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Complex fractions
The 2019 Stack Overflow Developer Survey Results Are InContinued Fractions as an operator.Why does widehat behave differently if I insert hspace0pt?Shortcuts and/or user-defined shortcuts for math symbols in LaTeX?Underlining fractionsGuidelines for typesetting fractionsUsing mathspec to change digits font in math mode isn't workingLeft aligning equations without align characterAdding a complex maths equation to LatexMathmod: coding complex equationTrouble with complex fractions and parentheses
How to make this more adequate ('beatifuller' :))? 2 needs to be better shown as being in the power of n-1, but the current representation just smothers it.
frac11-sum_2^n frac1fracrR^(2^(n-1))
documentclass[10pt]article
usepackageamssymb
usepackageamsmath
usepackagemathtools
usepackagetextcomp
begindocument
frac11-sum_2^n frac1fracrR^(2^(n-1))
enddocument
math-mode amsmath math-operators mathtools
asked Mar 29 at 10:51
Dmitry StarostinDmitry Starostin
1926
add a comment |
How to make this more adequate ('beatifuller' :))? 2 needs to be better shown as being in the power of n-1, but the current representation just smothers it.
frac11-sum_2^n frac1fracrR^(2^(n-1))
documentclass[10pt]article
usepackageamssymb
usepackageamsmath
usepackagemathtools
usepackagetextcomp
begindocument
frac11-sum_2^n frac1fracrR^(2^(n-1))
enddocument
math-mode amsmath math-operators mathtools
asked Mar 29 at 10:51
Dmitry StarostinDmitry Starostin
1926
add a comment |
How to make this more adequate ('beatifuller' :))? 2 needs to be better shown as being in the power of n-1, but the current representation just smothers it.
frac11-sum_2^n frac1fracrR^(2^(n-1))
documentclass[10pt]article
usepackageamssymb
usepackageamsmath
usepackagemathtools
usepackagetextcomp
begindocument
frac11-sum_2^n frac1fracrR^(2^(n-1))
enddocument
math-mode amsmath math-operators mathtools
asked Mar 29 at 10:51
Dmitry StarostinDmitry Starostin
1926
How to make this more adequate ('beatifuller' :))? 2 needs to be better shown as being in the power of n-1, but the current representation just smothers it.
frac11-sum_2^n frac1fracrR^(2^(n-1))
documentclass[10pt]article
usepackageamssymb
usepackageamsmath
usepackagemathtools
usepackagetextcomp
begindocument
frac11-sum_2^n frac1fracrR^(2^(n-1))
enddocument
math-mode amsmath math-operators mathtools
math-mode amsmath math-operators mathtools
asked Mar 29 at 10:51
Dmitry StarostinDmitry Starostin
1926
asked Mar 29 at 10:51
Dmitry StarostinDmitry Starostin
1926
asked Mar 29 at 10:51
Dmitry StarostinDmitry Starostin
1926
asked Mar 29 at 10:51
Dmitry StarostinDmitry Starostin
1926
asked Mar 29 at 10:51
Dmitry StarostinDmitry Starostin
1926
1926
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
one more variation:
documentclass[10pt]article
usepackagenccmath
begindocument
[
frac11-sumlimits_2^n Bigl(mfracrRBigr)^! -2^n-1
]
enddocument
answered Mar 29 at 11:39
ZarkoZarko
129k868169
add a comment |
If you want to write abc, you need to write a^bc instead of a^bc or a^(bc). I prefer this way
documentclass[10pt]article
usepackageamssymb
usepackageamsmath
usepackagemathtools
usepackagetextcomp
begindocument
[frac11-sum_2^ncfrac1left(fracrRright)^2^n-1]
enddocument
answered Mar 29 at 10:54
JouleVJouleV
12.2k22662
add a comment |
I propose one of these, based on the medium-size commands from nccmath (~ 80% of displaystyle):
documentclass[10pt]article
usepackageamssymb
usepackagemathtools, nccmath
begindocument
[ frac11-medopsum_2^n frac1bigl(mfracrRbigr)^! 2^n-1mathstrut qquad frac11-medopsum_2^n bigl(mfracRrbigr)^!2^n-1]
enddocument
answered Mar 29 at 11:17
BernardBernard
176k778209
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
one more variation:
documentclass[10pt]article
usepackagenccmath
begindocument
[
frac11-sumlimits_2^n Bigl(mfracrRBigr)^! -2^n-1
]
enddocument
answered Mar 29 at 11:39
ZarkoZarko
129k868169
add a comment |
one more variation:
documentclass[10pt]article
usepackagenccmath
begindocument
[
frac11-sumlimits_2^n Bigl(mfracrRBigr)^! -2^n-1
]
enddocument
answered Mar 29 at 11:39
ZarkoZarko
129k868169
add a comment |
one more variation:
documentclass[10pt]article
usepackagenccmath
begindocument
[
frac11-sumlimits_2^n Bigl(mfracrRBigr)^! -2^n-1
]
enddocument
answered Mar 29 at 11:39
ZarkoZarko
129k868169
one more variation:
documentclass[10pt]article
usepackagenccmath
begindocument
[
frac11-sumlimits_2^n Bigl(mfracrRBigr)^! -2^n-1
]
enddocument
answered Mar 29 at 11:39
ZarkoZarko
129k868169
answered Mar 29 at 11:39
ZarkoZarko
129k868169
answered Mar 29 at 11:39
ZarkoZarko
129k868169
answered Mar 29 at 11:39
ZarkoZarko
129k868169
129k868169
add a comment |
add a comment |
If you want to write abc, you need to write a^bc instead of a^bc or a^(bc). I prefer this way
documentclass[10pt]article
usepackageamssymb
usepackageamsmath
usepackagemathtools
usepackagetextcomp
begindocument
[frac11-sum_2^ncfrac1left(fracrRright)^2^n-1]
enddocument
answered Mar 29 at 10:54
JouleVJouleV
12.2k22662
add a comment |
If you want to write abc, you need to write a^bc instead of a^bc or a^(bc). I prefer this way
documentclass[10pt]article
usepackageamssymb
usepackageamsmath
usepackagemathtools
usepackagetextcomp
begindocument
[frac11-sum_2^ncfrac1left(fracrRright)^2^n-1]
enddocument
answered Mar 29 at 10:54
JouleVJouleV
12.2k22662
add a comment |
If you want to write abc, you need to write a^bc instead of a^bc or a^(bc). I prefer this way
documentclass[10pt]article
usepackageamssymb
usepackageamsmath
usepackagemathtools
usepackagetextcomp
begindocument
[frac11-sum_2^ncfrac1left(fracrRright)^2^n-1]
enddocument
answered Mar 29 at 10:54
JouleVJouleV
12.2k22662
If you want to write abc, you need to write a^bc instead of a^bc or a^(bc). I prefer this way
documentclass[10pt]article
usepackageamssymb
usepackageamsmath
usepackagemathtools
usepackagetextcomp
begindocument
[frac11-sum_2^ncfrac1left(fracrRright)^2^n-1]
enddocument
answered Mar 29 at 10:54
JouleVJouleV
12.2k22662
edited Mar 29 at 11:13
answered Mar 29 at 10:54
JouleVJouleV
12.2k22662
answered Mar 29 at 10:54
JouleVJouleV
12.2k22662
answered Mar 29 at 10:54
JouleVJouleV
12.2k22662
12.2k22662
add a comment |
add a comment |
I propose one of these, based on the medium-size commands from nccmath (~ 80% of displaystyle):
documentclass[10pt]article
usepackageamssymb
usepackagemathtools, nccmath
begindocument
[ frac11-medopsum_2^n frac1bigl(mfracrRbigr)^! 2^n-1mathstrut qquad frac11-medopsum_2^n bigl(mfracRrbigr)^!2^n-1]
enddocument
answered Mar 29 at 11:17
BernardBernard
176k778209
add a comment |
I propose one of these, based on the medium-size commands from nccmath (~ 80% of displaystyle):
documentclass[10pt]article
usepackageamssymb
usepackagemathtools, nccmath
begindocument
[ frac11-medopsum_2^n frac1bigl(mfracrRbigr)^! 2^n-1mathstrut qquad frac11-medopsum_2^n bigl(mfracRrbigr)^!2^n-1]
enddocument
answered Mar 29 at 11:17
BernardBernard
176k778209
add a comment |
I propose one of these, based on the medium-size commands from nccmath (~ 80% of displaystyle):
documentclass[10pt]article
usepackageamssymb
usepackagemathtools, nccmath
begindocument
[ frac11-medopsum_2^n frac1bigl(mfracrRbigr)^! 2^n-1mathstrut qquad frac11-medopsum_2^n bigl(mfracRrbigr)^!2^n-1]
enddocument
answered Mar 29 at 11:17
BernardBernard
176k778209
I propose one of these, based on the medium-size commands from nccmath (~ 80% of displaystyle):
documentclass[10pt]article
usepackageamssymb
usepackagemathtools, nccmath
begindocument
[ frac11-medopsum_2^n frac1bigl(mfracrRbigr)^! 2^n-1mathstrut qquad frac11-medopsum_2^n bigl(mfracRrbigr)^!2^n-1]
enddocument
answered Mar 29 at 11:17
BernardBernard
176k778209
edited Mar 29 at 11:33
answered Mar 29 at 11:17
BernardBernard
176k778209
answered Mar 29 at 11:17
BernardBernard
176k778209
answered Mar 29 at 11:17
BernardBernard
176k778209
176k778209
add a comment |
add a comment |
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