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Implementing SVM from scratch?
The Next CEO of Stack Overflow2019 Community Moderator ElectionIntuition for the regularization parameter in SVMImplementing sklearn.linear_model.SGDClassifier using pythonDoes the “laplacian” kernel used in the SVM context come from a Hilbert space inner product?Python SVM rgb clusterSVM on sparse dataDoubt with SVM mathsvm optimization problemSVM vs RVM, when to use what?Dataset where svm performance is significantly different from random forest
$begingroup$
I am trying to implement the rbf kernel for SVM from scratch as practice for my coming interviews. I attempted to use cvxopt to solve the optimization problem. However, when I compute the accuracy and compare it to the actual SVM library on sklearn, there is an extremely large discrepancy. I have attempted to isolate the problem but I cannot seem to fix it. Any help would be greatly appreciated. Posted below is the code. If anyone could please let me know what I am doing wrong or help suggest an alternative approach I would greatly appreciate it.
import numpy as np
import cvxopt
def rbf_kernel(gamma, **kwargs):
def f(x1, x2):
distance = np.linalg.norm(x1 - x2) ** 2
return np.exp(-gamma * distance)
return f
class SupportVectorMachine(object):
def __init__(self, C=1, kernel=rbf_kernel, power=4, gamma=None, coef=4):
self.C = C
self.kernel = kernel
self.power = power
self.gamma = gamma
self.coef = coef
self.lagr_multipliers = None
self.support_vectors = None
self.support_vector_labels = None
self.intercept = None
def fit(self, X, y):
n_samples, n_features = np.shape(X)
# Set gamma to 1/n_features by default
if not self.gamma:
self.gamma = 1 / n_features
# Initialize kernel method with parameters
self.kernel = self.kernel(
power=self.power,
gamma=self.gamma,
coef=self.coef)
# Calculate kernel matrix
kernel_matrix = np.zeros((n_samples, n_samples))
for i in range(n_samples):
for j in range(n_samples):
kernel_matrix[i, j] = self.kernel(X[i], X[j])
# Define the quadratic optimization problem
P = cvxopt.matrix(np.outer(y, y) * kernel_matrix, tc='d')
q = cvxopt.matrix(np.ones(n_samples) * -1)
A = cvxopt.matrix(y, (1, n_samples), tc='d')
b = cvxopt.matrix(0, tc='d')
if not self.C: #if its empty
G = cvxopt.matrix(np.identity(n_samples) * -1)
h = cvxopt.matrix(np.zeros(n_samples))
else:
G_max = np.identity(n_samples) * -1
G_min = np.identity(n_samples)
G = cvxopt.matrix(np.vstack((G_max, G_min)))
h_max = cvxopt.matrix(np.zeros(n_samples))
h_min = cvxopt.matrix(np.ones(n_samples) * self.C)
h = cvxopt.matrix(np.vstack((h_max, h_min)))
# Solve the quadratic optimization problem using cvxopt
minimization = cvxopt.solvers.qp(P, q, G, h, A, b)
# Lagrange multipliers
lagr_mult = np.ravel(minimization['x'])
# Extract support vectors
# Get indexes of non-zero lagr. multipiers
idx = lagr_mult > 1e-11
# Get the corresponding lagr. multipliers
self.lagr_multipliers = lagr_mult[idx]
# Get the samples that will act as support vectors
self.support_vectors = X[idx]
# Get the corresponding labels
self.support_vector_labels = y[idx]
# Calculate intercept with first support vector
self.intercept = self.support_vector_labels[0]
for i in range(len(self.lagr_multipliers)):
self.intercept -= self.lagr_multipliers[i] * self.support_vector_labels[
i] * self.kernel(self.support_vectors[i], self.support_vectors[0])
def predict(self, X):
y_pred = []
# Iterate through list of samples and make predictions
for sample in X:
prediction = 0
# Determine the label of the sample by the support vectors
for i in range(len(self.lagr_multipliers)):
prediction += self.lagr_multipliers[i] * self.support_vector_labels[
i] * self.kernel(self.support_vectors[i], sample)
prediction += self.intercept
y_pred.append(np.sign(prediction))
return np.array(y_pred)
def main():
print ("-- SVM Classifier --")
data = load_iris()
# previous error
#X = normalize(data.data)
#y = data.target
# correct version
X = normalize(data.data[data.target != 0])
y = data.target[data.target != 0]
y[y == 1] = -1
y[y == 2] = 1
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.4)
clf = SupportVectorMachine(kernel=rbf_kernel, gamma = 1)
clf.fit(X_train, y_train)
y_pred = clf.predict(X_test)
accuracy = accuracy_score(y_test, y_pred)
print ("Accuracy (scratch):", accuracy)
clf_sklearn = SVC(gamma = 'auto')
clf_sklearn.fit(X_train, y_train)
y_pred2 = clf_sklearn.predict(X_test)
accuracy = accuracy_score(y_test, y_pred2)
print ("Accuracy :", accuracy)
if __name__ == "__main__":
main()
RESULTS:
Accuracy (from scratch): 0.31666666666666665
Accuracy (using SVM Library) : 1.0
Note, I did not add the libraries to save space
svm
$endgroup$
add a comment |
$begingroup$
I am trying to implement the rbf kernel for SVM from scratch as practice for my coming interviews. I attempted to use cvxopt to solve the optimization problem. However, when I compute the accuracy and compare it to the actual SVM library on sklearn, there is an extremely large discrepancy. I have attempted to isolate the problem but I cannot seem to fix it. Any help would be greatly appreciated. Posted below is the code. If anyone could please let me know what I am doing wrong or help suggest an alternative approach I would greatly appreciate it.
import numpy as np
import cvxopt
def rbf_kernel(gamma, **kwargs):
def f(x1, x2):
distance = np.linalg.norm(x1 - x2) ** 2
return np.exp(-gamma * distance)
return f
class SupportVectorMachine(object):
def __init__(self, C=1, kernel=rbf_kernel, power=4, gamma=None, coef=4):
self.C = C
self.kernel = kernel
self.power = power
self.gamma = gamma
self.coef = coef
self.lagr_multipliers = None
self.support_vectors = None
self.support_vector_labels = None
self.intercept = None
def fit(self, X, y):
n_samples, n_features = np.shape(X)
# Set gamma to 1/n_features by default
if not self.gamma:
self.gamma = 1 / n_features
# Initialize kernel method with parameters
self.kernel = self.kernel(
power=self.power,
gamma=self.gamma,
coef=self.coef)
# Calculate kernel matrix
kernel_matrix = np.zeros((n_samples, n_samples))
for i in range(n_samples):
for j in range(n_samples):
kernel_matrix[i, j] = self.kernel(X[i], X[j])
# Define the quadratic optimization problem
P = cvxopt.matrix(np.outer(y, y) * kernel_matrix, tc='d')
q = cvxopt.matrix(np.ones(n_samples) * -1)
A = cvxopt.matrix(y, (1, n_samples), tc='d')
b = cvxopt.matrix(0, tc='d')
if not self.C: #if its empty
G = cvxopt.matrix(np.identity(n_samples) * -1)
h = cvxopt.matrix(np.zeros(n_samples))
else:
G_max = np.identity(n_samples) * -1
G_min = np.identity(n_samples)
G = cvxopt.matrix(np.vstack((G_max, G_min)))
h_max = cvxopt.matrix(np.zeros(n_samples))
h_min = cvxopt.matrix(np.ones(n_samples) * self.C)
h = cvxopt.matrix(np.vstack((h_max, h_min)))
# Solve the quadratic optimization problem using cvxopt
minimization = cvxopt.solvers.qp(P, q, G, h, A, b)
# Lagrange multipliers
lagr_mult = np.ravel(minimization['x'])
# Extract support vectors
# Get indexes of non-zero lagr. multipiers
idx = lagr_mult > 1e-11
# Get the corresponding lagr. multipliers
self.lagr_multipliers = lagr_mult[idx]
# Get the samples that will act as support vectors
self.support_vectors = X[idx]
# Get the corresponding labels
self.support_vector_labels = y[idx]
# Calculate intercept with first support vector
self.intercept = self.support_vector_labels[0]
for i in range(len(self.lagr_multipliers)):
self.intercept -= self.lagr_multipliers[i] * self.support_vector_labels[
i] * self.kernel(self.support_vectors[i], self.support_vectors[0])
def predict(self, X):
y_pred = []
# Iterate through list of samples and make predictions
for sample in X:
prediction = 0
# Determine the label of the sample by the support vectors
for i in range(len(self.lagr_multipliers)):
prediction += self.lagr_multipliers[i] * self.support_vector_labels[
i] * self.kernel(self.support_vectors[i], sample)
prediction += self.intercept
y_pred.append(np.sign(prediction))
return np.array(y_pred)
def main():
print ("-- SVM Classifier --")
data = load_iris()
# previous error
#X = normalize(data.data)
#y = data.target
# correct version
X = normalize(data.data[data.target != 0])
y = data.target[data.target != 0]
y[y == 1] = -1
y[y == 2] = 1
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.4)
clf = SupportVectorMachine(kernel=rbf_kernel, gamma = 1)
clf.fit(X_train, y_train)
y_pred = clf.predict(X_test)
accuracy = accuracy_score(y_test, y_pred)
print ("Accuracy (scratch):", accuracy)
clf_sklearn = SVC(gamma = 'auto')
clf_sklearn.fit(X_train, y_train)
y_pred2 = clf_sklearn.predict(X_test)
accuracy = accuracy_score(y_test, y_pred2)
print ("Accuracy :", accuracy)
if __name__ == "__main__":
main()
RESULTS:
Accuracy (from scratch): 0.31666666666666665
Accuracy (using SVM Library) : 1.0
Note, I did not add the libraries to save space
svm
$endgroup$
$begingroup$
Could you please post the hyperparameters after you fitted the model, both from sklearn and your own model?
$endgroup$
– Pedro Henrique Monforte
Mar 25 at 18:51
add a comment |
$begingroup$
I am trying to implement the rbf kernel for SVM from scratch as practice for my coming interviews. I attempted to use cvxopt to solve the optimization problem. However, when I compute the accuracy and compare it to the actual SVM library on sklearn, there is an extremely large discrepancy. I have attempted to isolate the problem but I cannot seem to fix it. Any help would be greatly appreciated. Posted below is the code. If anyone could please let me know what I am doing wrong or help suggest an alternative approach I would greatly appreciate it.
import numpy as np
import cvxopt
def rbf_kernel(gamma, **kwargs):
def f(x1, x2):
distance = np.linalg.norm(x1 - x2) ** 2
return np.exp(-gamma * distance)
return f
class SupportVectorMachine(object):
def __init__(self, C=1, kernel=rbf_kernel, power=4, gamma=None, coef=4):
self.C = C
self.kernel = kernel
self.power = power
self.gamma = gamma
self.coef = coef
self.lagr_multipliers = None
self.support_vectors = None
self.support_vector_labels = None
self.intercept = None
def fit(self, X, y):
n_samples, n_features = np.shape(X)
# Set gamma to 1/n_features by default
if not self.gamma:
self.gamma = 1 / n_features
# Initialize kernel method with parameters
self.kernel = self.kernel(
power=self.power,
gamma=self.gamma,
coef=self.coef)
# Calculate kernel matrix
kernel_matrix = np.zeros((n_samples, n_samples))
for i in range(n_samples):
for j in range(n_samples):
kernel_matrix[i, j] = self.kernel(X[i], X[j])
# Define the quadratic optimization problem
P = cvxopt.matrix(np.outer(y, y) * kernel_matrix, tc='d')
q = cvxopt.matrix(np.ones(n_samples) * -1)
A = cvxopt.matrix(y, (1, n_samples), tc='d')
b = cvxopt.matrix(0, tc='d')
if not self.C: #if its empty
G = cvxopt.matrix(np.identity(n_samples) * -1)
h = cvxopt.matrix(np.zeros(n_samples))
else:
G_max = np.identity(n_samples) * -1
G_min = np.identity(n_samples)
G = cvxopt.matrix(np.vstack((G_max, G_min)))
h_max = cvxopt.matrix(np.zeros(n_samples))
h_min = cvxopt.matrix(np.ones(n_samples) * self.C)
h = cvxopt.matrix(np.vstack((h_max, h_min)))
# Solve the quadratic optimization problem using cvxopt
minimization = cvxopt.solvers.qp(P, q, G, h, A, b)
# Lagrange multipliers
lagr_mult = np.ravel(minimization['x'])
# Extract support vectors
# Get indexes of non-zero lagr. multipiers
idx = lagr_mult > 1e-11
# Get the corresponding lagr. multipliers
self.lagr_multipliers = lagr_mult[idx]
# Get the samples that will act as support vectors
self.support_vectors = X[idx]
# Get the corresponding labels
self.support_vector_labels = y[idx]
# Calculate intercept with first support vector
self.intercept = self.support_vector_labels[0]
for i in range(len(self.lagr_multipliers)):
self.intercept -= self.lagr_multipliers[i] * self.support_vector_labels[
i] * self.kernel(self.support_vectors[i], self.support_vectors[0])
def predict(self, X):
y_pred = []
# Iterate through list of samples and make predictions
for sample in X:
prediction = 0
# Determine the label of the sample by the support vectors
for i in range(len(self.lagr_multipliers)):
prediction += self.lagr_multipliers[i] * self.support_vector_labels[
i] * self.kernel(self.support_vectors[i], sample)
prediction += self.intercept
y_pred.append(np.sign(prediction))
return np.array(y_pred)
def main():
print ("-- SVM Classifier --")
data = load_iris()
# previous error
#X = normalize(data.data)
#y = data.target
# correct version
X = normalize(data.data[data.target != 0])
y = data.target[data.target != 0]
y[y == 1] = -1
y[y == 2] = 1
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.4)
clf = SupportVectorMachine(kernel=rbf_kernel, gamma = 1)
clf.fit(X_train, y_train)
y_pred = clf.predict(X_test)
accuracy = accuracy_score(y_test, y_pred)
print ("Accuracy (scratch):", accuracy)
clf_sklearn = SVC(gamma = 'auto')
clf_sklearn.fit(X_train, y_train)
y_pred2 = clf_sklearn.predict(X_test)
accuracy = accuracy_score(y_test, y_pred2)
print ("Accuracy :", accuracy)
if __name__ == "__main__":
main()
RESULTS:
Accuracy (from scratch): 0.31666666666666665
Accuracy (using SVM Library) : 1.0
Note, I did not add the libraries to save space
svm
$endgroup$
I am trying to implement the rbf kernel for SVM from scratch as practice for my coming interviews. I attempted to use cvxopt to solve the optimization problem. However, when I compute the accuracy and compare it to the actual SVM library on sklearn, there is an extremely large discrepancy. I have attempted to isolate the problem but I cannot seem to fix it. Any help would be greatly appreciated. Posted below is the code. If anyone could please let me know what I am doing wrong or help suggest an alternative approach I would greatly appreciate it.
import numpy as np
import cvxopt
def rbf_kernel(gamma, **kwargs):
def f(x1, x2):
distance = np.linalg.norm(x1 - x2) ** 2
return np.exp(-gamma * distance)
return f
class SupportVectorMachine(object):
def __init__(self, C=1, kernel=rbf_kernel, power=4, gamma=None, coef=4):
self.C = C
self.kernel = kernel
self.power = power
self.gamma = gamma
self.coef = coef
self.lagr_multipliers = None
self.support_vectors = None
self.support_vector_labels = None
self.intercept = None
def fit(self, X, y):
n_samples, n_features = np.shape(X)
# Set gamma to 1/n_features by default
if not self.gamma:
self.gamma = 1 / n_features
# Initialize kernel method with parameters
self.kernel = self.kernel(
power=self.power,
gamma=self.gamma,
coef=self.coef)
# Calculate kernel matrix
kernel_matrix = np.zeros((n_samples, n_samples))
for i in range(n_samples):
for j in range(n_samples):
kernel_matrix[i, j] = self.kernel(X[i], X[j])
# Define the quadratic optimization problem
P = cvxopt.matrix(np.outer(y, y) * kernel_matrix, tc='d')
q = cvxopt.matrix(np.ones(n_samples) * -1)
A = cvxopt.matrix(y, (1, n_samples), tc='d')
b = cvxopt.matrix(0, tc='d')
if not self.C: #if its empty
G = cvxopt.matrix(np.identity(n_samples) * -1)
h = cvxopt.matrix(np.zeros(n_samples))
else:
G_max = np.identity(n_samples) * -1
G_min = np.identity(n_samples)
G = cvxopt.matrix(np.vstack((G_max, G_min)))
h_max = cvxopt.matrix(np.zeros(n_samples))
h_min = cvxopt.matrix(np.ones(n_samples) * self.C)
h = cvxopt.matrix(np.vstack((h_max, h_min)))
# Solve the quadratic optimization problem using cvxopt
minimization = cvxopt.solvers.qp(P, q, G, h, A, b)
# Lagrange multipliers
lagr_mult = np.ravel(minimization['x'])
# Extract support vectors
# Get indexes of non-zero lagr. multipiers
idx = lagr_mult > 1e-11
# Get the corresponding lagr. multipliers
self.lagr_multipliers = lagr_mult[idx]
# Get the samples that will act as support vectors
self.support_vectors = X[idx]
# Get the corresponding labels
self.support_vector_labels = y[idx]
# Calculate intercept with first support vector
self.intercept = self.support_vector_labels[0]
for i in range(len(self.lagr_multipliers)):
self.intercept -= self.lagr_multipliers[i] * self.support_vector_labels[
i] * self.kernel(self.support_vectors[i], self.support_vectors[0])
def predict(self, X):
y_pred = []
# Iterate through list of samples and make predictions
for sample in X:
prediction = 0
# Determine the label of the sample by the support vectors
for i in range(len(self.lagr_multipliers)):
prediction += self.lagr_multipliers[i] * self.support_vector_labels[
i] * self.kernel(self.support_vectors[i], sample)
prediction += self.intercept
y_pred.append(np.sign(prediction))
return np.array(y_pred)
def main():
print ("-- SVM Classifier --")
data = load_iris()
# previous error
#X = normalize(data.data)
#y = data.target
# correct version
X = normalize(data.data[data.target != 0])
y = data.target[data.target != 0]
y[y == 1] = -1
y[y == 2] = 1
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.4)
clf = SupportVectorMachine(kernel=rbf_kernel, gamma = 1)
clf.fit(X_train, y_train)
y_pred = clf.predict(X_test)
accuracy = accuracy_score(y_test, y_pred)
print ("Accuracy (scratch):", accuracy)
clf_sklearn = SVC(gamma = 'auto')
clf_sklearn.fit(X_train, y_train)
y_pred2 = clf_sklearn.predict(X_test)
accuracy = accuracy_score(y_test, y_pred2)
print ("Accuracy :", accuracy)
if __name__ == "__main__":
main()
RESULTS:
Accuracy (from scratch): 0.31666666666666665
Accuracy (using SVM Library) : 1.0
Note, I did not add the libraries to save space
svm
svm
edited Mar 25 at 19:05
user70145
asked Mar 25 at 4:02
user70145user70145
42
42
$begingroup$
Could you please post the hyperparameters after you fitted the model, both from sklearn and your own model?
$endgroup$
– Pedro Henrique Monforte
Mar 25 at 18:51
add a comment |
$begingroup$
Could you please post the hyperparameters after you fitted the model, both from sklearn and your own model?
$endgroup$
– Pedro Henrique Monforte
Mar 25 at 18:51
$begingroup$
Could you please post the hyperparameters after you fitted the model, both from sklearn and your own model?
$endgroup$
– Pedro Henrique Monforte
Mar 25 at 18:51
$begingroup$
Could you please post the hyperparameters after you fitted the model, both from sklearn and your own model?
$endgroup$
– Pedro Henrique Monforte
Mar 25 at 18:51
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
This is actually correct code. Nothing is wrong with it per se.
However, NOTE: that this is meant for OVO (one versus one) SVM. Basically if you are comparing two classes. THIS is not meant for more than two classes, hence why you would get a lower accuracy.
$endgroup$
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
This is actually correct code. Nothing is wrong with it per se.
However, NOTE: that this is meant for OVO (one versus one) SVM. Basically if you are comparing two classes. THIS is not meant for more than two classes, hence why you would get a lower accuracy.
$endgroup$
add a comment |
$begingroup$
This is actually correct code. Nothing is wrong with it per se.
However, NOTE: that this is meant for OVO (one versus one) SVM. Basically if you are comparing two classes. THIS is not meant for more than two classes, hence why you would get a lower accuracy.
$endgroup$
add a comment |
$begingroup$
This is actually correct code. Nothing is wrong with it per se.
However, NOTE: that this is meant for OVO (one versus one) SVM. Basically if you are comparing two classes. THIS is not meant for more than two classes, hence why you would get a lower accuracy.
$endgroup$
This is actually correct code. Nothing is wrong with it per se.
However, NOTE: that this is meant for OVO (one versus one) SVM. Basically if you are comparing two classes. THIS is not meant for more than two classes, hence why you would get a lower accuracy.
answered Mar 25 at 18:42
user70145user70145
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$begingroup$
Could you please post the hyperparameters after you fitted the model, both from sklearn and your own model?
$endgroup$
– Pedro Henrique Monforte
Mar 25 at 18:51