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Replace character with another only if repeated and not part of a word

Only match word outside a HTML statement with a regex“ReplaceWith” & - but only part of itRegExp regular expression find & replace whole words onlyJava regex - parts of wordsRegex match word groups and parts of previously matched word groupsWord replacement using regex if the target word is not a part of another wordreplace after “word” character by character in notepad ++?Why does `word (.(?!another-word))*?` match only a character?Replacing consecutive repeated characters in javareplacing part of a string but the part is very long

6

In Python3, the following code works to replace a string (two or more) of *'s with x's.

import re
re.sub(r'*(?=*)|(?<=*)*', 'x', 'Replace this *** but not this *')
# 'Replace this xxx but not this *'

But what if I also want to exempt a string of *'s that are part of a "word" like the following? (I.e. the string is attached to one or more [a-zA-Z] characters.)

text = "Don't replace foo*** or **bar, either."
# unmodified text expected

How do I do this? I can probably match the exempted cases as well and use a replacement function to deal with them, but is there a better way?

python regex python-3.x

share|improve this question

edited Mar 28 at 2:23

0m3r

8,04792554

asked Mar 28 at 2:04

bongbangbongbang

617720

add a comment | 

6

In Python3, the following code works to replace a string (two or more) of *'s with x's.

import re
re.sub(r'*(?=*)|(?<=*)*', 'x', 'Replace this *** but not this *')
# 'Replace this xxx but not this *'

But what if I also want to exempt a string of *'s that are part of a "word" like the following? (I.e. the string is attached to one or more [a-zA-Z] characters.)

text = "Don't replace foo*** or **bar, either."
# unmodified text expected

How do I do this? I can probably match the exempted cases as well and use a replacement function to deal with them, but is there a better way?

python regex python-3.x

share|improve this question

edited Mar 28 at 2:23

0m3r

8,04792554

asked Mar 28 at 2:04

bongbangbongbang

617720

add a comment | 

In Python3, the following code works to replace a string (two or more) of *'s with x's.

import re
re.sub(r'*(?=*)|(?<=*)*', 'x', 'Replace this *** but not this *')
# 'Replace this xxx but not this *'

But what if I also want to exempt a string of *'s that are part of a "word" like the following? (I.e. the string is attached to one or more [a-zA-Z] characters.)

text = "Don't replace foo*** or **bar, either."
# unmodified text expected

How do I do this? I can probably match the exempted cases as well and use a replacement function to deal with them, but is there a better way?

python regex python-3.x

share|improve this question

edited Mar 28 at 2:23

0m3r

8,04792554

asked Mar 28 at 2:04

bongbangbongbang

617720

import re
re.sub(r'*(?=*)|(?<=*)*', 'x', 'Replace this *** but not this *')
# 'Replace this xxx but not this *'

text = "Don't replace foo*** or **bar, either."
# unmodified text expected

share|improve this question

edited Mar 28 at 2:23

0m3r

8,04792554

asked Mar 28 at 2:04

bongbangbongbang

617720

share|improve this question

edited Mar 28 at 2:23

0m3r

8,04792554

asked Mar 28 at 2:04

bongbangbongbang

617720

edited Mar 28 at 2:23

0m3r

8,04792554

edited Mar 28 at 2:23

0m3r

8,04792554

asked Mar 28 at 2:04

bongbangbongbang

617720

asked Mar 28 at 2:04

bongbangbongbang

617720

2 Answers
2

active

oldest

votes

7

regex = r"s*2,[sn]"

This matches 2 or more * chars, surrounded by whitespace (or ended with a newline)

Call it maybe like this?

regex = r"s*2,[sn]"


def replacer(match):
 return 'x' * len(match.group())

re.sub(regex, replacer, your_string_here)

share|improve this answer

answered Mar 28 at 2:16

Danielle M.Danielle M.

2,2541623

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turn this **** string into this******string, which is not I want. It would also not replace **** this string, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.
  
  – bongbang
  Mar 28 at 2:40
  
  

  
  
  
  

add a comment | 

1

This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.

regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'

share|improve this answer

answered Mar 28 at 2:45

bongbangbongbang

617720

add a comment | 

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7

regex = r"s*2,[sn]"

This matches 2 or more * chars, surrounded by whitespace (or ended with a newline)

Call it maybe like this?

regex = r"s*2,[sn]"


def replacer(match):
 return 'x' * len(match.group())

re.sub(regex, replacer, your_string_here)

share|improve this answer

answered Mar 28 at 2:16

Danielle M.Danielle M.

2,2541623

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turn this **** string into this******string, which is not I want. It would also not replace **** this string, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.
  
  – bongbang
  Mar 28 at 2:40
  
  

  
  
  
  

add a comment | 

7

regex = r"s*2,[sn]"

This matches 2 or more * chars, surrounded by whitespace (or ended with a newline)

Call it maybe like this?

regex = r"s*2,[sn]"


def replacer(match):
 return 'x' * len(match.group())

re.sub(regex, replacer, your_string_here)

share|improve this answer

answered Mar 28 at 2:16

Danielle M.Danielle M.

2,2541623

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turn this **** string into this******string, which is not I want. It would also not replace **** this string, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.
  
  – bongbang
  Mar 28 at 2:40
  
  

  
  
  
  

add a comment | 

regex = r"s*2,[sn]"

This matches 2 or more * chars, surrounded by whitespace (or ended with a newline)

Call it maybe like this?

regex = r"s*2,[sn]"


def replacer(match):
 return 'x' * len(match.group())

re.sub(regex, replacer, your_string_here)

share|improve this answer

answered Mar 28 at 2:16

Danielle M.Danielle M.

2,2541623

regex = r"s*2,[sn]"

regex = r"s*2,[sn]"


def replacer(match):
 return 'x' * len(match.group())

re.sub(regex, replacer, your_string_here)

share|improve this answer

answered Mar 28 at 2:16

Danielle M.Danielle M.

2,2541623

answered Mar 28 at 2:16

Danielle M.Danielle M.

2,2541623

answered Mar 28 at 2:16

Danielle M.Danielle M.

2,2541623

1

This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.

regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'

share|improve this answer

answered Mar 28 at 2:45

bongbangbongbang

617720

add a comment | 

1

This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.

regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'

share|improve this answer

answered Mar 28 at 2:45

bongbangbongbang

617720

add a comment | 

This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.

regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'

share|improve this answer

answered Mar 28 at 2:45

bongbangbongbang

617720

regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'

share|improve this answer

answered Mar 28 at 2:45

bongbangbongbang

617720

answered Mar 28 at 2:45

bongbangbongbang

617720

answered Mar 28 at 2:45

bongbangbongbang

617720