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Plot of a tornado-shaped surface



The Next CEO of Stack OverflowStrange spikes in my surfacePlot closed surface with ListPlot3Dinterpolating a smooth closed surface to a non-uniform data set (ListSurfacePlot3D)Plot a revolution surface, with two cross sections to show its shapeSolution of a 5D Hypersurface and a 3D SurfacePlot Surface from Curves and Shortest DistancePlot 2D B-spline curve on 3D B-spline surfaceHow to convert a polar plot in surface PlotPlot surface defined by inequalityHow to create a surface plot using unequal vectors










10












$begingroup$


What is a simple code to plot a surface shaped like a tornado?
Any help is welcome.










share|improve this question











$endgroup$
















    10












    $begingroup$


    What is a simple code to plot a surface shaped like a tornado?
    Any help is welcome.










    share|improve this question











    $endgroup$














      10












      10








      10


      2



      $begingroup$


      What is a simple code to plot a surface shaped like a tornado?
      Any help is welcome.










      share|improve this question











      $endgroup$




      What is a simple code to plot a surface shaped like a tornado?
      Any help is welcome.







      plotting






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 22 at 11:51









      J. M. is slightly pensive

      98.7k10311467




      98.7k10311467










      asked Mar 22 at 2:39









      janmarqzjanmarqz

      1515




      1515




















          2 Answers
          2






          active

          oldest

          votes


















          17












          $begingroup$

          I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:



          With[h = 1/10, n = 24, c = 4, p = 2/3,
          ParametricPlot3D[t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p,
          t, 0, 3, v, 0, 2 π, Axes -> None, Boxed -> False,
          Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
          PlotStyle -> Opacity[3/4, Black], ViewPoint -> 3.2, -1.6, 1.]]


          tornado?



          Adjust parameters as seen fit.






          share|improve this answer









          $endgroup$








          • 5




            $begingroup$
            (I should prolly do a cartoon of the "tornado" moving about in a random walk...)
            $endgroup$
            – J. M. is slightly pensive
            Mar 22 at 12:38


















          16












          $begingroup$

          My quick go at it:



          ContourPlot3D[
          (x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
          , x, -1, 1, y, -1, 1, z, 0, 2
          , Mesh -> None, Axes -> False, Boxed -> False
          , PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
          ]


          Tornado






          share|improve this answer









          $endgroup$













            Your Answer





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            2 Answers
            2






            active

            oldest

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            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            17












            $begingroup$

            I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:



            With[h = 1/10, n = 24, c = 4, p = 2/3,
            ParametricPlot3D[t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p,
            t, 0, 3, v, 0, 2 π, Axes -> None, Boxed -> False,
            Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
            PlotStyle -> Opacity[3/4, Black], ViewPoint -> 3.2, -1.6, 1.]]


            tornado?



            Adjust parameters as seen fit.






            share|improve this answer









            $endgroup$








            • 5




              $begingroup$
              (I should prolly do a cartoon of the "tornado" moving about in a random walk...)
              $endgroup$
              – J. M. is slightly pensive
              Mar 22 at 12:38















            17












            $begingroup$

            I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:



            With[h = 1/10, n = 24, c = 4, p = 2/3,
            ParametricPlot3D[t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p,
            t, 0, 3, v, 0, 2 π, Axes -> None, Boxed -> False,
            Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
            PlotStyle -> Opacity[3/4, Black], ViewPoint -> 3.2, -1.6, 1.]]


            tornado?



            Adjust parameters as seen fit.






            share|improve this answer









            $endgroup$








            • 5




              $begingroup$
              (I should prolly do a cartoon of the "tornado" moving about in a random walk...)
              $endgroup$
              – J. M. is slightly pensive
              Mar 22 at 12:38













            17












            17








            17





            $begingroup$

            I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:



            With[h = 1/10, n = 24, c = 4, p = 2/3,
            ParametricPlot3D[t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p,
            t, 0, 3, v, 0, 2 π, Axes -> None, Boxed -> False,
            Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
            PlotStyle -> Opacity[3/4, Black], ViewPoint -> 3.2, -1.6, 1.]]


            tornado?



            Adjust parameters as seen fit.






            share|improve this answer









            $endgroup$



            I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:



            With[h = 1/10, n = 24, c = 4, p = 2/3,
            ParametricPlot3D[t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p,
            t, 0, 3, v, 0, 2 π, Axes -> None, Boxed -> False,
            Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
            PlotStyle -> Opacity[3/4, Black], ViewPoint -> 3.2, -1.6, 1.]]


            tornado?



            Adjust parameters as seen fit.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Mar 22 at 6:01









            J. M. is slightly pensiveJ. M. is slightly pensive

            98.7k10311467




            98.7k10311467







            • 5




              $begingroup$
              (I should prolly do a cartoon of the "tornado" moving about in a random walk...)
              $endgroup$
              – J. M. is slightly pensive
              Mar 22 at 12:38












            • 5




              $begingroup$
              (I should prolly do a cartoon of the "tornado" moving about in a random walk...)
              $endgroup$
              – J. M. is slightly pensive
              Mar 22 at 12:38







            5




            5




            $begingroup$
            (I should prolly do a cartoon of the "tornado" moving about in a random walk...)
            $endgroup$
            – J. M. is slightly pensive
            Mar 22 at 12:38




            $begingroup$
            (I should prolly do a cartoon of the "tornado" moving about in a random walk...)
            $endgroup$
            – J. M. is slightly pensive
            Mar 22 at 12:38











            16












            $begingroup$

            My quick go at it:



            ContourPlot3D[
            (x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
            , x, -1, 1, y, -1, 1, z, 0, 2
            , Mesh -> None, Axes -> False, Boxed -> False
            , PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
            ]


            Tornado






            share|improve this answer









            $endgroup$

















              16












              $begingroup$

              My quick go at it:



              ContourPlot3D[
              (x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
              , x, -1, 1, y, -1, 1, z, 0, 2
              , Mesh -> None, Axes -> False, Boxed -> False
              , PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
              ]


              Tornado






              share|improve this answer









              $endgroup$















                16












                16








                16





                $begingroup$

                My quick go at it:



                ContourPlot3D[
                (x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
                , x, -1, 1, y, -1, 1, z, 0, 2
                , Mesh -> None, Axes -> False, Boxed -> False
                , PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
                ]


                Tornado






                share|improve this answer









                $endgroup$



                My quick go at it:



                ContourPlot3D[
                (x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
                , x, -1, 1, y, -1, 1, z, 0, 2
                , Mesh -> None, Axes -> False, Boxed -> False
                , PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
                ]


                Tornado







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 22 at 3:32









                Thies HeideckeThies Heidecke

                7,2812639




                7,2812639



























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