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6

I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.

function execute_function() head -c 6 ; echo ''`
 echo "Launching Job: $job_id"
 echo $i
 done

When I run it, I always get:

execute_function 10

 Launching 10 jobs
 Launching Job: XX9BWC
 1..10

The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"

shell-script shell osx brace-expansion

share|improve this question

edited Apr 2 at 8:02

Kusalananda♦

142k18266442

asked Apr 2 at 4:55

spicyramenspicyramen

1334

add a comment | 

6

I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.

function execute_function() head -c 6 ; echo ''`
 echo "Launching Job: $job_id"
 echo $i
 done

When I run it, I always get:

execute_function 10

 Launching 10 jobs
 Launching Job: XX9BWC
 1..10

The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"

shell-script shell osx brace-expansion

share|improve this question

edited Apr 2 at 8:02

Kusalananda♦

142k18266442

asked Apr 2 at 4:55

spicyramenspicyramen

1334

add a comment | 

I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.

function execute_function() head -c 6 ; echo ''`
 echo "Launching Job: $job_id"
 echo $i
 done

When I run it, I always get:

execute_function 10

 Launching 10 jobs
 Launching Job: XX9BWC
 1..10

The same happens if I replace: $1 with $number_of_jobs or "$number_of_jobs"

shell-script shell osx brace-expansion

share|improve this question

edited Apr 2 at 8:02

Kusalananda♦

142k18266442

asked Apr 2 at 4:55

spicyramenspicyramen

1334

function execute_function() head -c 6 ; echo ''`
 echo "Launching Job: $job_id"
 echo $i
 done

execute_function 10

 Launching 10 jobs
 Launching Job: XX9BWC
 1..10

share|improve this question

edited Apr 2 at 8:02

Kusalananda♦

142k18266442

asked Apr 2 at 4:55

spicyramenspicyramen

1334

share|improve this question

edited Apr 2 at 8:02

Kusalananda♦

142k18266442

asked Apr 2 at 4:55

spicyramenspicyramen

1334

edited Apr 2 at 8:02

Kusalananda♦

142k18266442

edited Apr 2 at 8:02

Kusalananda♦

142k18266442

asked Apr 2 at 4:55

spicyramenspicyramen

1334

asked Apr 2 at 4:55

spicyramenspicyramen

1334

2 Answers
2

active

oldest

votes

6

The problem here is variable in braces expansion.

Try rewriting it to

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited Apr 2 at 6:59

answered Apr 2 at 5:08

Jakub JindraJakub Jindra

608514

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That worked perfectly
  
  – spicyramen
  Apr 2 at 5:22
  

  
  
  
  

add a comment | 

7

Your script is written for zsh but you are executing it with bash.

bash does not support using variables as ranges in brace-expansions.

To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.

See also:

• Listing numbered files using wildcard sequence with predefined range


• How can I use $variable in a shell brace expansion of a sequence?


• Does the shebang determine the shell which runs the script?

share|improve this answer

edited Apr 2 at 7:59

answered Apr 2 at 5:28

Kusalananda♦Kusalananda

142k18266442

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  include #!/bin/zsh as first line. (you may need to check the path.
  
  – ctrl-alt-delor
  Apr 2 at 7:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  what about #!/usr/bin/env zsh?
  
  – Jakub Jindra
  Apr 2 at 8:46
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.
  
  – Kusalananda♦
  Apr 2 at 8:50
  
  

  
  
  
  

add a comment | 

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6

The problem here is variable in braces expansion.

Try rewriting it to

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited Apr 2 at 6:59

answered Apr 2 at 5:08

Jakub JindraJakub Jindra

608514

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That worked perfectly
  
  – spicyramen
  Apr 2 at 5:22
  

  
  
  
  

add a comment | 

6

The problem here is variable in braces expansion.

Try rewriting it to

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited Apr 2 at 6:59

answered Apr 2 at 5:08

Jakub JindraJakub Jindra

608514

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That worked perfectly
  
  – spicyramen
  Apr 2 at 5:22
  

  
  
  
  

add a comment | 

The problem here is variable in braces expansion.

Try rewriting it to

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited Apr 2 at 6:59

answered Apr 2 at 5:08

Jakub JindraJakub Jindra

608514

for ((i=1;i<=$1;i++))
do
 #your code here
done

share|improve this answer

edited Apr 2 at 6:59

answered Apr 2 at 5:08

Jakub JindraJakub Jindra

608514

answered Apr 2 at 5:08

Jakub JindraJakub Jindra

608514

answered Apr 2 at 5:08

Jakub JindraJakub Jindra

608514

7

Your script is written for zsh but you are executing it with bash.

bash does not support using variables as ranges in brace-expansions.

To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.

See also:

• Listing numbered files using wildcard sequence with predefined range


• How can I use $variable in a shell brace expansion of a sequence?


• Does the shebang determine the shell which runs the script?

share|improve this answer

edited Apr 2 at 7:59

answered Apr 2 at 5:28

Kusalananda♦Kusalananda

142k18266442

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  include #!/bin/zsh as first line. (you may need to check the path.
  
  – ctrl-alt-delor
  Apr 2 at 7:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  what about #!/usr/bin/env zsh?
  
  – Jakub Jindra
  Apr 2 at 8:46
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.
  
  – Kusalananda♦
  Apr 2 at 8:50
  
  

  
  
  
  

add a comment | 

7

Your script is written for zsh but you are executing it with bash.

bash does not support using variables as ranges in brace-expansions.

To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.

See also:

• Listing numbered files using wildcard sequence with predefined range


• How can I use $variable in a shell brace expansion of a sequence?


• Does the shebang determine the shell which runs the script?

share|improve this answer

edited Apr 2 at 7:59

answered Apr 2 at 5:28

Kusalananda♦Kusalananda

142k18266442

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  include #!/bin/zsh as first line. (you may need to check the path.
  
  – ctrl-alt-delor
  Apr 2 at 7:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  what about #!/usr/bin/env zsh?
  
  – Jakub Jindra
  Apr 2 at 8:46
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.
  
  – Kusalananda♦
  Apr 2 at 8:50
  
  

  
  
  
  

add a comment | 

Your script is written for zsh but you are executing it with bash.

bash does not support using variables as ranges in brace-expansions.

To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.

See also:

• Listing numbered files using wildcard sequence with predefined range


• How can I use $variable in a shell brace expansion of a sequence?


• Does the shebang determine the shell which runs the script?

share|improve this answer

edited Apr 2 at 7:59

answered Apr 2 at 5:28

Kusalananda♦Kusalananda

142k18266442

share|improve this answer

edited Apr 2 at 7:59

answered Apr 2 at 5:28

Kusalananda♦Kusalananda

142k18266442

answered Apr 2 at 5:28

Kusalananda♦Kusalananda

142k18266442

answered Apr 2 at 5:28

Kusalananda♦Kusalananda

142k18266442