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Why would five hundred and five be same as one?

What's the teacher's fractional addition algorithm?One hundred and one hatsGrandpa can't even tell time? Another Grandpa Mystery1 = 2? A Non-Math RiddleSimple Math Problem #3$6$ is prime? Another Grandpa Mystery (not made by @DEEM, this time)A Body Part inside another Body PartMy Grandpa's Box #1Can 4 = 6 and 10 = 1000? : Another Grandpa QuestionI walked uphill both ways

8

2

$begingroup$

Grandpa was in his crazy math mood again.

"using rot13 and your math knowledge prove to me that

505 = 1"

He said.

Really? Can you?

HINT

Think Trigonometry

riddle mathematics lateral-thinking

share|improve this question

edited Mar 20 at 20:48

JonMark Perry

20.4k64099

asked Mar 19 at 13:02

DEEMDEEM

6,483121116

$endgroup$

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  $begingroup$
  Don't have an answer, but I'll note 2 findings given the hint: 1) 505 is the hypotenuse of a triangle with integer length sides. 2) Rot13-ing the Roman Numerals for the number 105 produces a trigonometric term. Maybe one of these is on the right path and will help someone.
  $endgroup$
  – TwoBitOperation
  Mar 20 at 14:40
  
  

  
  
  
  


• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  @TwoBitOperation for anyone possibly going with route 1: The possible sides of a triangle that work are (100, 495) (217, 456) (303, 404) (336, 377)
  $endgroup$
  – akozi
  Mar 20 at 16:28
  

  
  
  
  

add a comment | 

8

2

$begingroup$

Grandpa was in his crazy math mood again.

"using rot13 and your math knowledge prove to me that

505 = 1"

He said.

Really? Can you?

HINT

Think Trigonometry

riddle mathematics lateral-thinking

share|improve this question

edited Mar 20 at 20:48

JonMark Perry

20.4k64099

asked Mar 19 at 13:02

DEEMDEEM

6,483121116

$endgroup$

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  $begingroup$
  Don't have an answer, but I'll note 2 findings given the hint: 1) 505 is the hypotenuse of a triangle with integer length sides. 2) Rot13-ing the Roman Numerals for the number 105 produces a trigonometric term. Maybe one of these is on the right path and will help someone.
  $endgroup$
  – TwoBitOperation
  Mar 20 at 14:40
  
  

  
  
  
  


• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  @TwoBitOperation for anyone possibly going with route 1: The possible sides of a triangle that work are (100, 495) (217, 456) (303, 404) (336, 377)
  $endgroup$
  – akozi
  Mar 20 at 16:28
  

  
  
  
  

add a comment | 

$begingroup$

Grandpa was in his crazy math mood again.

"using rot13 and your math knowledge prove to me that

505 = 1"

He said.

Really? Can you?

HINT

Think Trigonometry

riddle mathematics lateral-thinking

share|improve this question

edited Mar 20 at 20:48

JonMark Perry

20.4k64099

asked Mar 19 at 13:02

DEEMDEEM

6,483121116

$endgroup$

share|improve this question

edited Mar 20 at 20:48

JonMark Perry

20.4k64099

asked Mar 19 at 13:02

DEEMDEEM

6,483121116

share|improve this question

edited Mar 20 at 20:48

JonMark Perry

20.4k64099

asked Mar 19 at 13:02

DEEMDEEM

6,483121116

edited Mar 20 at 20:48

JonMark Perry

20.4k64099

edited Mar 20 at 20:48

JonMark Perry

20.4k64099

asked Mar 19 at 13:02

DEEMDEEM

6,483121116

asked Mar 19 at 13:02

DEEMDEEM

6,483121116

9 Answers
9

active

oldest

votes

22

$begingroup$

Here's one possible solution:

1. $505 = 1$ : Given

2. $DV = 1$ : By Romanizing left

3. $V = 1/D$

4. $CV = C/D$ : Multiply through by 100

5. $(PI)= C/D$ : By Rot(13)ing left

6. $Dπ = C$


By the circumference formula for a circle (C= πD),the left and right are equivalent

Q.E.D.

share|improve this answer

edited Mar 20 at 20:32

answered Mar 20 at 20:19

TwoBitOperationTwoBitOperation

7,91711364

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  11
  

  
  
  
  
  
  

  
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  Wow. If that's the intended solution I'll be quite surprised. Regardless, that's an amazingly convoluted way to answer this, and I love it. :)
  $endgroup$
  – Rubio♦
  Mar 20 at 20:51
  

  
  
  
  


• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
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  I'm... just as surprised as everyone else here.
  $endgroup$
  – TwoBitOperation
  Mar 20 at 21:44
  

  
  
  
  


• 
  
  
  

  
  8
  

  
  
  
  
  
  

  
  $begingroup$
  @DEEM What does this have to do with trigonometry?
  $endgroup$
  – noedne
  Mar 20 at 21:53
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  $begingroup$
  wouldn't step 5 require you to to do both sides, yielding P/Q?
  $endgroup$
  – corsiKa
  Mar 21 at 0:49
  

  
  
  
  


• 
  
  
  

  
  8
  

  
  
  
  
  
  

  
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  Step 2 to 3 doesn't make sense, as Roman numerals are additive, not multiplicative.
  $endgroup$
  – Herb Wolfe
  Mar 21 at 3:19
  

  
  
  
  

 | 
show 4 more comments

40

$begingroup$

Reasoning

In Roman numerals 505 is DV. If we use rot13 on these two characters, we get QI.
Qi is the circulating life force whose existence and properties are the basis of much Chinese philosophy and medicine. It allows us to say that we are one with the universe. In this way, 505=1

share|improve this answer

answered Mar 19 at 13:08

hexominohexomino

44.6k4136215

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• 
  
  
  

  
  

  
  
  
  
  
  

  
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  Lot different than my answer
  $endgroup$
  – DEEM
  Mar 19 at 13:10
  

  
  
  
  


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  1
  

  
  
  
  
  
  

  
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  @DEEM Can you tell us a way in which your answer differs from this answer?
  $endgroup$
  – Tanner Swett
  Mar 19 at 18:48
  

  
  
  
  


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  1
  

  
  
  
  
  
  

  
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  So there is the rot13 part and there is the math part. Both are needed for my answer
  $endgroup$
  – DEEM
  Mar 20 at 1:36
  

  
  
  
  

add a comment | 

26

$begingroup$

By using

hexomino's idea of ROT13 on Roman numerals

we can obtain

$textROT13(505)=textROT13(V^4-V^3+V)=I^4-I^3+I=1$.

share|improve this answer

answered Mar 19 at 15:27

noednenoedne

7,50212159

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  Could you (or one of the 22 upvoters) explain the last step to me?
  $endgroup$
  – user1717828
  Mar 21 at 1:35
  
  

  
  
  
  


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  @user1717828 $I$ is the Roman numeral for $1$, so $I^4-I^3+I=1^4-1^3+1=1-1+1=1$.
  $endgroup$
  – noedne
  Mar 21 at 2:03
  

  
  
  
  


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  Ahh!! I did the complex math out like three times before submitting to Google to confirm I wasn't crazy. No idea what I was thinking. Thanks!
  $endgroup$
  – user1717828
  Mar 21 at 10:46
  

  
  
  
  

add a comment | 

6

$begingroup$

The rot13 translation of "one" is "bar". The only connection between "bar" and 505 that I could find is this very obscure definition given in urban dictionary (which was entry #4 and has more downvotes than upvotes), which says that it's slang for getting a drink at a bar with friends after work. Perhaps it's a really old outdated slang term, which is why your grandpa used it.

share|improve this answer

answered Mar 19 at 16:38

BridgeburnersBridgeburners

1612

New contributor

Bridgeburners is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Beer O'Clock, Can't be any different to 4:20 or the Masonic arguments pertaining to yardarms or the time of day, It's beer O'Clock somewhere in the world. In the olden days 505 meant OOO. We left at 5pm.
  $endgroup$
  – mckenzm
  Mar 21 at 5:42
  

  
  
  
  

add a comment | 

5

$begingroup$

Elaborating on @hexomino answer 505 -> DV.

Is it possible that:

I want to DownVote you 505 times which was odd number resulting 1 DV.
var num=505; isOdd(num); function isOdd(num) return num % 2;

_{I'm not downvoting you.}

share|improve this answer

answered Mar 20 at 10:24

MukyuuMukyuu

4361113

$endgroup$

add a comment | 

1

$begingroup$

Use the digital radix: 5 + 0 + 5 = 10, 1 + 0 = 1

share|improve this answer

answered Mar 19 at 15:11

LurkerLurker

111

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Lurker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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• 
  
  
  

  
  11
  

  
  
  
  
  
  

  
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  And where is Rot13 used?
  $endgroup$
  – Chronocidal
  Mar 19 at 15:58
  

  
  
  
  

add a comment | 

0

$begingroup$

Working out possible solutions using rot13 and trig:

I feel gross and like I'm doing something wrong doing this but:

505 = 5 * 101 => V * CI

Then you:

rot13(V * CI) = I * PI => i * pi (getting pi honestly is the only reason I think this might be the right direction.

Here's where the rot13(gevt) comes in I guess? Not sure where to proceed from there.

share|improve this answer

answered Mar 20 at 20:06

Nick VithaNick Vitha

774

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$endgroup$

• 
  
  
  

  
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  $begingroup$
  rot13 of I is not I.
  $endgroup$
  – Rubio♦
  Mar 20 at 20:53
  

  
  
  
  


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  1
  

  
  
  
  
  
  

  
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  Well I'm an idiot.
  $endgroup$
  – Nick Vitha
  Mar 20 at 21:05
  

  
  
  
  

add a comment | 

0

$begingroup$

Tongue in cheek answer - technically works anyhow ;-)

050/5 rdhnyf 6/5 gurersber 050 rdhnyf 6. "Cebirq" hfvat zngu xabjyrqtr naq ebg68, nf erdhrfgrq ;-)

Rot13 a_zA-Z0-9

share|improve this answer

answered Mar 20 at 22:39

StilezStilez

1,204211

$endgroup$

add a comment | 

0

$begingroup$

If you use a "fivethousandfiftydecimal" base then 505 in this base is equal to 1 in decimal base.
Just like 12 in octal base is equal to 10 in decimal base.

share|improve this answer

answered Mar 21 at 11:07

BaudoisBaudois

1

New contributor

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Check out our Code of Conduct.

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
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  Welcome to Puzzling.SE! I like the lateral thinking in this answer, but I'm afraid it doesn't quite answer the question, since it doesn't use rot13.
  $endgroup$
  – Brandon_J
  Mar 21 at 13:27
  

  
  
  
  

add a comment | 

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22

$begingroup$

Here's one possible solution:

1. $505 = 1$ : Given

2. $DV = 1$ : By Romanizing left

3. $V = 1/D$

4. $CV = C/D$ : Multiply through by 100

5. $(PI)= C/D$ : By Rot(13)ing left

6. $Dπ = C$


By the circumference formula for a circle (C= πD),the left and right are equivalent

Q.E.D.

share|improve this answer

edited Mar 20 at 20:32

answered Mar 20 at 20:19

TwoBitOperationTwoBitOperation

7,91711364

$endgroup$

• 
  
  
  

  
  11
  

  
  
  
  
  
  

  
  $begingroup$
  Wow. If that's the intended solution I'll be quite surprised. Regardless, that's an amazingly convoluted way to answer this, and I love it. :)
  $endgroup$
  – Rubio♦
  Mar 20 at 20:51
  

  
  
  
  


• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  $begingroup$
  I'm... just as surprised as everyone else here.
  $endgroup$
  – TwoBitOperation
  Mar 20 at 21:44
  

  
  
  
  


• 
  
  
  

  
  8
  

  
  
  
  
  
  

  
  $begingroup$
  @DEEM What does this have to do with trigonometry?
  $endgroup$
  – noedne
  Mar 20 at 21:53
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  $begingroup$
  wouldn't step 5 require you to to do both sides, yielding P/Q?
  $endgroup$
  – corsiKa
  Mar 21 at 0:49
  

  
  
  
  


• 
  
  
  

  
  8
  

  
  
  
  
  
  

  
  $begingroup$
  Step 2 to 3 doesn't make sense, as Roman numerals are additive, not multiplicative.
  $endgroup$
  – Herb Wolfe
  Mar 21 at 3:19
  

  
  
  
  

 | 
show 4 more comments

22

$begingroup$

Here's one possible solution:

1. $505 = 1$ : Given

2. $DV = 1$ : By Romanizing left

3. $V = 1/D$

4. $CV = C/D$ : Multiply through by 100

5. $(PI)= C/D$ : By Rot(13)ing left

6. $Dπ = C$


By the circumference formula for a circle (C= πD),the left and right are equivalent

Q.E.D.

share|improve this answer

edited Mar 20 at 20:32

answered Mar 20 at 20:19

TwoBitOperationTwoBitOperation

7,91711364

$endgroup$

• 
  
  
  

  
  11
  

  
  
  
  
  
  

  
  $begingroup$
  Wow. If that's the intended solution I'll be quite surprised. Regardless, that's an amazingly convoluted way to answer this, and I love it. :)
  $endgroup$
  – Rubio♦
  Mar 20 at 20:51
  

  
  
  
  


• 
  
  
  

  
  5
  

  
  
  
  
  
  

  
  $begingroup$
  I'm... just as surprised as everyone else here.
  $endgroup$
  – TwoBitOperation
  Mar 20 at 21:44
  

  
  
  
  


• 
  
  
  

  
  8
  

  
  
  
  
  
  

  
  $begingroup$
  @DEEM What does this have to do with trigonometry?
  $endgroup$
  – noedne
  Mar 20 at 21:53
  

  
  
  
  


• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  $begingroup$
  wouldn't step 5 require you to to do both sides, yielding P/Q?
  $endgroup$
  – corsiKa
  Mar 21 at 0:49
  

  
  
  
  


• 
  
  
  

  
  8
  

  
  
  
  
  
  

  
  $begingroup$
  Step 2 to 3 doesn't make sense, as Roman numerals are additive, not multiplicative.
  $endgroup$
  – Herb Wolfe
  Mar 21 at 3:19
  

  
  
  
  

 | 
show 4 more comments

$begingroup$

Here's one possible solution:

1. $505 = 1$ : Given

2. $DV = 1$ : By Romanizing left

3. $V = 1/D$

4. $CV = C/D$ : Multiply through by 100

5. $(PI)= C/D$ : By Rot(13)ing left

6. $Dπ = C$


By the circumference formula for a circle (C= πD),the left and right are equivalent

Q.E.D.

share|improve this answer

edited Mar 20 at 20:32

answered Mar 20 at 20:19

TwoBitOperationTwoBitOperation

7,91711364

$endgroup$

share|improve this answer

edited Mar 20 at 20:32

answered Mar 20 at 20:19

TwoBitOperationTwoBitOperation

7,91711364

answered Mar 20 at 20:19

TwoBitOperationTwoBitOperation

7,91711364

answered Mar 20 at 20:19

TwoBitOperationTwoBitOperation

7,91711364

40

$begingroup$

Reasoning

In Roman numerals 505 is DV. If we use rot13 on these two characters, we get QI.
Qi is the circulating life force whose existence and properties are the basis of much Chinese philosophy and medicine. It allows us to say that we are one with the universe. In this way, 505=1

share|improve this answer

answered Mar 19 at 13:08

hexominohexomino

44.6k4136215

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• 
  
  
  

  
  

  
  
  
  
  
  

  
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  Lot different than my answer
  $endgroup$
  – DEEM
  Mar 19 at 13:10
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  @DEEM Can you tell us a way in which your answer differs from this answer?
  $endgroup$
  – Tanner Swett
  Mar 19 at 18:48
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  So there is the rot13 part and there is the math part. Both are needed for my answer
  $endgroup$
  – DEEM
  Mar 20 at 1:36
  

  
  
  
  

add a comment | 

40

$begingroup$

Reasoning

In Roman numerals 505 is DV. If we use rot13 on these two characters, we get QI.
Qi is the circulating life force whose existence and properties are the basis of much Chinese philosophy and medicine. It allows us to say that we are one with the universe. In this way, 505=1

share|improve this answer

answered Mar 19 at 13:08

hexominohexomino

44.6k4136215

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Lot different than my answer
  $endgroup$
  – DEEM
  Mar 19 at 13:10
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  @DEEM Can you tell us a way in which your answer differs from this answer?
  $endgroup$
  – Tanner Swett
  Mar 19 at 18:48
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  So there is the rot13 part and there is the math part. Both are needed for my answer
  $endgroup$
  – DEEM
  Mar 20 at 1:36
  

  
  
  
  

add a comment | 

$begingroup$

Reasoning

In Roman numerals 505 is DV. If we use rot13 on these two characters, we get QI.
Qi is the circulating life force whose existence and properties are the basis of much Chinese philosophy and medicine. It allows us to say that we are one with the universe. In this way, 505=1

share|improve this answer

answered Mar 19 at 13:08

hexominohexomino

44.6k4136215

$endgroup$

share|improve this answer

answered Mar 19 at 13:08

hexominohexomino

44.6k4136215

answered Mar 19 at 13:08

hexominohexomino

44.6k4136215

answered Mar 19 at 13:08

hexominohexomino

44.6k4136215

26

$begingroup$

By using

hexomino's idea of ROT13 on Roman numerals

we can obtain

$textROT13(505)=textROT13(V^4-V^3+V)=I^4-I^3+I=1$.

share|improve this answer

answered Mar 19 at 15:27

noednenoedne

7,50212159

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  Could you (or one of the 22 upvoters) explain the last step to me?
  $endgroup$
  – user1717828
  Mar 21 at 1:35
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
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  @user1717828 $I$ is the Roman numeral for $1$, so $I^4-I^3+I=1^4-1^3+1=1-1+1=1$.
  $endgroup$
  – noedne
  Mar 21 at 2:03
  

  
  
  
  


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  Ahh!! I did the complex math out like three times before submitting to Google to confirm I wasn't crazy. No idea what I was thinking. Thanks!
  $endgroup$
  – user1717828
  Mar 21 at 10:46
  

  
  
  
  

add a comment | 

26

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By using

hexomino's idea of ROT13 on Roman numerals

we can obtain

$textROT13(505)=textROT13(V^4-V^3+V)=I^4-I^3+I=1$.

share|improve this answer

answered Mar 19 at 15:27

noednenoedne

7,50212159

$endgroup$

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  Could you (or one of the 22 upvoters) explain the last step to me?
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  – user1717828
  Mar 21 at 1:35
  
  

  
  
  
  


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  @user1717828 $I$ is the Roman numeral for $1$, so $I^4-I^3+I=1^4-1^3+1=1-1+1=1$.
  $endgroup$
  – noedne
  Mar 21 at 2:03
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Ahh!! I did the complex math out like three times before submitting to Google to confirm I wasn't crazy. No idea what I was thinking. Thanks!
  $endgroup$
  – user1717828
  Mar 21 at 10:46
  

  
  
  
  

add a comment | 

$begingroup$

By using

hexomino's idea of ROT13 on Roman numerals

we can obtain

$textROT13(505)=textROT13(V^4-V^3+V)=I^4-I^3+I=1$.

share|improve this answer

answered Mar 19 at 15:27

noednenoedne

7,50212159

$endgroup$

share|improve this answer

answered Mar 19 at 15:27

noednenoedne

7,50212159

answered Mar 19 at 15:27

noednenoedne

7,50212159

answered Mar 19 at 15:27

noednenoedne

7,50212159

6

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The rot13 translation of "one" is "bar". The only connection between "bar" and 505 that I could find is this very obscure definition given in urban dictionary (which was entry #4 and has more downvotes than upvotes), which says that it's slang for getting a drink at a bar with friends after work. Perhaps it's a really old outdated slang term, which is why your grandpa used it.

share|improve this answer

answered Mar 19 at 16:38

BridgeburnersBridgeburners

1612

New contributor

Bridgeburners is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
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  Beer O'Clock, Can't be any different to 4:20 or the Masonic arguments pertaining to yardarms or the time of day, It's beer O'Clock somewhere in the world. In the olden days 505 meant OOO. We left at 5pm.
  $endgroup$
  – mckenzm
  Mar 21 at 5:42
  

  
  
  
  

add a comment | 

6

$begingroup$

The rot13 translation of "one" is "bar". The only connection between "bar" and 505 that I could find is this very obscure definition given in urban dictionary (which was entry #4 and has more downvotes than upvotes), which says that it's slang for getting a drink at a bar with friends after work. Perhaps it's a really old outdated slang term, which is why your grandpa used it.

share|improve this answer

answered Mar 19 at 16:38

BridgeburnersBridgeburners

1612

New contributor

Bridgeburners is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Beer O'Clock, Can't be any different to 4:20 or the Masonic arguments pertaining to yardarms or the time of day, It's beer O'Clock somewhere in the world. In the olden days 505 meant OOO. We left at 5pm.
  $endgroup$
  – mckenzm
  Mar 21 at 5:42
  

  
  
  
  

add a comment | 

$begingroup$

The rot13 translation of "one" is "bar". The only connection between "bar" and 505 that I could find is this very obscure definition given in urban dictionary (which was entry #4 and has more downvotes than upvotes), which says that it's slang for getting a drink at a bar with friends after work. Perhaps it's a really old outdated slang term, which is why your grandpa used it.

share|improve this answer

answered Mar 19 at 16:38

BridgeburnersBridgeburners

1612

New contributor

Bridgeburners is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

share|improve this answer

answered Mar 19 at 16:38

BridgeburnersBridgeburners

1612

New contributor

Bridgeburners is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

answered Mar 19 at 16:38

BridgeburnersBridgeburners

1612

New contributor

Bridgeburners is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

answered Mar 19 at 16:38

BridgeburnersBridgeburners

1612

5

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Elaborating on @hexomino answer 505 -> DV.

Is it possible that:

I want to DownVote you 505 times which was odd number resulting 1 DV.
var num=505; isOdd(num); function isOdd(num) return num % 2;

_{I'm not downvoting you.}

share|improve this answer

answered Mar 20 at 10:24

MukyuuMukyuu

4361113

$endgroup$

add a comment | 

5

$begingroup$

Elaborating on @hexomino answer 505 -> DV.

Is it possible that:

I want to DownVote you 505 times which was odd number resulting 1 DV.
var num=505; isOdd(num); function isOdd(num) return num % 2;

_{I'm not downvoting you.}

share|improve this answer

answered Mar 20 at 10:24

MukyuuMukyuu

4361113

$endgroup$

add a comment | 

$begingroup$

Elaborating on @hexomino answer 505 -> DV.

Is it possible that:

I want to DownVote you 505 times which was odd number resulting 1 DV.
var num=505; isOdd(num); function isOdd(num) return num % 2;

_{I'm not downvoting you.}

share|improve this answer

answered Mar 20 at 10:24

MukyuuMukyuu

4361113

$endgroup$