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Difference between -| and |- in TikZ
The Next CEO of Stack OverflowInsertion of perpendicular symbol at intersection of two perpendicular linesTikZ: What EXACTLY does the the |- notation for arrows do?How to Mark Right Angle in TikzHow to add perpendicular symbol at desired locationHow to fix TikZ corners in 3DTweaking behaviour of tikz trees for Feynman diagramsTikZ: how to find the intersection of two extended lines?Right Angle Symbol Alignment with TikZ/CalcWhat's the difference between path and draw in Tikz?A display indicating the definition of the distance between a point and a line (using only TikZ)How filling angle symbol?TikZ: bad line caps at the intersectionsSmoothing out angles made up of different line widthsTikZ calculate in/out-angle from nodes
Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -| and |-.
tikz-pgf
add a comment |
Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -| and |-.
tikz-pgf
1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
add a comment |
Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -| and |-.
tikz-pgf
Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -| and |-.
tikz-pgf
tikz-pgf
asked Mar 24 at 12:16
subham sonisubham soni
4,81483187
4,81483187
1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
add a comment |
1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
1
1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
add a comment |
3 Answers
3
active
oldest
votes
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) -| (y);
endtikzpicture
enddocument
Mathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) |- (y);
endtikzpicture
enddocument
Mathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
add a comment |
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument

2
You're welcome! I edited my answer to put x and y within$...$.
– CarLaTeX
Mar 25 at 5:56
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) -| (y);
endtikzpicture
enddocument
Mathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) |- (y);
endtikzpicture
enddocument
Mathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
add a comment |
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) -| (y);
endtikzpicture
enddocument
Mathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) |- (y);
endtikzpicture
enddocument
Mathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
add a comment |
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) -| (y);
endtikzpicture
enddocument
Mathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) |- (y);
endtikzpicture
enddocument
Mathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) -| (y);
endtikzpicture
enddocument
Mathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) |- (y);
endtikzpicture
enddocument
Mathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
edited Mar 25 at 10:27
answered Mar 24 at 13:55
JouleVJouleV
9,11222256
9,11222256
add a comment |
add a comment |
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument

2
You're welcome! I edited my answer to put x and y within$...$.
– CarLaTeX
Mar 25 at 5:56
add a comment |
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument

2
You're welcome! I edited my answer to put x and y within$...$.
– CarLaTeX
Mar 25 at 5:56
add a comment |
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument

I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument

edited Mar 25 at 5:54
answered Mar 24 at 18:14
CarLaTeXCarLaTeX
34.3k552141
34.3k552141
2
You're welcome! I edited my answer to put x and y within$...$.
– CarLaTeX
Mar 25 at 5:56
add a comment |
2
You're welcome! I edited my answer to put x and y within$...$.
– CarLaTeX
Mar 25 at 5:56
2
2
You're welcome! I edited my answer to put x and y within
$...$.– CarLaTeX
Mar 25 at 5:56
You're welcome! I edited my answer to put x and y within
$...$.– CarLaTeX
Mar 25 at 5:56
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
answered Mar 24 at 18:31
Artificial Hairless ArmpitArtificial Hairless Armpit
5,02711142
5,02711142
add a comment |
add a comment |
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1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33