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Order table by two columns
Sequential joining of tables in orderGroup by + Order by Behavior Explanation?Best way to rank all the columns in a table and store those ranks in another tableSet in mySQL a predefined order for SELECT queries without using the ORDER BY clauseHow do I control order/arrangement of certain columns in a resultset?Transposing hierachical data from one VARCHAR to two INTsHow can I speed up an ASC sort on a column that only holds an integer between 0 and 9 across multiple millions of rows?Mysql: slow down with order by, global database problemORDER BY doesn't use an index on SQL Server if CASE WHEN is presentHow to identify columns order in a table, bis
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I would like to order this table but I can not find a way to make it work. Can you help me?
I have this table:
I need this:
I have a table where documents are listed, the first field is the id of the document and the second field represents the father, so I must show a list where you can see in an orderly manner that 242 is the first document and 252 and 335 were generated from the 242.
The query:
select * from table_name order by col1 ASC, Col2 ASC
...doesn't work for me. I do this query:
SELECT
FR1.[report_id],
FR1.[report_parent]
FROM [FARA_reports] FR1
WHERE
FR1.[report_is_delete] <> 1
AND FR1.[report_is_tmp] <> 1
ORDER BY
FR1.[report_id] asc,
FR1.[report_parent] desc
and this is my first image.
sql-server sql-server-2008 order-by
add a comment |
I would like to order this table but I can not find a way to make it work. Can you help me?
I have this table:
I need this:
I have a table where documents are listed, the first field is the id of the document and the second field represents the father, so I must show a list where you can see in an orderly manner that 242 is the first document and 252 and 335 were generated from the 242.
The query:
select * from table_name order by col1 ASC, Col2 ASC
...doesn't work for me. I do this query:
SELECT
FR1.[report_id],
FR1.[report_parent]
FROM [FARA_reports] FR1
WHERE
FR1.[report_is_delete] <> 1
AND FR1.[report_is_tmp] <> 1
ORDER BY
FR1.[report_id] asc,
FR1.[report_parent] desc
and this is my first image.
sql-server sql-server-2008 order-by
add a comment |
I would like to order this table but I can not find a way to make it work. Can you help me?
I have this table:
I need this:
I have a table where documents are listed, the first field is the id of the document and the second field represents the father, so I must show a list where you can see in an orderly manner that 242 is the first document and 252 and 335 were generated from the 242.
The query:
select * from table_name order by col1 ASC, Col2 ASC
...doesn't work for me. I do this query:
SELECT
FR1.[report_id],
FR1.[report_parent]
FROM [FARA_reports] FR1
WHERE
FR1.[report_is_delete] <> 1
AND FR1.[report_is_tmp] <> 1
ORDER BY
FR1.[report_id] asc,
FR1.[report_parent] desc
and this is my first image.
sql-server sql-server-2008 order-by
I would like to order this table but I can not find a way to make it work. Can you help me?
I have this table:
I need this:
I have a table where documents are listed, the first field is the id of the document and the second field represents the father, so I must show a list where you can see in an orderly manner that 242 is the first document and 252 and 335 were generated from the 242.
The query:
select * from table_name order by col1 ASC, Col2 ASC
...doesn't work for me. I do this query:
SELECT
FR1.[report_id],
FR1.[report_parent]
FROM [FARA_reports] FR1
WHERE
FR1.[report_is_delete] <> 1
AND FR1.[report_is_tmp] <> 1
ORDER BY
FR1.[report_id] asc,
FR1.[report_parent] desc
and this is my first image.
sql-server sql-server-2008 order-by
sql-server sql-server-2008 order-by
edited Apr 10 at 5:19
Paul White♦
54.5k14290461
54.5k14290461
asked Apr 9 at 22:57
Liliana del Carmen CastellanosLiliana del Carmen Castellanos
182
182
add a comment |
add a comment |
5 Answers
5
active
oldest
votes
Another option:
select a, b
from t
order by
case when a < b or b is null then a else b end,
case when a < b or b is null then b else a end ;
Test in dbfiddle.uk.
Can't you just order byisnull(id2, id1), id2
?
– bendataclear
Apr 10 at 12:22
1
@bendtaclear yes. When I wrote the answer, it wasn't clear that first column can never be null.
– ypercubeᵀᴹ
Apr 10 at 13:55
These really work for me :D
– Liliana del Carmen Castellanos
Apr 10 at 15:07
add a comment |
Your data:
CREATE TABLE dbo.WEIRD_ORDERING
(
ID1 INT NULL,
ID2 INT NULL
);
INSERT INTO dbo.WEIRD_ORDERING VALUES
(242, NULL),
(243, NULL),
(244, NULL),
(252, 242),
(254, NULL),
(255, NULL),
(256, NULL),
(292, NULL),
(308, NULL),
(311, NULL),
(313, 311),
(314, 311),
(323, NULL),
(324, 311),
(335, 242),
(340, NULL),
(341, NULL),
(358, NULL),
(372, NULL),
(373, NULL),
(377, NULL),
(378, 358),
(379, 358),
(380, 358),
(381, 358);
This gives you results in the desired order:
SELECT ID1, ID2
FROM
(
SELECT ID1, ID2, ID1 AS ORDERING_COLUMN
FROM dbo.WEIRD_ORDERING
WHERE ID1 <= ID2 OR ID2 IS NULL
UNION ALL
SELECT ID1, ID2, ID2 AS ORDERING_COLUMN
FROM dbo.WEIRD_ORDERING
WHERE ID1 > ID2 OR ID1 IS NULL
) q
ORDER BY ORDERING_COLUMN;
db fiddle
Thank you so much. You are AWESOME!! :D
– Liliana del Carmen Castellanos
Apr 10 at 15:01
This doesn't quite work, if you reorder your input data from(313, 311), (314, 311)
to(314, 311),(313, 311)
it comes out in the wrong order, I suggest updating the order by statement to beORDER BY ORDERING_COLUMN, ID1
to fix that
– Xynos
Apr 10 at 15:01
@Xynos feel free to edit
– Joe Obbish
Apr 10 at 19:52
add a comment |
Stealing the sql fiddle table from Joe Obbish this is a simple solution
SELECT * FROM dbo.WEIRD_ORDERING
ORDER BY coalesce(ID2*1000+1, ID1*1000)
add a comment |
SELECT *
FROM datatable
ORDER BY CASE WHEN field2 IS NULL THEN field1 ELSE field2 END, -- sort groups
CASE WHEN field2 IS NULL THEN 1 ELSE 2 END, -- move parent first
field2 -- sort childs
add a comment |
All answers so far rely on an assumption that there are no further levels of "generated from" (e.g. there is no 382 generated from the 381 which is itself generated from 352 - or which was it).
They should know what is said of "assume", so they should have asked you about this first.
If you can indeed have further levels of "generated from", then you need a recursive query to do the full path construction ("352" , "352/381" , "352/381/382" , etc etc) and ORDER BY that full path.
add a comment |
Your Answer
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
Another option:
select a, b
from t
order by
case when a < b or b is null then a else b end,
case when a < b or b is null then b else a end ;
Test in dbfiddle.uk.
Can't you just order byisnull(id2, id1), id2
?
– bendataclear
Apr 10 at 12:22
1
@bendtaclear yes. When I wrote the answer, it wasn't clear that first column can never be null.
– ypercubeᵀᴹ
Apr 10 at 13:55
These really work for me :D
– Liliana del Carmen Castellanos
Apr 10 at 15:07
add a comment |
Another option:
select a, b
from t
order by
case when a < b or b is null then a else b end,
case when a < b or b is null then b else a end ;
Test in dbfiddle.uk.
Can't you just order byisnull(id2, id1), id2
?
– bendataclear
Apr 10 at 12:22
1
@bendtaclear yes. When I wrote the answer, it wasn't clear that first column can never be null.
– ypercubeᵀᴹ
Apr 10 at 13:55
These really work for me :D
– Liliana del Carmen Castellanos
Apr 10 at 15:07
add a comment |
Another option:
select a, b
from t
order by
case when a < b or b is null then a else b end,
case when a < b or b is null then b else a end ;
Test in dbfiddle.uk.
Another option:
select a, b
from t
order by
case when a < b or b is null then a else b end,
case when a < b or b is null then b else a end ;
Test in dbfiddle.uk.
answered Apr 10 at 6:47
ypercubeᵀᴹypercubeᵀᴹ
78.8k11137223
78.8k11137223
Can't you just order byisnull(id2, id1), id2
?
– bendataclear
Apr 10 at 12:22
1
@bendtaclear yes. When I wrote the answer, it wasn't clear that first column can never be null.
– ypercubeᵀᴹ
Apr 10 at 13:55
These really work for me :D
– Liliana del Carmen Castellanos
Apr 10 at 15:07
add a comment |
Can't you just order byisnull(id2, id1), id2
?
– bendataclear
Apr 10 at 12:22
1
@bendtaclear yes. When I wrote the answer, it wasn't clear that first column can never be null.
– ypercubeᵀᴹ
Apr 10 at 13:55
These really work for me :D
– Liliana del Carmen Castellanos
Apr 10 at 15:07
Can't you just order by
isnull(id2, id1), id2
?– bendataclear
Apr 10 at 12:22
Can't you just order by
isnull(id2, id1), id2
?– bendataclear
Apr 10 at 12:22
1
1
@bendtaclear yes. When I wrote the answer, it wasn't clear that first column can never be null.
– ypercubeᵀᴹ
Apr 10 at 13:55
@bendtaclear yes. When I wrote the answer, it wasn't clear that first column can never be null.
– ypercubeᵀᴹ
Apr 10 at 13:55
These really work for me :D
– Liliana del Carmen Castellanos
Apr 10 at 15:07
These really work for me :D
– Liliana del Carmen Castellanos
Apr 10 at 15:07
add a comment |
Your data:
CREATE TABLE dbo.WEIRD_ORDERING
(
ID1 INT NULL,
ID2 INT NULL
);
INSERT INTO dbo.WEIRD_ORDERING VALUES
(242, NULL),
(243, NULL),
(244, NULL),
(252, 242),
(254, NULL),
(255, NULL),
(256, NULL),
(292, NULL),
(308, NULL),
(311, NULL),
(313, 311),
(314, 311),
(323, NULL),
(324, 311),
(335, 242),
(340, NULL),
(341, NULL),
(358, NULL),
(372, NULL),
(373, NULL),
(377, NULL),
(378, 358),
(379, 358),
(380, 358),
(381, 358);
This gives you results in the desired order:
SELECT ID1, ID2
FROM
(
SELECT ID1, ID2, ID1 AS ORDERING_COLUMN
FROM dbo.WEIRD_ORDERING
WHERE ID1 <= ID2 OR ID2 IS NULL
UNION ALL
SELECT ID1, ID2, ID2 AS ORDERING_COLUMN
FROM dbo.WEIRD_ORDERING
WHERE ID1 > ID2 OR ID1 IS NULL
) q
ORDER BY ORDERING_COLUMN;
db fiddle
Thank you so much. You are AWESOME!! :D
– Liliana del Carmen Castellanos
Apr 10 at 15:01
This doesn't quite work, if you reorder your input data from(313, 311), (314, 311)
to(314, 311),(313, 311)
it comes out in the wrong order, I suggest updating the order by statement to beORDER BY ORDERING_COLUMN, ID1
to fix that
– Xynos
Apr 10 at 15:01
@Xynos feel free to edit
– Joe Obbish
Apr 10 at 19:52
add a comment |
Your data:
CREATE TABLE dbo.WEIRD_ORDERING
(
ID1 INT NULL,
ID2 INT NULL
);
INSERT INTO dbo.WEIRD_ORDERING VALUES
(242, NULL),
(243, NULL),
(244, NULL),
(252, 242),
(254, NULL),
(255, NULL),
(256, NULL),
(292, NULL),
(308, NULL),
(311, NULL),
(313, 311),
(314, 311),
(323, NULL),
(324, 311),
(335, 242),
(340, NULL),
(341, NULL),
(358, NULL),
(372, NULL),
(373, NULL),
(377, NULL),
(378, 358),
(379, 358),
(380, 358),
(381, 358);
This gives you results in the desired order:
SELECT ID1, ID2
FROM
(
SELECT ID1, ID2, ID1 AS ORDERING_COLUMN
FROM dbo.WEIRD_ORDERING
WHERE ID1 <= ID2 OR ID2 IS NULL
UNION ALL
SELECT ID1, ID2, ID2 AS ORDERING_COLUMN
FROM dbo.WEIRD_ORDERING
WHERE ID1 > ID2 OR ID1 IS NULL
) q
ORDER BY ORDERING_COLUMN;
db fiddle
Thank you so much. You are AWESOME!! :D
– Liliana del Carmen Castellanos
Apr 10 at 15:01
This doesn't quite work, if you reorder your input data from(313, 311), (314, 311)
to(314, 311),(313, 311)
it comes out in the wrong order, I suggest updating the order by statement to beORDER BY ORDERING_COLUMN, ID1
to fix that
– Xynos
Apr 10 at 15:01
@Xynos feel free to edit
– Joe Obbish
Apr 10 at 19:52
add a comment |
Your data:
CREATE TABLE dbo.WEIRD_ORDERING
(
ID1 INT NULL,
ID2 INT NULL
);
INSERT INTO dbo.WEIRD_ORDERING VALUES
(242, NULL),
(243, NULL),
(244, NULL),
(252, 242),
(254, NULL),
(255, NULL),
(256, NULL),
(292, NULL),
(308, NULL),
(311, NULL),
(313, 311),
(314, 311),
(323, NULL),
(324, 311),
(335, 242),
(340, NULL),
(341, NULL),
(358, NULL),
(372, NULL),
(373, NULL),
(377, NULL),
(378, 358),
(379, 358),
(380, 358),
(381, 358);
This gives you results in the desired order:
SELECT ID1, ID2
FROM
(
SELECT ID1, ID2, ID1 AS ORDERING_COLUMN
FROM dbo.WEIRD_ORDERING
WHERE ID1 <= ID2 OR ID2 IS NULL
UNION ALL
SELECT ID1, ID2, ID2 AS ORDERING_COLUMN
FROM dbo.WEIRD_ORDERING
WHERE ID1 > ID2 OR ID1 IS NULL
) q
ORDER BY ORDERING_COLUMN;
db fiddle
Your data:
CREATE TABLE dbo.WEIRD_ORDERING
(
ID1 INT NULL,
ID2 INT NULL
);
INSERT INTO dbo.WEIRD_ORDERING VALUES
(242, NULL),
(243, NULL),
(244, NULL),
(252, 242),
(254, NULL),
(255, NULL),
(256, NULL),
(292, NULL),
(308, NULL),
(311, NULL),
(313, 311),
(314, 311),
(323, NULL),
(324, 311),
(335, 242),
(340, NULL),
(341, NULL),
(358, NULL),
(372, NULL),
(373, NULL),
(377, NULL),
(378, 358),
(379, 358),
(380, 358),
(381, 358);
This gives you results in the desired order:
SELECT ID1, ID2
FROM
(
SELECT ID1, ID2, ID1 AS ORDERING_COLUMN
FROM dbo.WEIRD_ORDERING
WHERE ID1 <= ID2 OR ID2 IS NULL
UNION ALL
SELECT ID1, ID2, ID2 AS ORDERING_COLUMN
FROM dbo.WEIRD_ORDERING
WHERE ID1 > ID2 OR ID1 IS NULL
) q
ORDER BY ORDERING_COLUMN;
db fiddle
answered Apr 10 at 0:08
Joe ObbishJoe Obbish
22.6k43495
22.6k43495
Thank you so much. You are AWESOME!! :D
– Liliana del Carmen Castellanos
Apr 10 at 15:01
This doesn't quite work, if you reorder your input data from(313, 311), (314, 311)
to(314, 311),(313, 311)
it comes out in the wrong order, I suggest updating the order by statement to beORDER BY ORDERING_COLUMN, ID1
to fix that
– Xynos
Apr 10 at 15:01
@Xynos feel free to edit
– Joe Obbish
Apr 10 at 19:52
add a comment |
Thank you so much. You are AWESOME!! :D
– Liliana del Carmen Castellanos
Apr 10 at 15:01
This doesn't quite work, if you reorder your input data from(313, 311), (314, 311)
to(314, 311),(313, 311)
it comes out in the wrong order, I suggest updating the order by statement to beORDER BY ORDERING_COLUMN, ID1
to fix that
– Xynos
Apr 10 at 15:01
@Xynos feel free to edit
– Joe Obbish
Apr 10 at 19:52
Thank you so much. You are AWESOME!! :D
– Liliana del Carmen Castellanos
Apr 10 at 15:01
Thank you so much. You are AWESOME!! :D
– Liliana del Carmen Castellanos
Apr 10 at 15:01
This doesn't quite work, if you reorder your input data from
(313, 311), (314, 311)
to (314, 311),(313, 311)
it comes out in the wrong order, I suggest updating the order by statement to be ORDER BY ORDERING_COLUMN, ID1
to fix that– Xynos
Apr 10 at 15:01
This doesn't quite work, if you reorder your input data from
(313, 311), (314, 311)
to (314, 311),(313, 311)
it comes out in the wrong order, I suggest updating the order by statement to be ORDER BY ORDERING_COLUMN, ID1
to fix that– Xynos
Apr 10 at 15:01
@Xynos feel free to edit
– Joe Obbish
Apr 10 at 19:52
@Xynos feel free to edit
– Joe Obbish
Apr 10 at 19:52
add a comment |
Stealing the sql fiddle table from Joe Obbish this is a simple solution
SELECT * FROM dbo.WEIRD_ORDERING
ORDER BY coalesce(ID2*1000+1, ID1*1000)
add a comment |
Stealing the sql fiddle table from Joe Obbish this is a simple solution
SELECT * FROM dbo.WEIRD_ORDERING
ORDER BY coalesce(ID2*1000+1, ID1*1000)
add a comment |
Stealing the sql fiddle table from Joe Obbish this is a simple solution
SELECT * FROM dbo.WEIRD_ORDERING
ORDER BY coalesce(ID2*1000+1, ID1*1000)
Stealing the sql fiddle table from Joe Obbish this is a simple solution
SELECT * FROM dbo.WEIRD_ORDERING
ORDER BY coalesce(ID2*1000+1, ID1*1000)
answered Apr 10 at 7:34
SpacebenSpaceben
311
311
add a comment |
add a comment |
SELECT *
FROM datatable
ORDER BY CASE WHEN field2 IS NULL THEN field1 ELSE field2 END, -- sort groups
CASE WHEN field2 IS NULL THEN 1 ELSE 2 END, -- move parent first
field2 -- sort childs
add a comment |
SELECT *
FROM datatable
ORDER BY CASE WHEN field2 IS NULL THEN field1 ELSE field2 END, -- sort groups
CASE WHEN field2 IS NULL THEN 1 ELSE 2 END, -- move parent first
field2 -- sort childs
add a comment |
SELECT *
FROM datatable
ORDER BY CASE WHEN field2 IS NULL THEN field1 ELSE field2 END, -- sort groups
CASE WHEN field2 IS NULL THEN 1 ELSE 2 END, -- move parent first
field2 -- sort childs
SELECT *
FROM datatable
ORDER BY CASE WHEN field2 IS NULL THEN field1 ELSE field2 END, -- sort groups
CASE WHEN field2 IS NULL THEN 1 ELSE 2 END, -- move parent first
field2 -- sort childs
answered Apr 10 at 4:53
AkinaAkina
5,1611411
5,1611411
add a comment |
add a comment |
All answers so far rely on an assumption that there are no further levels of "generated from" (e.g. there is no 382 generated from the 381 which is itself generated from 352 - or which was it).
They should know what is said of "assume", so they should have asked you about this first.
If you can indeed have further levels of "generated from", then you need a recursive query to do the full path construction ("352" , "352/381" , "352/381/382" , etc etc) and ORDER BY that full path.
add a comment |
All answers so far rely on an assumption that there are no further levels of "generated from" (e.g. there is no 382 generated from the 381 which is itself generated from 352 - or which was it).
They should know what is said of "assume", so they should have asked you about this first.
If you can indeed have further levels of "generated from", then you need a recursive query to do the full path construction ("352" , "352/381" , "352/381/382" , etc etc) and ORDER BY that full path.
add a comment |
All answers so far rely on an assumption that there are no further levels of "generated from" (e.g. there is no 382 generated from the 381 which is itself generated from 352 - or which was it).
They should know what is said of "assume", so they should have asked you about this first.
If you can indeed have further levels of "generated from", then you need a recursive query to do the full path construction ("352" , "352/381" , "352/381/382" , etc etc) and ORDER BY that full path.
All answers so far rely on an assumption that there are no further levels of "generated from" (e.g. there is no 382 generated from the 381 which is itself generated from 352 - or which was it).
They should know what is said of "assume", so they should have asked you about this first.
If you can indeed have further levels of "generated from", then you need a recursive query to do the full path construction ("352" , "352/381" , "352/381/382" , etc etc) and ORDER BY that full path.
answered Apr 10 at 11:45
Erwin SmoutErwin Smout
1,421812
1,421812
add a comment |
add a comment |
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