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tikz grid without top edge


TikZ (finite) grid with character in each cellLaTeX equivalent of ConTeXt buffersHow to define the default vertical distance between nodes?Numerical conditional within tikz keys?TikZ/ERD: node (=Entity) label on the insideWhy do I get an extra white page before my TikZ picture?TikZ: Drawing an arc from an intersection to an intersectionHow to prevent rounded and duplicated tick labels in pgfplots with fixed precision?Drawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themHow to draw a square and its diagonals with arrows?













4















In this code from TikZ (finite) grid with character in each cell



documentclassarticle
usepackagetikz
usetikzlibrarymatrix

begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument


I would like to delete the top and left edges of the grid.



I have found solutions using nodes but much prefer this one with a matrix.










share|improve this question






















  • Off topic: You have a very nice reputation number :)

    – JouleV
    Mar 25 at 13:35











  • @JouleV Indeed, It won't survive any votes on this question.

    – Ethan Bolker
    Mar 25 at 13:36















4















In this code from TikZ (finite) grid with character in each cell



documentclassarticle
usepackagetikz
usetikzlibrarymatrix

begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument


I would like to delete the top and left edges of the grid.



I have found solutions using nodes but much prefer this one with a matrix.










share|improve this question






















  • Off topic: You have a very nice reputation number :)

    – JouleV
    Mar 25 at 13:35











  • @JouleV Indeed, It won't survive any votes on this question.

    – Ethan Bolker
    Mar 25 at 13:36













4












4








4








In this code from TikZ (finite) grid with character in each cell



documentclassarticle
usepackagetikz
usetikzlibrarymatrix

begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument


I would like to delete the top and left edges of the grid.



I have found solutions using nodes but much prefer this one with a matrix.










share|improve this question














In this code from TikZ (finite) grid with character in each cell



documentclassarticle
usepackagetikz
usetikzlibrarymatrix

begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument


I would like to delete the top and left edges of the grid.



I have found solutions using nodes but much prefer this one with a matrix.







tikz-pgf






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 25 at 13:31









Ethan BolkerEthan Bolker

6,69832453




6,69832453












  • Off topic: You have a very nice reputation number :)

    – JouleV
    Mar 25 at 13:35











  • @JouleV Indeed, It won't survive any votes on this question.

    – Ethan Bolker
    Mar 25 at 13:36

















  • Off topic: You have a very nice reputation number :)

    – JouleV
    Mar 25 at 13:35











  • @JouleV Indeed, It won't survive any votes on this question.

    – Ethan Bolker
    Mar 25 at 13:36
















Off topic: You have a very nice reputation number :)

– JouleV
Mar 25 at 13:35





Off topic: You have a very nice reputation number :)

– JouleV
Mar 25 at 13:35













@JouleV Indeed, It won't survive any votes on this question.

– Ethan Bolker
Mar 25 at 13:36





@JouleV Indeed, It won't survive any votes on this question.

– Ethan Bolker
Mar 25 at 13:36










2 Answers
2






active

oldest

votes


















4














We can use foreach:



documentclass[tikz]standalone
usetikzlibrarymatrix

begindocument
begintikzpicture
%draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
foreach i in -0.5,0,0.5,1
draw[gray] (-1,-i)--(1,-i);
draw[gray] (i,-1)--(i,1);

matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument


enter image description here



Honestly I don't think nodes or matrices have any thing to do here.




This approach is based on marmot's creative way, which is nicer and more tricky:



documentclass[tikz]standalone
usetikzlibrarymatrix

begindocument
begintikzpicture
draw[step=0.5cm,color=gray] (-1cm+0.2pt,-1) grid (1cm,1cm-0.2pt);
matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
endtikzpicture
enddocument


enter image description here






share|improve this answer




















  • 1





    Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

    – Ethan Bolker
    Mar 25 at 13:46











  • @EthanBolker No problem. You are welcome ;)

    – JouleV
    Mar 25 at 13:47











  • Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

    – marmot
    Mar 25 at 15:15











  • @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

    – JouleV
    Mar 25 at 15:17











  • @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

    – marmot
    Mar 25 at 15:18


















3














Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.



documentclass[tikz,border=2mm]standalone
usetikzlibrarymatrix

begindocument
begintikzpicture
matrix[matrix of nodes,nodes=draw=gray, anchor=center, minimum size=.6cm, column sep=-pgflinewidth, row sep=-pgflinewidth] (A)
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\;
draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
endtikzpicture
enddocument


enter image description here






share|improve this answer























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    2 Answers
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    active

    oldest

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    We can use foreach:



    documentclass[tikz]standalone
    usetikzlibrarymatrix

    begindocument
    begintikzpicture
    %draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
    foreach i in -0.5,0,0.5,1
    draw[gray] (-1,-i)--(1,-i);
    draw[gray] (i,-1)--(i,1);

    matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\;
    endtikzpicture
    enddocument


    enter image description here



    Honestly I don't think nodes or matrices have any thing to do here.




    This approach is based on marmot's creative way, which is nicer and more tricky:



    documentclass[tikz]standalone
    usetikzlibrarymatrix

    begindocument
    begintikzpicture
    draw[step=0.5cm,color=gray] (-1cm+0.2pt,-1) grid (1cm,1cm-0.2pt);
    matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\;
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer




















    • 1





      Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

      – Ethan Bolker
      Mar 25 at 13:46











    • @EthanBolker No problem. You are welcome ;)

      – JouleV
      Mar 25 at 13:47











    • Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

      – marmot
      Mar 25 at 15:15











    • @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

      – JouleV
      Mar 25 at 15:17











    • @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

      – marmot
      Mar 25 at 15:18















    4














    We can use foreach:



    documentclass[tikz]standalone
    usetikzlibrarymatrix

    begindocument
    begintikzpicture
    %draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
    foreach i in -0.5,0,0.5,1
    draw[gray] (-1,-i)--(1,-i);
    draw[gray] (i,-1)--(i,1);

    matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\;
    endtikzpicture
    enddocument


    enter image description here



    Honestly I don't think nodes or matrices have any thing to do here.




    This approach is based on marmot's creative way, which is nicer and more tricky:



    documentclass[tikz]standalone
    usetikzlibrarymatrix

    begindocument
    begintikzpicture
    draw[step=0.5cm,color=gray] (-1cm+0.2pt,-1) grid (1cm,1cm-0.2pt);
    matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\;
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer




















    • 1





      Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

      – Ethan Bolker
      Mar 25 at 13:46











    • @EthanBolker No problem. You are welcome ;)

      – JouleV
      Mar 25 at 13:47











    • Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

      – marmot
      Mar 25 at 15:15











    • @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

      – JouleV
      Mar 25 at 15:17











    • @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

      – marmot
      Mar 25 at 15:18













    4












    4








    4







    We can use foreach:



    documentclass[tikz]standalone
    usetikzlibrarymatrix

    begindocument
    begintikzpicture
    %draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
    foreach i in -0.5,0,0.5,1
    draw[gray] (-1,-i)--(1,-i);
    draw[gray] (i,-1)--(i,1);

    matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\;
    endtikzpicture
    enddocument


    enter image description here



    Honestly I don't think nodes or matrices have any thing to do here.




    This approach is based on marmot's creative way, which is nicer and more tricky:



    documentclass[tikz]standalone
    usetikzlibrarymatrix

    begindocument
    begintikzpicture
    draw[step=0.5cm,color=gray] (-1cm+0.2pt,-1) grid (1cm,1cm-0.2pt);
    matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\;
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer















    We can use foreach:



    documentclass[tikz]standalone
    usetikzlibrarymatrix

    begindocument
    begintikzpicture
    %draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
    foreach i in -0.5,0,0.5,1
    draw[gray] (-1,-i)--(1,-i);
    draw[gray] (i,-1)--(i,1);

    matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\;
    endtikzpicture
    enddocument


    enter image description here



    Honestly I don't think nodes or matrices have any thing to do here.




    This approach is based on marmot's creative way, which is nicer and more tricky:



    documentclass[tikz]standalone
    usetikzlibrarymatrix

    begindocument
    begintikzpicture
    draw[step=0.5cm,color=gray] (-1cm+0.2pt,-1) grid (1cm,1cm-0.2pt);
    matrix[matrix of nodes,nodes=inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm]
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\;
    endtikzpicture
    enddocument


    enter image description here







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Mar 25 at 15:25

























    answered Mar 25 at 13:39









    JouleVJouleV

    10.1k22558




    10.1k22558







    • 1





      Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

      – Ethan Bolker
      Mar 25 at 13:46











    • @EthanBolker No problem. You are welcome ;)

      – JouleV
      Mar 25 at 13:47











    • Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

      – marmot
      Mar 25 at 15:15











    • @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

      – JouleV
      Mar 25 at 15:17











    • @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

      – marmot
      Mar 25 at 15:18












    • 1





      Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

      – Ethan Bolker
      Mar 25 at 13:46











    • @EthanBolker No problem. You are welcome ;)

      – JouleV
      Mar 25 at 13:47











    • Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

      – marmot
      Mar 25 at 15:15











    • @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

      – JouleV
      Mar 25 at 15:17











    • @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

      – marmot
      Mar 25 at 15:18







    1




    1





    Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

    – Ethan Bolker
    Mar 25 at 13:46





    Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.

    – Ethan Bolker
    Mar 25 at 13:46













    @EthanBolker No problem. You are welcome ;)

    – JouleV
    Mar 25 at 13:47





    @EthanBolker No problem. You are welcome ;)

    – JouleV
    Mar 25 at 13:47













    Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

    – marmot
    Mar 25 at 15:15





    Maybe mention also draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.

    – marmot
    Mar 25 at 15:15













    @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

    – JouleV
    Mar 25 at 15:17





    @marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.

    – JouleV
    Mar 25 at 15:17













    @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

    – marmot
    Mar 25 at 15:18





    @JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.

    – marmot
    Mar 25 at 15:18











    3














    Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.



    documentclass[tikz,border=2mm]standalone
    usetikzlibrarymatrix

    begindocument
    begintikzpicture
    matrix[matrix of nodes,nodes=draw=gray, anchor=center, minimum size=.6cm, column sep=-pgflinewidth, row sep=-pgflinewidth] (A)
    A & B & C & D \
    E & F & & H \
    I & J & K & L \
    M & N & O & P\;
    draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer



























      3














      Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.



      documentclass[tikz,border=2mm]standalone
      usetikzlibrarymatrix

      begindocument
      begintikzpicture
      matrix[matrix of nodes,nodes=draw=gray, anchor=center, minimum size=.6cm, column sep=-pgflinewidth, row sep=-pgflinewidth] (A)
      A & B & C & D \
      E & F & & H \
      I & J & K & L \
      M & N & O & P\;
      draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
      endtikzpicture
      enddocument


      enter image description here






      share|improve this answer

























        3












        3








        3







        Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.



        documentclass[tikz,border=2mm]standalone
        usetikzlibrarymatrix

        begindocument
        begintikzpicture
        matrix[matrix of nodes,nodes=draw=gray, anchor=center, minimum size=.6cm, column sep=-pgflinewidth, row sep=-pgflinewidth] (A)
        A & B & C & D \
        E & F & & H \
        I & J & K & L \
        M & N & O & P\;
        draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
        endtikzpicture
        enddocument


        enter image description here






        share|improve this answer













        Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.



        documentclass[tikz,border=2mm]standalone
        usetikzlibrarymatrix

        begindocument
        begintikzpicture
        matrix[matrix of nodes,nodes=draw=gray, anchor=center, minimum size=.6cm, column sep=-pgflinewidth, row sep=-pgflinewidth] (A)
        A & B & C & D \
        E & F & & H \
        I & J & K & L \
        M & N & O & P\;
        draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
        endtikzpicture
        enddocument


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 25 at 16:03









        IgnasiIgnasi

        95.6k4175319




        95.6k4175319



























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