Why are stellar absorption line spectra passed through a cold gas? The Next CEO of Stack OverflowWhy do stars have absorption spectra?Galaxy Spectra: Emission and Absorption Linesabsorption and emission lines in Cassiopeia A hydrogen spectrumWould it be possible to detect nuclear explosion on exoplanet?Why has the amount of star formation in the Universe decreased over time?Spectroscopy - Absorption linesPhotometric surveys vs. Spectroscopic surveysVariable speed of light impact on spectral absorption lines in distance luminous objects?Spectroscopy: The trustworthiness of reflected, refracted, and “mixed” light sourcesWhy are there dark lines in an absorption line spectrum from the Sun?
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Why are stellar absorption line spectra passed through a cold gas?
The Next CEO of Stack OverflowWhy do stars have absorption spectra?Galaxy Spectra: Emission and Absorption Linesabsorption and emission lines in Cassiopeia A hydrogen spectrumWould it be possible to detect nuclear explosion on exoplanet?Why has the amount of star formation in the Universe decreased over time?Spectroscopy - Absorption linesPhotometric surveys vs. Spectroscopic surveysVariable speed of light impact on spectral absorption lines in distance luminous objects?Spectroscopy: The trustworthiness of reflected, refracted, and “mixed” light sourcesWhy are there dark lines in an absorption line spectrum from the Sun?
$begingroup$
I am currently studying spectral lines and saw in my notes that the way in which the absorbtion line spectra for a star was measured was by taking its light and shining it through a cold gas. The remaining light would show a black body spectrum with dark lines at the wavelengths which correspond to an exact difference in energy levels between two orbitals for an electron.
My question is, isn't this sort of spectroscopy supposed to identify the elemental composition of the star? It seems to me this would identify what elements were in the cold gas instead.
Note: I am asking whether the measured absorption spectra represents the stars or the cold gas. If it measures the stars, why? Wouldn't changing the gas change the wavelengths at which electrons will make a transition?
astrophysics astronomy spectroscopy
$endgroup$
add a comment |
$begingroup$
I am currently studying spectral lines and saw in my notes that the way in which the absorbtion line spectra for a star was measured was by taking its light and shining it through a cold gas. The remaining light would show a black body spectrum with dark lines at the wavelengths which correspond to an exact difference in energy levels between two orbitals for an electron.
My question is, isn't this sort of spectroscopy supposed to identify the elemental composition of the star? It seems to me this would identify what elements were in the cold gas instead.
Note: I am asking whether the measured absorption spectra represents the stars or the cold gas. If it measures the stars, why? Wouldn't changing the gas change the wavelengths at which electrons will make a transition?
astrophysics astronomy spectroscopy
$endgroup$
add a comment |
$begingroup$
I am currently studying spectral lines and saw in my notes that the way in which the absorbtion line spectra for a star was measured was by taking its light and shining it through a cold gas. The remaining light would show a black body spectrum with dark lines at the wavelengths which correspond to an exact difference in energy levels between two orbitals for an electron.
My question is, isn't this sort of spectroscopy supposed to identify the elemental composition of the star? It seems to me this would identify what elements were in the cold gas instead.
Note: I am asking whether the measured absorption spectra represents the stars or the cold gas. If it measures the stars, why? Wouldn't changing the gas change the wavelengths at which electrons will make a transition?
astrophysics astronomy spectroscopy
$endgroup$
I am currently studying spectral lines and saw in my notes that the way in which the absorbtion line spectra for a star was measured was by taking its light and shining it through a cold gas. The remaining light would show a black body spectrum with dark lines at the wavelengths which correspond to an exact difference in energy levels between two orbitals for an electron.
My question is, isn't this sort of spectroscopy supposed to identify the elemental composition of the star? It seems to me this would identify what elements were in the cold gas instead.
Note: I am asking whether the measured absorption spectra represents the stars or the cold gas. If it measures the stars, why? Wouldn't changing the gas change the wavelengths at which electrons will make a transition?
astrophysics astronomy spectroscopy
astrophysics astronomy spectroscopy
edited Mar 26 at 8:21
Johnny
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1031
asked Mar 24 at 10:28
Vishal JainVishal Jain
1119
1119
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3 Answers
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$begingroup$
The idea of shining light from a (hot) source through a cold gas is a very basic model of what a stellar atmosphere is like.
The radiation field emitted from hotter interior layers has to pass through cooler outer layers before it gets to us. This is how absorption lines become imprinted on what otherwise would be a featureless continuum. In other words, the star's radiation is self-absorbed by its outer, cooler layers.
A good way to look at this is that the photons we receive come from the layer at which the optical depth (at that wavelength) is approximately unity. i.e. We see down into the atmosphere as far as a mean free path for a photon of that wavelength.
Because the solar interior gets hotter as we go inwards and the radiation field approximates to a Planck blackbody function, then if the mean free path is long at a particular wavelength we see deeper, hotter and therefore brighter. On the other hand, if the mean free path is short (for example because there is a radiative transition of some type of atom at that wavelength and that element exists in the atmosphere), then our view will be to shallower depths and cooler temperatures, meaning less intense light.
The mean free path will be proportional to the number density of that particular type of atom and thus by measuring the strength of absorption lines we get not just the indication of the presence of a particular species of atom, but also its number density (a.k.a. its abundance).
$endgroup$
add a comment |
$begingroup$
One has not to make confusion between the way we can create an absorption spectrum in laboratory (making radiation with a continuum spectrum passing through a cold gas) and the way absorption spectra are formed in the photosphere of a star or by absorption by planet atmospheres or interstellar gases. In the astrophysical case, spectroscopists have only to collect the light coming from far sources.
No need to use a further absorbing layer which could not say anything about composition of far objects. Absorption lines in solar spectrum were observed for the first time by Fraunhofer mid-19th century. Basic starting information about absorption spectroscopy can be found in this wikipedia page.
$endgroup$
add a comment |
$begingroup$
I am currently studying spectral lines and saw in my notes that the way in which the absorbtion line spectra for a star was measured was by taking its light and shining it through a cold gas.
The absorption spectrum of a star is generated when light coming from within the photosphere passes through the "cold" outer atmosphere of the star (where "cold" in this context merely means that the vast majority of the atoms are in the ground state, which can be quite hot indeed by human standards). To get the absorption spectrum of the star, we simply directly measure the light coming towards us.
$endgroup$
add a comment |
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3 Answers
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active
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3 Answers
3
active
oldest
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active
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active
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votes
$begingroup$
The idea of shining light from a (hot) source through a cold gas is a very basic model of what a stellar atmosphere is like.
The radiation field emitted from hotter interior layers has to pass through cooler outer layers before it gets to us. This is how absorption lines become imprinted on what otherwise would be a featureless continuum. In other words, the star's radiation is self-absorbed by its outer, cooler layers.
A good way to look at this is that the photons we receive come from the layer at which the optical depth (at that wavelength) is approximately unity. i.e. We see down into the atmosphere as far as a mean free path for a photon of that wavelength.
Because the solar interior gets hotter as we go inwards and the radiation field approximates to a Planck blackbody function, then if the mean free path is long at a particular wavelength we see deeper, hotter and therefore brighter. On the other hand, if the mean free path is short (for example because there is a radiative transition of some type of atom at that wavelength and that element exists in the atmosphere), then our view will be to shallower depths and cooler temperatures, meaning less intense light.
The mean free path will be proportional to the number density of that particular type of atom and thus by measuring the strength of absorption lines we get not just the indication of the presence of a particular species of atom, but also its number density (a.k.a. its abundance).
$endgroup$
add a comment |
$begingroup$
The idea of shining light from a (hot) source through a cold gas is a very basic model of what a stellar atmosphere is like.
The radiation field emitted from hotter interior layers has to pass through cooler outer layers before it gets to us. This is how absorption lines become imprinted on what otherwise would be a featureless continuum. In other words, the star's radiation is self-absorbed by its outer, cooler layers.
A good way to look at this is that the photons we receive come from the layer at which the optical depth (at that wavelength) is approximately unity. i.e. We see down into the atmosphere as far as a mean free path for a photon of that wavelength.
Because the solar interior gets hotter as we go inwards and the radiation field approximates to a Planck blackbody function, then if the mean free path is long at a particular wavelength we see deeper, hotter and therefore brighter. On the other hand, if the mean free path is short (for example because there is a radiative transition of some type of atom at that wavelength and that element exists in the atmosphere), then our view will be to shallower depths and cooler temperatures, meaning less intense light.
The mean free path will be proportional to the number density of that particular type of atom and thus by measuring the strength of absorption lines we get not just the indication of the presence of a particular species of atom, but also its number density (a.k.a. its abundance).
$endgroup$
add a comment |
$begingroup$
The idea of shining light from a (hot) source through a cold gas is a very basic model of what a stellar atmosphere is like.
The radiation field emitted from hotter interior layers has to pass through cooler outer layers before it gets to us. This is how absorption lines become imprinted on what otherwise would be a featureless continuum. In other words, the star's radiation is self-absorbed by its outer, cooler layers.
A good way to look at this is that the photons we receive come from the layer at which the optical depth (at that wavelength) is approximately unity. i.e. We see down into the atmosphere as far as a mean free path for a photon of that wavelength.
Because the solar interior gets hotter as we go inwards and the radiation field approximates to a Planck blackbody function, then if the mean free path is long at a particular wavelength we see deeper, hotter and therefore brighter. On the other hand, if the mean free path is short (for example because there is a radiative transition of some type of atom at that wavelength and that element exists in the atmosphere), then our view will be to shallower depths and cooler temperatures, meaning less intense light.
The mean free path will be proportional to the number density of that particular type of atom and thus by measuring the strength of absorption lines we get not just the indication of the presence of a particular species of atom, but also its number density (a.k.a. its abundance).
$endgroup$
The idea of shining light from a (hot) source through a cold gas is a very basic model of what a stellar atmosphere is like.
The radiation field emitted from hotter interior layers has to pass through cooler outer layers before it gets to us. This is how absorption lines become imprinted on what otherwise would be a featureless continuum. In other words, the star's radiation is self-absorbed by its outer, cooler layers.
A good way to look at this is that the photons we receive come from the layer at which the optical depth (at that wavelength) is approximately unity. i.e. We see down into the atmosphere as far as a mean free path for a photon of that wavelength.
Because the solar interior gets hotter as we go inwards and the radiation field approximates to a Planck blackbody function, then if the mean free path is long at a particular wavelength we see deeper, hotter and therefore brighter. On the other hand, if the mean free path is short (for example because there is a radiative transition of some type of atom at that wavelength and that element exists in the atmosphere), then our view will be to shallower depths and cooler temperatures, meaning less intense light.
The mean free path will be proportional to the number density of that particular type of atom and thus by measuring the strength of absorption lines we get not just the indication of the presence of a particular species of atom, but also its number density (a.k.a. its abundance).
answered Mar 24 at 12:27
Rob JeffriesRob Jeffries
70.2k7142243
70.2k7142243
add a comment |
add a comment |
$begingroup$
One has not to make confusion between the way we can create an absorption spectrum in laboratory (making radiation with a continuum spectrum passing through a cold gas) and the way absorption spectra are formed in the photosphere of a star or by absorption by planet atmospheres or interstellar gases. In the astrophysical case, spectroscopists have only to collect the light coming from far sources.
No need to use a further absorbing layer which could not say anything about composition of far objects. Absorption lines in solar spectrum were observed for the first time by Fraunhofer mid-19th century. Basic starting information about absorption spectroscopy can be found in this wikipedia page.
$endgroup$
add a comment |
$begingroup$
One has not to make confusion between the way we can create an absorption spectrum in laboratory (making radiation with a continuum spectrum passing through a cold gas) and the way absorption spectra are formed in the photosphere of a star or by absorption by planet atmospheres or interstellar gases. In the astrophysical case, spectroscopists have only to collect the light coming from far sources.
No need to use a further absorbing layer which could not say anything about composition of far objects. Absorption lines in solar spectrum were observed for the first time by Fraunhofer mid-19th century. Basic starting information about absorption spectroscopy can be found in this wikipedia page.
$endgroup$
add a comment |
$begingroup$
One has not to make confusion between the way we can create an absorption spectrum in laboratory (making radiation with a continuum spectrum passing through a cold gas) and the way absorption spectra are formed in the photosphere of a star or by absorption by planet atmospheres or interstellar gases. In the astrophysical case, spectroscopists have only to collect the light coming from far sources.
No need to use a further absorbing layer which could not say anything about composition of far objects. Absorption lines in solar spectrum were observed for the first time by Fraunhofer mid-19th century. Basic starting information about absorption spectroscopy can be found in this wikipedia page.
$endgroup$
One has not to make confusion between the way we can create an absorption spectrum in laboratory (making radiation with a continuum spectrum passing through a cold gas) and the way absorption spectra are formed in the photosphere of a star or by absorption by planet atmospheres or interstellar gases. In the astrophysical case, spectroscopists have only to collect the light coming from far sources.
No need to use a further absorbing layer which could not say anything about composition of far objects. Absorption lines in solar spectrum were observed for the first time by Fraunhofer mid-19th century. Basic starting information about absorption spectroscopy can be found in this wikipedia page.
answered Mar 24 at 12:43
GiorgioPGiorgioP
4,2501628
4,2501628
add a comment |
add a comment |
$begingroup$
I am currently studying spectral lines and saw in my notes that the way in which the absorbtion line spectra for a star was measured was by taking its light and shining it through a cold gas.
The absorption spectrum of a star is generated when light coming from within the photosphere passes through the "cold" outer atmosphere of the star (where "cold" in this context merely means that the vast majority of the atoms are in the ground state, which can be quite hot indeed by human standards). To get the absorption spectrum of the star, we simply directly measure the light coming towards us.
$endgroup$
add a comment |
$begingroup$
I am currently studying spectral lines and saw in my notes that the way in which the absorbtion line spectra for a star was measured was by taking its light and shining it through a cold gas.
The absorption spectrum of a star is generated when light coming from within the photosphere passes through the "cold" outer atmosphere of the star (where "cold" in this context merely means that the vast majority of the atoms are in the ground state, which can be quite hot indeed by human standards). To get the absorption spectrum of the star, we simply directly measure the light coming towards us.
$endgroup$
add a comment |
$begingroup$
I am currently studying spectral lines and saw in my notes that the way in which the absorbtion line spectra for a star was measured was by taking its light and shining it through a cold gas.
The absorption spectrum of a star is generated when light coming from within the photosphere passes through the "cold" outer atmosphere of the star (where "cold" in this context merely means that the vast majority of the atoms are in the ground state, which can be quite hot indeed by human standards). To get the absorption spectrum of the star, we simply directly measure the light coming towards us.
$endgroup$
I am currently studying spectral lines and saw in my notes that the way in which the absorbtion line spectra for a star was measured was by taking its light and shining it through a cold gas.
The absorption spectrum of a star is generated when light coming from within the photosphere passes through the "cold" outer atmosphere of the star (where "cold" in this context merely means that the vast majority of the atoms are in the ground state, which can be quite hot indeed by human standards). To get the absorption spectrum of the star, we simply directly measure the light coming towards us.
edited Mar 24 at 16:26
answered Mar 24 at 15:00
probably_someoneprobably_someone
18.6k12960
18.6k12960
add a comment |
add a comment |
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