Unlock My Phone! February 2018 Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Unlock My Phone! January 2018The summer term exams must go onIn standard isolated labWe have an important mission for youARG - morse/wordplay puzzle?A Puzzling Cipher: ReduxI can't unlock my phone!Enigmatic AnimalsAn important club and two competing applicantsThe “Three Diamond” Distilling CompanyUnlock My Phone! January 2018
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Unlock My Phone! February 2018
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Unlock My Phone! January 2018The summer term exams must go onIn standard isolated labWe have an important mission for youARG - morse/wordplay puzzle?A Puzzling Cipher: ReduxI can't unlock my phone!Enigmatic AnimalsAn important club and two competing applicantsThe “Three Diamond” Distilling CompanyUnlock My Phone! January 2018
$begingroup$
I forgot my password again! I changed it a few days ago but already forgot!
What is my phone's password this month?
Hint #1:
My passwords do tend to be fairly long, as mentioned in the comments.
Hint #2:
The number itself may not have been on the moon, but maybe something it shares a trait with.
knowledge visual
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
331212
$endgroup$
add a comment |
$begingroup$
I forgot my password again! I changed it a few days ago but already forgot!
What is my phone's password this month?
Hint #1:
My passwords do tend to be fairly long, as mentioned in the comments.
Hint #2:
The number itself may not have been on the moon, but maybe something it shares a trait with.
knowledge visual
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
331212
$endgroup$
1
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
Apr 2 at 22:30
2
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
Apr 3 at 0:32
add a comment |
$begingroup$
I forgot my password again! I changed it a few days ago but already forgot!
What is my phone's password this month?
Hint #1:
My passwords do tend to be fairly long, as mentioned in the comments.
Hint #2:
The number itself may not have been on the moon, but maybe something it shares a trait with.
knowledge visual
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
331212
$endgroup$
I forgot my password again! I changed it a few days ago but already forgot!
What is my phone's password this month?
Hint #1:
My passwords do tend to be fairly long, as mentioned in the comments.
Hint #2:
The number itself may not have been on the moon, but maybe something it shares a trait with.
knowledge visual
knowledge visual
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
331212
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
331212
edited Apr 3 at 0:26
Tyler22Alex
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
331212
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
331212
asked Apr 2 at 17:08
Tyler22AlexTyler22Alex
331212
331212
1
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
Apr 2 at 22:30
2
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
Apr 3 at 0:32
add a comment |
1
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
Apr 2 at 22:30
2
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
Apr 3 at 0:32
1
1
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
Apr 2 at 22:30
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
Apr 2 at 22:30
2
2
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
Apr 3 at 0:32
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
Apr 3 at 0:32
add a comment |
8 Answers
8
active
oldest
votes
$begingroup$
Your lock code is
115132219018763992565095597973971522401
The reason
Neil Armstrong was the first man on moon. Armstrong number is an n-digit number in which sum of n-th power of each digit is equal to the number itself.
E.g. - 371 = 3^3 + 7^3 + 1^3. (3 digit number so power of 3).
Using this rationale, we find that
115132219018763992565095597973971522401 is the largest known armstrong number as per this and has 39 digits.
No wonder you forgot it!
Bonus reading - wikipedia
answered Apr 3 at 7:40
RedBaronRedBaron
38626
$endgroup$
5
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
add a comment |
$begingroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
answered Apr 2 at 19:49
AProughAPrough
5,9061245
$endgroup$
1
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
1
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
add a comment |
$begingroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,60821073
$endgroup$
7
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
1
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
add a comment |
$begingroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
answered Apr 2 at 21:21
user1812user1812
912
$endgroup$
1
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
1
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
add a comment |
$begingroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
2,640537
$endgroup$
1
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
1
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
add a comment |
$begingroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
$endgroup$
1
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
add a comment |
$begingroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
answered Apr 2 at 21:05
tuvokkituvokki
1312
$endgroup$
1
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
add a comment |
$begingroup$
The answer is
9.5 Because it's the boot size Neil Armstrong had when first setting foot on the moon.
Thus it was "the largest number to be first on the moon"
answered Apr 3 at 12:52
PeterPeter
2006
$endgroup$
add a comment |
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8 Answers
8
active
oldest
votes
8 Answers
8
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Your lock code is
115132219018763992565095597973971522401
The reason
Neil Armstrong was the first man on moon. Armstrong number is an n-digit number in which sum of n-th power of each digit is equal to the number itself.
E.g. - 371 = 3^3 + 7^3 + 1^3. (3 digit number so power of 3).
Using this rationale, we find that
115132219018763992565095597973971522401 is the largest known armstrong number as per this and has 39 digits.
No wonder you forgot it!
Bonus reading - wikipedia
answered Apr 3 at 7:40
RedBaronRedBaron
38626
$endgroup$
5
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
add a comment |
$begingroup$
Your lock code is
115132219018763992565095597973971522401
The reason
Neil Armstrong was the first man on moon. Armstrong number is an n-digit number in which sum of n-th power of each digit is equal to the number itself.
E.g. - 371 = 3^3 + 7^3 + 1^3. (3 digit number so power of 3).
Using this rationale, we find that
115132219018763992565095597973971522401 is the largest known armstrong number as per this and has 39 digits.
No wonder you forgot it!
Bonus reading - wikipedia
answered Apr 3 at 7:40
RedBaronRedBaron
38626
$endgroup$
5
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
add a comment |
$begingroup$
Your lock code is
115132219018763992565095597973971522401
The reason
Neil Armstrong was the first man on moon. Armstrong number is an n-digit number in which sum of n-th power of each digit is equal to the number itself.
E.g. - 371 = 3^3 + 7^3 + 1^3. (3 digit number so power of 3).
Using this rationale, we find that
115132219018763992565095597973971522401 is the largest known armstrong number as per this and has 39 digits.
No wonder you forgot it!
Bonus reading - wikipedia
answered Apr 3 at 7:40
RedBaronRedBaron
38626
$endgroup$
Your lock code is
115132219018763992565095597973971522401
The reason
Neil Armstrong was the first man on moon. Armstrong number is an n-digit number in which sum of n-th power of each digit is equal to the number itself.
E.g. - 371 = 3^3 + 7^3 + 1^3. (3 digit number so power of 3).
Using this rationale, we find that
115132219018763992565095597973971522401 is the largest known armstrong number as per this and has 39 digits.
No wonder you forgot it!
Bonus reading - wikipedia
answered Apr 3 at 7:40
RedBaronRedBaron
38626
edited Apr 3 at 8:08
answered Apr 3 at 7:40
RedBaronRedBaron
38626
answered Apr 3 at 7:40
RedBaronRedBaron
38626
answered Apr 3 at 7:40
RedBaronRedBaron
38626
38626
5
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
add a comment |
5
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
5
5
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
$begingroup$
Nice job! You got it! Side note: I actually used this (and all other password puzzles I post) as my password and I don't think I've forgotten one yet :) I like numbers!
$endgroup$
– Tyler22Alex
Apr 3 at 14:29
add a comment |
$begingroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
answered Apr 2 at 19:49
AProughAPrough
5,9061245
$endgroup$
1
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
1
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
add a comment |
$begingroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
answered Apr 2 at 19:49
AProughAPrough
5,9061245
$endgroup$
1
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
1
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
add a comment |
$begingroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
answered Apr 2 at 19:49
AProughAPrough
5,9061245
$endgroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
answered Apr 2 at 19:49
AProughAPrough
5,9061245
answered Apr 2 at 19:49
AProughAPrough
5,9061245
answered Apr 2 at 19:49
AProughAPrough
5,9061245
answered Apr 2 at 19:49
AProughAPrough
5,9061245
5,9061245
1
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
1
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
add a comment |
1
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
1
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
1
1
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
Apr 3 at 0:36
1
1
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
Apr 3 at 0:44
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
$begingroup$
Yeah, answer was from before the hints. Nice puzzle though.
$endgroup$
– APrough
Apr 3 at 15:06
add a comment |
$begingroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,60821073
$endgroup$
7
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
1
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
add a comment |
$begingroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,60821073
$endgroup$
7
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
1
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
add a comment |
$begingroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,60821073
$endgroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,60821073
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,60821073
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,60821073
answered Apr 2 at 17:25
Joe-You-KnowJoe-You-Know
6,60821073
6,60821073
7
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
1
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
add a comment |
7
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
1
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
7
7
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
Apr 2 at 18:20
1
1
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
$begingroup$
On the right track with Armstrong, but looking in the wrong direction for the number. Maybe what you've got so far and my second hint will get you closer!
$endgroup$
– Tyler22Alex
Apr 3 at 4:31
add a comment |
$begingroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
answered Apr 2 at 21:21
user1812user1812
912
$endgroup$
1
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
1
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
add a comment |
$begingroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
answered Apr 2 at 21:21
user1812user1812
912
$endgroup$
1
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
1
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
add a comment |
$begingroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
answered Apr 2 at 21:21
user1812user1812
912
$endgroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
answered Apr 2 at 21:21
user1812user1812
912
answered Apr 2 at 21:21
user1812user1812
912
answered Apr 2 at 21:21
user1812user1812
912
answered Apr 2 at 21:21
user1812user1812
912
912
1
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
1
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
add a comment |
1
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
1
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
1
1
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
Apr 3 at 0:28
1
1
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
I think this was posted before I added the first hint, so I apologize for that, but good thinking nonetheless!
$endgroup$
– Tyler22Alex
Apr 3 at 4:36
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
$begingroup$
@Tyler22Alex oh, it was? My bad. (Also, is it nevertheless or nonetheless...? Or are they interchangeable?)
$endgroup$
– user477343
Apr 3 at 11:03
add a comment |
$begingroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
2,640537
$endgroup$
1
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
1
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
add a comment |
$begingroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
2,640537
$endgroup$
1
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
1
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
add a comment |
$begingroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
2,640537
$endgroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
2,640537
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
2,640537
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
2,640537
answered Apr 2 at 19:07
PiIsNot3PiIsNot3
2,640537
2,640537
1
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
1
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
add a comment |
1
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
1
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
1
1
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
Apr 3 at 0:37
1
1
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
$begingroup$
Interesting idea! However I think you posted this before I added the first hint, so I apologize for that.
$endgroup$
– Tyler22Alex
Apr 3 at 4:34
add a comment |
$begingroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
$endgroup$
1
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
add a comment |
$begingroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
$endgroup$
1
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
add a comment |
$begingroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
$endgroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
answered Apr 2 at 22:14
Rubio♦Rubio
30.5k567188
30.5k567188
1
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
add a comment |
1
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
1
1
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
$begingroup$
Hopefully my hint helped a bit, and I'll add more hints as time goes by if people still aren't getting it.
$endgroup$
– Tyler22Alex
Apr 3 at 4:33
add a comment |
$begingroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
answered Apr 2 at 21:05
tuvokkituvokki
1312
$endgroup$
1
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
add a comment |
$begingroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
answered Apr 2 at 21:05
tuvokkituvokki
1312
$endgroup$
1
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
add a comment |
$begingroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
answered Apr 2 at 21:05
tuvokkituvokki
1312
$endgroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
answered Apr 2 at 21:05
tuvokkituvokki
1312
answered Apr 2 at 21:05
tuvokkituvokki
1312
answered Apr 2 at 21:05
tuvokkituvokki
1312
answered Apr 2 at 21:05
tuvokkituvokki
1312
1312
1
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
add a comment |
1
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
1
1
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
$begingroup$
Good thinking but not quite! Maybe look at the hints I added. Good luck!
$endgroup$
– Tyler22Alex
Apr 3 at 4:35
add a comment |
$begingroup$
The answer is
9.5 Because it's the boot size Neil Armstrong had when first setting foot on the moon.
Thus it was "the largest number to be first on the moon"
answered Apr 3 at 12:52
PeterPeter
2006
$endgroup$
add a comment |
$begingroup$
The answer is
9.5 Because it's the boot size Neil Armstrong had when first setting foot on the moon.
Thus it was "the largest number to be first on the moon"
answered Apr 3 at 12:52
PeterPeter
2006
$endgroup$
add a comment |
$begingroup$
The answer is
9.5 Because it's the boot size Neil Armstrong had when first setting foot on the moon.
Thus it was "the largest number to be first on the moon"
answered Apr 3 at 12:52
PeterPeter
2006
$endgroup$
The answer is
9.5 Because it's the boot size Neil Armstrong had when first setting foot on the moon.
Thus it was "the largest number to be first on the moon"
answered Apr 3 at 12:52
PeterPeter
2006
answered Apr 3 at 12:52
PeterPeter
2006
answered Apr 3 at 12:52
PeterPeter
2006
answered Apr 3 at 12:52
PeterPeter
2006
2006
add a comment |
add a comment |
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1
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
Apr 2 at 22:30
2
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
Apr 3 at 0:32