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Can I connect a DC high voltage booster directly to my Raspberry Pi? [closed]

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1

$begingroup$

I have one of these modules:

Is it safe to connect it to two pins to my Raspberry Pi, directly, and turn it on by emitting HIGH on one of the pins (the other one being the ground), which is around 5V, if I am not wrong?

Will that use too much power from the Raspberry Pi or maybe burn it?

dc raspberry-pi high-voltage

share|improve this question

edited Apr 10 at 14:49

feetwet

1,15941839

asked Apr 10 at 4:56

Ionică BizăuIonică Bizău

17718

$endgroup$

closed as unclear what you're asking by Chris Stratton, laptop2d, Finbarr, Brian Carlton, RoyC Apr 14 at 13:43

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  Without engineering data (no a link to a sales page dies not qualify) this is off topic here. But it sounds like a terrible technical idea, probably in pursuit of a misguided or improper goal.
  $endgroup$
  – Chris Stratton
  Apr 10 at 7:09
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  There's nothing to be gained in casting aspersions on the OP's motives. Whatever these modules are, they're apparently cheap and plentiful on ebay, so plenty of people will likely be playing with them for all sorts of reasons. Best if they know how to do that without killing their Raspberry Pi's. :)
  $endgroup$
  – aroth
  Apr 10 at 12:46
  

  
  
  
  

add a comment | 

1

$begingroup$

I have one of these modules:

Is it safe to connect it to two pins to my Raspberry Pi, directly, and turn it on by emitting HIGH on one of the pins (the other one being the ground), which is around 5V, if I am not wrong?

Will that use too much power from the Raspberry Pi or maybe burn it?

dc raspberry-pi high-voltage

share|improve this question

edited Apr 10 at 14:49

feetwet

1,15941839

asked Apr 10 at 4:56

Ionică BizăuIonică Bizău

17718

$endgroup$

closed as unclear what you're asking by Chris Stratton, laptop2d, Finbarr, Brian Carlton, RoyC Apr 14 at 13:43

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  Without engineering data (no a link to a sales page dies not qualify) this is off topic here. But it sounds like a terrible technical idea, probably in pursuit of a misguided or improper goal.
  $endgroup$
  – Chris Stratton
  Apr 10 at 7:09
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  There's nothing to be gained in casting aspersions on the OP's motives. Whatever these modules are, they're apparently cheap and plentiful on ebay, so plenty of people will likely be playing with them for all sorts of reasons. Best if they know how to do that without killing their Raspberry Pi's. :)
  $endgroup$
  – aroth
  Apr 10 at 12:46
  

  
  
  
  

add a comment | 

$begingroup$

I have one of these modules:

Is it safe to connect it to two pins to my Raspberry Pi, directly, and turn it on by emitting HIGH on one of the pins (the other one being the ground), which is around 5V, if I am not wrong?

Will that use too much power from the Raspberry Pi or maybe burn it?

dc raspberry-pi high-voltage

share|improve this question

edited Apr 10 at 14:49

feetwet

1,15941839

asked Apr 10 at 4:56

Ionică BizăuIonică Bizău

17718

$endgroup$

share|improve this question

edited Apr 10 at 14:49

feetwet

1,15941839

asked Apr 10 at 4:56

Ionică BizăuIonică Bizău

17718

share|improve this question

edited Apr 10 at 14:49

feetwet

1,15941839

asked Apr 10 at 4:56

Ionică BizăuIonică Bizău

17718

edited Apr 10 at 14:49

feetwet

1,15941839

edited Apr 10 at 14:49

feetwet

1,15941839

asked Apr 10 at 4:56

Ionică BizăuIonică Bizău

17718

asked Apr 10 at 4:56

Ionică BizăuIonică Bizău

17718

3 Answers
3

active

oldest

votes

8

$begingroup$

The advert says it needs 5 Amperes. That’s hundreds of times more than a Raspberry Pi GPIO can supply.

You would need a driver, preferably with isolation, and a separate power supply capable of at least 5A. One solution would be a CPC709J, with a suitable series resistor for the LED.

You may well cause disruption or damage even with that, but the chances are better. You’re essentially putting a multi-watt spark-gap transmitter in close proximity to an unshielded microcomputer.

share|improve this answer

edited Apr 10 at 5:47

answered Apr 10 at 5:42

Spehro PefhanySpehro Pefhany

216k5165440

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thanks! I think using a relay would be a solution too, right?
  $endgroup$
  – Ionică Bizău
  Apr 10 at 8:36
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Absolutely, but you also then need to build a relay driver, and relays don’t give perfect isolation either.
  $endgroup$
  – Spehro Pefhany
  Apr 10 at 10:35
  

  
  
  
  

add a comment | 

5

$begingroup$

Apart from not having enough energy to drive that circuit:

Generating sparks near a piece of electronics is never a good idea.

Although the circuit has protection on some of the I/O ports, especially the HDMI and USB interfaces, there is non on the GPIO pins. Those have the standard ESD protection which is designed for, well... ESD. It is NOT designed to handle the energy which comes from huge voltage sparks.

share|improve this answer

answered Apr 10 at 5:06

OldfartOldfart

9,0462927

$endgroup$

add a comment | 

5

$begingroup$

The micro-lightning arc HV noise generator needs 1 or Li-Ion cells to power it. If should never be operated near any computer.

If it operates near an R-Pi, it will cause functional failure and possible damage to signal ports on cables acting as an antenna.

share|improve this answer

answered Apr 10 at 7:10

Sunnyskyguy EE75Sunnyskyguy EE75

72.7k228103

$endgroup$

add a comment | 

8

$begingroup$

The advert says it needs 5 Amperes. That’s hundreds of times more than a Raspberry Pi GPIO can supply.

You would need a driver, preferably with isolation, and a separate power supply capable of at least 5A. One solution would be a CPC709J, with a suitable series resistor for the LED.

You may well cause disruption or damage even with that, but the chances are better. You’re essentially putting a multi-watt spark-gap transmitter in close proximity to an unshielded microcomputer.

share|improve this answer

edited Apr 10 at 5:47

answered Apr 10 at 5:42

Spehro PefhanySpehro Pefhany

216k5165440

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thanks! I think using a relay would be a solution too, right?
  $endgroup$
  – Ionică Bizău
  Apr 10 at 8:36
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Absolutely, but you also then need to build a relay driver, and relays don’t give perfect isolation either.
  $endgroup$
  – Spehro Pefhany
  Apr 10 at 10:35
  

  
  
  
  

add a comment | 

8

$begingroup$

The advert says it needs 5 Amperes. That’s hundreds of times more than a Raspberry Pi GPIO can supply.

You would need a driver, preferably with isolation, and a separate power supply capable of at least 5A. One solution would be a CPC709J, with a suitable series resistor for the LED.

You may well cause disruption or damage even with that, but the chances are better. You’re essentially putting a multi-watt spark-gap transmitter in close proximity to an unshielded microcomputer.

share|improve this answer

edited Apr 10 at 5:47

answered Apr 10 at 5:42

Spehro PefhanySpehro Pefhany

216k5165440

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thanks! I think using a relay would be a solution too, right?
  $endgroup$
  – Ionică Bizău
  Apr 10 at 8:36
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Absolutely, but you also then need to build a relay driver, and relays don’t give perfect isolation either.
  $endgroup$
  – Spehro Pefhany
  Apr 10 at 10:35
  

  
  
  
  

add a comment | 

$begingroup$

The advert says it needs 5 Amperes. That’s hundreds of times more than a Raspberry Pi GPIO can supply.

You would need a driver, preferably with isolation, and a separate power supply capable of at least 5A. One solution would be a CPC709J, with a suitable series resistor for the LED.

You may well cause disruption or damage even with that, but the chances are better. You’re essentially putting a multi-watt spark-gap transmitter in close proximity to an unshielded microcomputer.

share|improve this answer

edited Apr 10 at 5:47

answered Apr 10 at 5:42

Spehro PefhanySpehro Pefhany

216k5165440

$endgroup$

share|improve this answer

edited Apr 10 at 5:47

answered Apr 10 at 5:42

Spehro PefhanySpehro Pefhany

216k5165440

answered Apr 10 at 5:42

Spehro PefhanySpehro Pefhany

216k5165440

answered Apr 10 at 5:42

Spehro PefhanySpehro Pefhany

216k5165440

5

$begingroup$

Apart from not having enough energy to drive that circuit:

Generating sparks near a piece of electronics is never a good idea.

Although the circuit has protection on some of the I/O ports, especially the HDMI and USB interfaces, there is non on the GPIO pins. Those have the standard ESD protection which is designed for, well... ESD. It is NOT designed to handle the energy which comes from huge voltage sparks.

share|improve this answer

answered Apr 10 at 5:06

OldfartOldfart

9,0462927

$endgroup$

add a comment | 

5

$begingroup$

Apart from not having enough energy to drive that circuit:

Generating sparks near a piece of electronics is never a good idea.

Although the circuit has protection on some of the I/O ports, especially the HDMI and USB interfaces, there is non on the GPIO pins. Those have the standard ESD protection which is designed for, well... ESD. It is NOT designed to handle the energy which comes from huge voltage sparks.

share|improve this answer

answered Apr 10 at 5:06

OldfartOldfart

9,0462927

$endgroup$

add a comment | 

$begingroup$

Apart from not having enough energy to drive that circuit:

Generating sparks near a piece of electronics is never a good idea.

Although the circuit has protection on some of the I/O ports, especially the HDMI and USB interfaces, there is non on the GPIO pins. Those have the standard ESD protection which is designed for, well... ESD. It is NOT designed to handle the energy which comes from huge voltage sparks.

share|improve this answer

answered Apr 10 at 5:06

OldfartOldfart

9,0462927

$endgroup$

share|improve this answer

answered Apr 10 at 5:06

OldfartOldfart

9,0462927

answered Apr 10 at 5:06

OldfartOldfart

9,0462927

answered Apr 10 at 5:06

OldfartOldfart

9,0462927

5

$begingroup$

The micro-lightning arc HV noise generator needs 1 or Li-Ion cells to power it. If should never be operated near any computer.

If it operates near an R-Pi, it will cause functional failure and possible damage to signal ports on cables acting as an antenna.

share|improve this answer

answered Apr 10 at 7:10

Sunnyskyguy EE75Sunnyskyguy EE75

72.7k228103

$endgroup$

add a comment | 

5

$begingroup$

The micro-lightning arc HV noise generator needs 1 or Li-Ion cells to power it. If should never be operated near any computer.

If it operates near an R-Pi, it will cause functional failure and possible damage to signal ports on cables acting as an antenna.

share|improve this answer

answered Apr 10 at 7:10

Sunnyskyguy EE75Sunnyskyguy EE75

72.7k228103

$endgroup$

add a comment | 

$begingroup$

The micro-lightning arc HV noise generator needs 1 or Li-Ion cells to power it. If should never be operated near any computer.

If it operates near an R-Pi, it will cause functional failure and possible damage to signal ports on cables acting as an antenna.

share|improve this answer

answered Apr 10 at 7:10

Sunnyskyguy EE75Sunnyskyguy EE75

72.7k228103

$endgroup$

share|improve this answer

answered Apr 10 at 7:10

Sunnyskyguy EE75Sunnyskyguy EE75

72.7k228103

answered Apr 10 at 7:10

Sunnyskyguy EE75Sunnyskyguy EE75

72.7k228103

answered Apr 10 at 7:10

Sunnyskyguy EE75Sunnyskyguy EE75

72.7k228103