience. +1 for your question

    – Shoaib Munir
    Mar 19 at 10:23















3















In Magento 1, I have been getting this error:




Deprecated: The each() function is deprecated. This message will be suppressed on further calls in /var/www/html/test/app/code/core/Mage/Eav/Model/Entity/Collection/Abstract.php on line 757




Code:



if (is_array($table)) 
list($tableAlias, $tableName) = each($table);
else
$tableName = $table;



How to solve this?



Any help would be much appreciated.










share|improve this question
























  • It's too much different question which you duplicated. First of all, please read it :)

    – Ansuman
    Mar 19 at 10:20











  • apologies for the inconvenience. +1 for your question

    – Shoaib Munir
    Mar 19 at 10:23













3












3








3








In Magento 1, I have been getting this error:




Deprecated: The each() function is deprecated. This message will be suppressed on further calls in /var/www/html/test/app/code/core/Mage/Eav/Model/Entity/Collection/Abstract.php on line 757




Code:



if (is_array($table)) 
list($tableAlias, $tableName) = each($table);
else
$tableName = $table;



How to solve this?



Any help would be much appreciated.










share|improve this question
















In Magento 1, I have been getting this error:




Deprecated: The each() function is deprecated. This message will be suppressed on further calls in /var/www/html/test/app/code/core/Mage/Eav/Model/Entity/Collection/Abstract.php on line 757




Code:



if (is_array($table)) 
list($tableAlias, $tableName) = each($table);
else
$tableName = $table;



How to solve this?



Any help would be much appreciated.







magento-1.9 php-7 deprecated






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 19 at 10:19







Ansuman

















asked Mar 19 at 10:15









AnsumanAnsuman

446




446












  • It's too much different question which you duplicated. First of all, please read it :)

    – Ansuman
    Mar 19 at 10:20











  • apologies for the inconvenience. +1 for your question

    – Shoaib Munir
    Mar 19 at 10:23

















  • It's too much different question which you duplicated. First of all, please read it :)

    – Ansuman
    Mar 19 at 10:20











  • apologies for the inconvenience. +1 for your question

    – Shoaib Munir
    Mar 19 at 10:23
















It's too much different question which you duplicated. First of all, please read it :)

– Ansuman
Mar 19 at 10:20





It's too much different question which you duplicated. First of all, please read it :)

– Ansuman
Mar 19 at 10:20













apologies for the inconvenience. +1 for your question

– Shoaib Munir
Mar 19 at 10:23





apologies for the inconvenience. +1 for your question

– Shoaib Munir
Mar 19 at 10:23










1 Answer
1






active

oldest

votes


















6














You should replace this below code in if condition :




list($tableAlias, $tableName) = [key($table), current($table)];




As like :



if (is_array($table)) 
list($tableAlias, $tableName) = [key($table), current($table)];
else
$tableName = $table;






share|improve this answer























  • Thanks ..!! It's working.

    – Ansuman
    Mar 19 at 10:22










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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









6














You should replace this below code in if condition :




list($tableAlias, $tableName) = [key($table), current($table)];




As like :



if (is_array($table)) 
list($tableAlias, $tableName) = [key($table), current($table)];
else
$tableName = $table;






share|improve this answer























  • Thanks ..!! It's working.

    – Ansuman
    Mar 19 at 10:22















6














You should replace this below code in if condition :




list($tableAlias, $tableName) = [key($table), current($table)];




As like :



if (is_array($table)) 
list($tableAlias, $tableName) = [key($table), current($table)];
else
$tableName = $table;






share|improve this answer























  • Thanks ..!! It's working.

    – Ansuman
    Mar 19 at 10:22













6












6








6







You should replace this below code in if condition :




list($tableAlias, $tableName) = [key($table), current($table)];




As like :



if (is_array($table)) 
list($tableAlias, $tableName) = [key($table), current($table)];
else
$tableName = $table;






share|improve this answer













You should replace this below code in if condition :




list($tableAlias, $tableName) = [key($table), current($table)];




As like :



if (is_array($table)) 
list($tableAlias, $tableName) = [key($table), current($table)];
else
$tableName = $table;







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 19 at 10:16









Rohan HapaniRohan Hapani

6,69331865




6,69331865












  • Thanks ..!! It's working.

    – Ansuman
    Mar 19 at 10:22

















  • Thanks ..!! It's working.

    – Ansuman
    Mar 19 at 10:22
















Thanks ..!! It's working.

– Ansuman
Mar 19 at 10:22





Thanks ..!! It's working.

– Ansuman
Mar 19 at 10:22

















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