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Fit as many overlapping generators as possible



The 2019 Stack Overflow Developer Survey Results Are InPuzzle that consists of all possible combinations of pieces containing 5 squaresIs it possible to build this out of soma cube parts?Tiling rectangles with Hexomino plus rectangle #3Max 4x1 pattern fit within 11x11 area










5












$begingroup$


Rimworld is a tile-based videogame. One of its constructibles in the wind generator:



enter image description here



The wind generator itself occupies a space of 7x2 and can be placed facing the 4 cardinal directions.



In order for it to work optimally, it is required that it has free (unoccupied) space for 10 tiles in front of it and 6 tiles to its back, for its entire 7 tile width, as shown in the image.



What is the optimal placement for wind generators, ie most generators per area?



For an answer I expect a description or even better an image which explains the setup, and a percentage of tiles used by the generators. In order to calculate this percentage, we have to be able to isolate a (hopefully rectangular!) area which can be validly replicated when tiled in the map. I will make a first (obvious and probably suboptimal) answer to showcase this.










share|improve this question









$endgroup$
















    5












    $begingroup$


    Rimworld is a tile-based videogame. One of its constructibles in the wind generator:



    enter image description here



    The wind generator itself occupies a space of 7x2 and can be placed facing the 4 cardinal directions.



    In order for it to work optimally, it is required that it has free (unoccupied) space for 10 tiles in front of it and 6 tiles to its back, for its entire 7 tile width, as shown in the image.



    What is the optimal placement for wind generators, ie most generators per area?



    For an answer I expect a description or even better an image which explains the setup, and a percentage of tiles used by the generators. In order to calculate this percentage, we have to be able to isolate a (hopefully rectangular!) area which can be validly replicated when tiled in the map. I will make a first (obvious and probably suboptimal) answer to showcase this.










    share|improve this question









    $endgroup$














      5












      5








      5





      $begingroup$


      Rimworld is a tile-based videogame. One of its constructibles in the wind generator:



      enter image description here



      The wind generator itself occupies a space of 7x2 and can be placed facing the 4 cardinal directions.



      In order for it to work optimally, it is required that it has free (unoccupied) space for 10 tiles in front of it and 6 tiles to its back, for its entire 7 tile width, as shown in the image.



      What is the optimal placement for wind generators, ie most generators per area?



      For an answer I expect a description or even better an image which explains the setup, and a percentage of tiles used by the generators. In order to calculate this percentage, we have to be able to isolate a (hopefully rectangular!) area which can be validly replicated when tiled in the map. I will make a first (obvious and probably suboptimal) answer to showcase this.










      share|improve this question









      $endgroup$




      Rimworld is a tile-based videogame. One of its constructibles in the wind generator:



      enter image description here



      The wind generator itself occupies a space of 7x2 and can be placed facing the 4 cardinal directions.



      In order for it to work optimally, it is required that it has free (unoccupied) space for 10 tiles in front of it and 6 tiles to its back, for its entire 7 tile width, as shown in the image.



      What is the optimal placement for wind generators, ie most generators per area?



      For an answer I expect a description or even better an image which explains the setup, and a percentage of tiles used by the generators. In order to calculate this percentage, we have to be able to isolate a (hopefully rectangular!) area which can be validly replicated when tiled in the map. I will make a first (obvious and probably suboptimal) answer to showcase this.







      tiling






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 30 at 10:01









      George MenoutisGeorge Menoutis

      1,077212




      1,077212




















          3 Answers
          3






          active

          oldest

          votes


















          3












          $begingroup$

          Here's simple 2-D pattern that seems to tile quite efficiently:




          enter image description here




          The area of the each tile (blue square) is $21times21 = 441$ tiles, and it contains $4times14=56$ generators tiles, for a ratio of $frac56441 approx 12.7%$



          The trick here is that




          it's easy to double the density to $frac112441 approx mathbf25.4%$ by adding a copy of the pattern, staggered so that the required empty spaces (marked in pink in the image above) overlap. This happens nicely as long as the copy is moved 9 to 12 tiles both horizontally and vertically.




          The final pattern looks like this:




          enter image description here




          POST-TICK EDIT: managed to find an even better pattern with $mathbf26.88%$ utility.




          enter image description here

          Green is the back side, the large square's sides are made of two generators each.


          The repeating pattern's (red square) side is $7+2+14+2=25$ tiles long, and it includes $12$ generators, which take up $ frac12 times 1425times25 = mathbf26.88%$ of the total area.







          share|improve this answer











          $endgroup$












          • $begingroup$
            This seems very, very promising!
            $endgroup$
            – George Menoutis
            Mar 30 at 18:07


















          2












          $begingroup$

          I decided to place the wind generators together pinwheel-fashion:




          enter image description here




          The repeated section looks like this:




          enter image description here




          To calculate the efficiency:

          There are $70+70+16+9 = 165$ empty squares, $4cdot14 = 56$ filled squares, for an efficiency of $frac56221 = 25.339%$.



          Sadly this is not quite as efficient as Bass's solution, but ever so close.



          In my first attempt I put them together more tightly, around a 2x2 square, but then the other intermediate square area was 5x5, leading to an efficiency of $24.88%$. In my current one the intermediate squares are 3x3 and 4x4. For maximum efficiency you would want those intermediate squares to all be equal size, but that is impossible on this grid. Bass's solution is the essentially exactly that but with parts shifted to make things grid-aligned.






          share|improve this answer









          $endgroup$




















            1












            $begingroup$

            As mentioned in the question, here is an example of an answer:
            setup2



            This 20x7 tile setup can be validly tile-replicated, as the required open space of the left generator which is "out of bounds" correctly loops to the right to coincide with the open space of the right one:



            setup2x2



            Since we've established validity, the ratio is: 28 generator tiles/140 total tiles=20%






            share|improve this answer









            $endgroup$












            • $begingroup$
              @hexomino based on the answer it sounds like the game field wraps left to right
              $endgroup$
              – Amorydai
              Mar 30 at 13:51










            • $begingroup$
              @Amorydai Ah, okay, thanks. Will delete my comment in that case.
              $endgroup$
              – hexomino
              Mar 30 at 16:20











            Your Answer





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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3












            $begingroup$

            Here's simple 2-D pattern that seems to tile quite efficiently:




            enter image description here




            The area of the each tile (blue square) is $21times21 = 441$ tiles, and it contains $4times14=56$ generators tiles, for a ratio of $frac56441 approx 12.7%$



            The trick here is that




            it's easy to double the density to $frac112441 approx mathbf25.4%$ by adding a copy of the pattern, staggered so that the required empty spaces (marked in pink in the image above) overlap. This happens nicely as long as the copy is moved 9 to 12 tiles both horizontally and vertically.




            The final pattern looks like this:




            enter image description here




            POST-TICK EDIT: managed to find an even better pattern with $mathbf26.88%$ utility.




            enter image description here

            Green is the back side, the large square's sides are made of two generators each.


            The repeating pattern's (red square) side is $7+2+14+2=25$ tiles long, and it includes $12$ generators, which take up $ frac12 times 1425times25 = mathbf26.88%$ of the total area.







            share|improve this answer











            $endgroup$












            • $begingroup$
              This seems very, very promising!
              $endgroup$
              – George Menoutis
              Mar 30 at 18:07















            3












            $begingroup$

            Here's simple 2-D pattern that seems to tile quite efficiently:




            enter image description here




            The area of the each tile (blue square) is $21times21 = 441$ tiles, and it contains $4times14=56$ generators tiles, for a ratio of $frac56441 approx 12.7%$



            The trick here is that




            it's easy to double the density to $frac112441 approx mathbf25.4%$ by adding a copy of the pattern, staggered so that the required empty spaces (marked in pink in the image above) overlap. This happens nicely as long as the copy is moved 9 to 12 tiles both horizontally and vertically.




            The final pattern looks like this:




            enter image description here




            POST-TICK EDIT: managed to find an even better pattern with $mathbf26.88%$ utility.




            enter image description here

            Green is the back side, the large square's sides are made of two generators each.


            The repeating pattern's (red square) side is $7+2+14+2=25$ tiles long, and it includes $12$ generators, which take up $ frac12 times 1425times25 = mathbf26.88%$ of the total area.







            share|improve this answer











            $endgroup$












            • $begingroup$
              This seems very, very promising!
              $endgroup$
              – George Menoutis
              Mar 30 at 18:07













            3












            3








            3





            $begingroup$

            Here's simple 2-D pattern that seems to tile quite efficiently:




            enter image description here




            The area of the each tile (blue square) is $21times21 = 441$ tiles, and it contains $4times14=56$ generators tiles, for a ratio of $frac56441 approx 12.7%$



            The trick here is that




            it's easy to double the density to $frac112441 approx mathbf25.4%$ by adding a copy of the pattern, staggered so that the required empty spaces (marked in pink in the image above) overlap. This happens nicely as long as the copy is moved 9 to 12 tiles both horizontally and vertically.




            The final pattern looks like this:




            enter image description here




            POST-TICK EDIT: managed to find an even better pattern with $mathbf26.88%$ utility.




            enter image description here

            Green is the back side, the large square's sides are made of two generators each.


            The repeating pattern's (red square) side is $7+2+14+2=25$ tiles long, and it includes $12$ generators, which take up $ frac12 times 1425times25 = mathbf26.88%$ of the total area.







            share|improve this answer











            $endgroup$



            Here's simple 2-D pattern that seems to tile quite efficiently:




            enter image description here




            The area of the each tile (blue square) is $21times21 = 441$ tiles, and it contains $4times14=56$ generators tiles, for a ratio of $frac56441 approx 12.7%$



            The trick here is that




            it's easy to double the density to $frac112441 approx mathbf25.4%$ by adding a copy of the pattern, staggered so that the required empty spaces (marked in pink in the image above) overlap. This happens nicely as long as the copy is moved 9 to 12 tiles both horizontally and vertically.




            The final pattern looks like this:




            enter image description here




            POST-TICK EDIT: managed to find an even better pattern with $mathbf26.88%$ utility.




            enter image description here

            Green is the back side, the large square's sides are made of two generators each.


            The repeating pattern's (red square) side is $7+2+14+2=25$ tiles long, and it includes $12$ generators, which take up $ frac12 times 1425times25 = mathbf26.88%$ of the total area.








            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Mar 30 at 20:54

























            answered Mar 30 at 17:53









            BassBass

            31k472188




            31k472188











            • $begingroup$
              This seems very, very promising!
              $endgroup$
              – George Menoutis
              Mar 30 at 18:07
















            • $begingroup$
              This seems very, very promising!
              $endgroup$
              – George Menoutis
              Mar 30 at 18:07















            $begingroup$
            This seems very, very promising!
            $endgroup$
            – George Menoutis
            Mar 30 at 18:07




            $begingroup$
            This seems very, very promising!
            $endgroup$
            – George Menoutis
            Mar 30 at 18:07











            2












            $begingroup$

            I decided to place the wind generators together pinwheel-fashion:




            enter image description here




            The repeated section looks like this:




            enter image description here




            To calculate the efficiency:

            There are $70+70+16+9 = 165$ empty squares, $4cdot14 = 56$ filled squares, for an efficiency of $frac56221 = 25.339%$.



            Sadly this is not quite as efficient as Bass's solution, but ever so close.



            In my first attempt I put them together more tightly, around a 2x2 square, but then the other intermediate square area was 5x5, leading to an efficiency of $24.88%$. In my current one the intermediate squares are 3x3 and 4x4. For maximum efficiency you would want those intermediate squares to all be equal size, but that is impossible on this grid. Bass's solution is the essentially exactly that but with parts shifted to make things grid-aligned.






            share|improve this answer









            $endgroup$

















              2












              $begingroup$

              I decided to place the wind generators together pinwheel-fashion:




              enter image description here




              The repeated section looks like this:




              enter image description here




              To calculate the efficiency:

              There are $70+70+16+9 = 165$ empty squares, $4cdot14 = 56$ filled squares, for an efficiency of $frac56221 = 25.339%$.



              Sadly this is not quite as efficient as Bass's solution, but ever so close.



              In my first attempt I put them together more tightly, around a 2x2 square, but then the other intermediate square area was 5x5, leading to an efficiency of $24.88%$. In my current one the intermediate squares are 3x3 and 4x4. For maximum efficiency you would want those intermediate squares to all be equal size, but that is impossible on this grid. Bass's solution is the essentially exactly that but with parts shifted to make things grid-aligned.






              share|improve this answer









              $endgroup$















                2












                2








                2





                $begingroup$

                I decided to place the wind generators together pinwheel-fashion:




                enter image description here




                The repeated section looks like this:




                enter image description here




                To calculate the efficiency:

                There are $70+70+16+9 = 165$ empty squares, $4cdot14 = 56$ filled squares, for an efficiency of $frac56221 = 25.339%$.



                Sadly this is not quite as efficient as Bass's solution, but ever so close.



                In my first attempt I put them together more tightly, around a 2x2 square, but then the other intermediate square area was 5x5, leading to an efficiency of $24.88%$. In my current one the intermediate squares are 3x3 and 4x4. For maximum efficiency you would want those intermediate squares to all be equal size, but that is impossible on this grid. Bass's solution is the essentially exactly that but with parts shifted to make things grid-aligned.






                share|improve this answer









                $endgroup$



                I decided to place the wind generators together pinwheel-fashion:




                enter image description here




                The repeated section looks like this:




                enter image description here




                To calculate the efficiency:

                There are $70+70+16+9 = 165$ empty squares, $4cdot14 = 56$ filled squares, for an efficiency of $frac56221 = 25.339%$.



                Sadly this is not quite as efficient as Bass's solution, but ever so close.



                In my first attempt I put them together more tightly, around a 2x2 square, but then the other intermediate square area was 5x5, leading to an efficiency of $24.88%$. In my current one the intermediate squares are 3x3 and 4x4. For maximum efficiency you would want those intermediate squares to all be equal size, but that is impossible on this grid. Bass's solution is the essentially exactly that but with parts shifted to make things grid-aligned.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 30 at 19:01









                Jaap ScherphuisJaap Scherphuis

                16.6k12872




                16.6k12872





















                    1












                    $begingroup$

                    As mentioned in the question, here is an example of an answer:
                    setup2



                    This 20x7 tile setup can be validly tile-replicated, as the required open space of the left generator which is "out of bounds" correctly loops to the right to coincide with the open space of the right one:



                    setup2x2



                    Since we've established validity, the ratio is: 28 generator tiles/140 total tiles=20%






                    share|improve this answer









                    $endgroup$












                    • $begingroup$
                      @hexomino based on the answer it sounds like the game field wraps left to right
                      $endgroup$
                      – Amorydai
                      Mar 30 at 13:51










                    • $begingroup$
                      @Amorydai Ah, okay, thanks. Will delete my comment in that case.
                      $endgroup$
                      – hexomino
                      Mar 30 at 16:20















                    1












                    $begingroup$

                    As mentioned in the question, here is an example of an answer:
                    setup2



                    This 20x7 tile setup can be validly tile-replicated, as the required open space of the left generator which is "out of bounds" correctly loops to the right to coincide with the open space of the right one:



                    setup2x2



                    Since we've established validity, the ratio is: 28 generator tiles/140 total tiles=20%






                    share|improve this answer









                    $endgroup$












                    • $begingroup$
                      @hexomino based on the answer it sounds like the game field wraps left to right
                      $endgroup$
                      – Amorydai
                      Mar 30 at 13:51










                    • $begingroup$
                      @Amorydai Ah, okay, thanks. Will delete my comment in that case.
                      $endgroup$
                      – hexomino
                      Mar 30 at 16:20













                    1












                    1








                    1





                    $begingroup$

                    As mentioned in the question, here is an example of an answer:
                    setup2



                    This 20x7 tile setup can be validly tile-replicated, as the required open space of the left generator which is "out of bounds" correctly loops to the right to coincide with the open space of the right one:



                    setup2x2



                    Since we've established validity, the ratio is: 28 generator tiles/140 total tiles=20%






                    share|improve this answer









                    $endgroup$



                    As mentioned in the question, here is an example of an answer:
                    setup2



                    This 20x7 tile setup can be validly tile-replicated, as the required open space of the left generator which is "out of bounds" correctly loops to the right to coincide with the open space of the right one:



                    setup2x2



                    Since we've established validity, the ratio is: 28 generator tiles/140 total tiles=20%







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Mar 30 at 10:09









                    George MenoutisGeorge Menoutis

                    1,077212




                    1,077212











                    • $begingroup$
                      @hexomino based on the answer it sounds like the game field wraps left to right
                      $endgroup$
                      – Amorydai
                      Mar 30 at 13:51










                    • $begingroup$
                      @Amorydai Ah, okay, thanks. Will delete my comment in that case.
                      $endgroup$
                      – hexomino
                      Mar 30 at 16:20
















                    • $begingroup$
                      @hexomino based on the answer it sounds like the game field wraps left to right
                      $endgroup$
                      – Amorydai
                      Mar 30 at 13:51










                    • $begingroup$
                      @Amorydai Ah, okay, thanks. Will delete my comment in that case.
                      $endgroup$
                      – hexomino
                      Mar 30 at 16:20















                    $begingroup$
                    @hexomino based on the answer it sounds like the game field wraps left to right
                    $endgroup$
                    – Amorydai
                    Mar 30 at 13:51




                    $begingroup$
                    @hexomino based on the answer it sounds like the game field wraps left to right
                    $endgroup$
                    – Amorydai
                    Mar 30 at 13:51












                    $begingroup$
                    @Amorydai Ah, okay, thanks. Will delete my comment in that case.
                    $endgroup$
                    – hexomino
                    Mar 30 at 16:20




                    $begingroup$
                    @Amorydai Ah, okay, thanks. Will delete my comment in that case.
                    $endgroup$
                    – hexomino
                    Mar 30 at 16:20

















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