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Adding empty element to declared container without declaring type of element



The Next CEO of Stack OverflowHow to add element to C++ array?Why can't variables be declared in a switch statement?What are POD types in C++?How do you declare an interface in C++?Meaning of 'const' last in a function declaration of a class?Pretty-print C++ STL containersHow to implement dynamic element container in C++Is it wrong if the standard container element type and std::allocator type are different?Ending lifetime of STL container without calling the destructorenum to string in modern C++11 / C++14 / C++17 and future C++20STL container holding class within declaration of that class










13















When we use a complicated container in C++, like



std::vector<std::map<std::string, std::set<std::string>>> table;


The only way to add an empty map (which may represent a row or column) is to initialize a new element and push it back. For example with



table.push_back(std::map<std::string, std::set<std::string>>());


Is there any way to avoid redeclaring the type, and just adding the correct typed element?










share|improve this question




























    13















    When we use a complicated container in C++, like



    std::vector<std::map<std::string, std::set<std::string>>> table;


    The only way to add an empty map (which may represent a row or column) is to initialize a new element and push it back. For example with



    table.push_back(std::map<std::string, std::set<std::string>>());


    Is there any way to avoid redeclaring the type, and just adding the correct typed element?










    share|improve this question


























      13












      13








      13








      When we use a complicated container in C++, like



      std::vector<std::map<std::string, std::set<std::string>>> table;


      The only way to add an empty map (which may represent a row or column) is to initialize a new element and push it back. For example with



      table.push_back(std::map<std::string, std::set<std::string>>());


      Is there any way to avoid redeclaring the type, and just adding the correct typed element?










      share|improve this question
















      When we use a complicated container in C++, like



      std::vector<std::map<std::string, std::set<std::string>>> table;


      The only way to add an empty map (which may represent a row or column) is to initialize a new element and push it back. For example with



      table.push_back(std::map<std::string, std::set<std::string>>());


      Is there any way to avoid redeclaring the type, and just adding the correct typed element?







      c++ c++11






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 25 at 10:41









      Mohammad Usman

      21.5k134758




      21.5k134758










      asked Mar 25 at 6:35









      VineetVineet

      354411




      354411






















          4 Answers
          4






          active

          oldest

          votes


















          33














          From CLion's IntelliSense, I later found that one useful method is emplace_back(). This constructs a new object of correct type and adds it to the end of the vector.



          table.emplace_back();





          share|improve this answer
































            24














            You can take advantage of copy-list-initialization (since C++11) and just write



            table.push_back();





            share|improve this answer
































              10














              Before C++11 sometimes I use x.resize(x.size()+1), in C++11 or later you can use x.push_back().






              share|improve this answer






























                5














                Though the other answers are correct, I will add that if you couldn't take that approach, you could have benefitted from declaring some type aliases to shorten that container type name.



                I can of course only guess at the logical meaning of your containers, which is another thing that this fixes!



                 using PhilosopherNameType = std::string;
                using NeighboursType = std::set<PhilosopherNameType>;
                using NeighbourMapType = std::map<PhilosopherNameType, NeighboursType>;

                std::vector<NeighbourMapType> table;
                table.push_back(NeighbourMapType());


                I mention this because you can likely still benefit from this in other places.






                share|improve this answer


















                • 2





                  agreed. Along the same lines are the types that the STL gives you (vector::value_type iirc)

                  – sudo rm -rf slash
                  Mar 26 at 8:01











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                4 Answers
                4






                active

                oldest

                votes








                4 Answers
                4






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                33














                From CLion's IntelliSense, I later found that one useful method is emplace_back(). This constructs a new object of correct type and adds it to the end of the vector.



                table.emplace_back();





                share|improve this answer





























                  33














                  From CLion's IntelliSense, I later found that one useful method is emplace_back(). This constructs a new object of correct type and adds it to the end of the vector.



                  table.emplace_back();





                  share|improve this answer



























                    33












                    33








                    33







                    From CLion's IntelliSense, I later found that one useful method is emplace_back(). This constructs a new object of correct type and adds it to the end of the vector.



                    table.emplace_back();





                    share|improve this answer















                    From CLion's IntelliSense, I later found that one useful method is emplace_back(). This constructs a new object of correct type and adds it to the end of the vector.



                    table.emplace_back();






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Mar 25 at 7:12

























                    answered Mar 25 at 6:51









                    VineetVineet

                    354411




                    354411























                        24














                        You can take advantage of copy-list-initialization (since C++11) and just write



                        table.push_back();





                        share|improve this answer





























                          24














                          You can take advantage of copy-list-initialization (since C++11) and just write



                          table.push_back();





                          share|improve this answer



























                            24












                            24








                            24







                            You can take advantage of copy-list-initialization (since C++11) and just write



                            table.push_back();





                            share|improve this answer















                            You can take advantage of copy-list-initialization (since C++11) and just write



                            table.push_back();






                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited Mar 25 at 6:46

























                            answered Mar 25 at 6:37









                            songyuanyaosongyuanyao

                            93.9k11182249




                            93.9k11182249





















                                10














                                Before C++11 sometimes I use x.resize(x.size()+1), in C++11 or later you can use x.push_back().






                                share|improve this answer



























                                  10














                                  Before C++11 sometimes I use x.resize(x.size()+1), in C++11 or later you can use x.push_back().






                                  share|improve this answer

























                                    10












                                    10








                                    10







                                    Before C++11 sometimes I use x.resize(x.size()+1), in C++11 or later you can use x.push_back().






                                    share|improve this answer













                                    Before C++11 sometimes I use x.resize(x.size()+1), in C++11 or later you can use x.push_back().







                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered Mar 25 at 6:49









                                    65026502

                                    87.6k13115218




                                    87.6k13115218





















                                        5














                                        Though the other answers are correct, I will add that if you couldn't take that approach, you could have benefitted from declaring some type aliases to shorten that container type name.



                                        I can of course only guess at the logical meaning of your containers, which is another thing that this fixes!



                                         using PhilosopherNameType = std::string;
                                        using NeighboursType = std::set<PhilosopherNameType>;
                                        using NeighbourMapType = std::map<PhilosopherNameType, NeighboursType>;

                                        std::vector<NeighbourMapType> table;
                                        table.push_back(NeighbourMapType());


                                        I mention this because you can likely still benefit from this in other places.






                                        share|improve this answer


















                                        • 2





                                          agreed. Along the same lines are the types that the STL gives you (vector::value_type iirc)

                                          – sudo rm -rf slash
                                          Mar 26 at 8:01















                                        5














                                        Though the other answers are correct, I will add that if you couldn't take that approach, you could have benefitted from declaring some type aliases to shorten that container type name.



                                        I can of course only guess at the logical meaning of your containers, which is another thing that this fixes!



                                         using PhilosopherNameType = std::string;
                                        using NeighboursType = std::set<PhilosopherNameType>;
                                        using NeighbourMapType = std::map<PhilosopherNameType, NeighboursType>;

                                        std::vector<NeighbourMapType> table;
                                        table.push_back(NeighbourMapType());


                                        I mention this because you can likely still benefit from this in other places.






                                        share|improve this answer


















                                        • 2





                                          agreed. Along the same lines are the types that the STL gives you (vector::value_type iirc)

                                          – sudo rm -rf slash
                                          Mar 26 at 8:01













                                        5












                                        5








                                        5







                                        Though the other answers are correct, I will add that if you couldn't take that approach, you could have benefitted from declaring some type aliases to shorten that container type name.



                                        I can of course only guess at the logical meaning of your containers, which is another thing that this fixes!



                                         using PhilosopherNameType = std::string;
                                        using NeighboursType = std::set<PhilosopherNameType>;
                                        using NeighbourMapType = std::map<PhilosopherNameType, NeighboursType>;

                                        std::vector<NeighbourMapType> table;
                                        table.push_back(NeighbourMapType());


                                        I mention this because you can likely still benefit from this in other places.






                                        share|improve this answer













                                        Though the other answers are correct, I will add that if you couldn't take that approach, you could have benefitted from declaring some type aliases to shorten that container type name.



                                        I can of course only guess at the logical meaning of your containers, which is another thing that this fixes!



                                         using PhilosopherNameType = std::string;
                                        using NeighboursType = std::set<PhilosopherNameType>;
                                        using NeighbourMapType = std::map<PhilosopherNameType, NeighboursType>;

                                        std::vector<NeighbourMapType> table;
                                        table.push_back(NeighbourMapType());


                                        I mention this because you can likely still benefit from this in other places.







                                        share|improve this answer












                                        share|improve this answer



                                        share|improve this answer










                                        answered Mar 25 at 17:12









                                        Lightness Races in OrbitLightness Races in Orbit

                                        295k54477812




                                        295k54477812







                                        • 2





                                          agreed. Along the same lines are the types that the STL gives you (vector::value_type iirc)

                                          – sudo rm -rf slash
                                          Mar 26 at 8:01












                                        • 2





                                          agreed. Along the same lines are the types that the STL gives you (vector::value_type iirc)

                                          – sudo rm -rf slash
                                          Mar 26 at 8:01







                                        2




                                        2





                                        agreed. Along the same lines are the types that the STL gives you (vector::value_type iirc)

                                        – sudo rm -rf slash
                                        Mar 26 at 8:01





                                        agreed. Along the same lines are the types that the STL gives you (vector::value_type iirc)

                                        – sudo rm -rf slash
                                        Mar 26 at 8:01

















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